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I need to be able to place the captcha image into a picturebox on my form, the reason being that I need to zoom the captcha image for the visualy impaired users.
It appears to be such a simple task, just take the image from the web page and put it into a picturebox but it is turning out to be not so simple.
i have WebBrowser control in form and for registration in one of site, i need captcha image in picture box. problem is that captcha image is generated by JavaScript, when java script runs then it gives url of captcha image. but every time when java script runs, captcha image goes change. i just want that captcha image which is on WebBrowser control current page.
Any help would be greatly appreciated.
yogesh
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No you cant create pictures using Javascript. You need to generate the picture in the serverside using Bitmap object.
This might help you
CAPTCHA Image[^] 
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i dont want to create captcha using javascript. i just told that captcha link comes when javascript runs.
yogesh
modified on Saturday, October 24, 2009 1:49 PM
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you need to change the size of the image ?
why dont you use javascript to do this??
set <img style="width:100px; height:100px" /> using javascript when user wants to zoom the image.
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i think, you have not read my message carefully. ok i am explaining again,
if you are going to create account in facebook.com, captcha will come there. if you see the page source then you can not get any specifice captcha url, you only get one link, and this links calls java script. whenever java script runs captcha url comes to webpage.
yogesh
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Hey ultimately it goes to a handler right. So calling the handler again will create a new image.
If javascript calles the handler then it should create an img tag. In your case, if you have an HTTPhandler you can easily write the captcha image in the output stream and through javascript create an img tag and place the image.
Now place a button to enlarge the existing image using
var img = document.getElementById('yourimgkey');
img.style.width = '100px';
img.style.height = '100px';
That will do the trick I think. why do you require to request to the server again. I know its an issue when you are hitting the server side again, the captcha image will change.
If still have problems, Please drop some code that you have done for your website so that I could get more about the actual problem you are facing. 
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here is my code.
public void FacebookRegistration()
{
HTMLDoc = (mshtml.HTMLDocument)WBrowser.Document.DomDocument;
iHTMLCol = HTMLDoc.getElementsByTagName("input");
foreach (IHTMLElement iHTMLEle in iHTMLCol)
{
if (iHTMLEle.getAttribute("name", 0) != null)
{
strAttriName = iHTMLEle.getAttribute("name", 0).ToString();
if (strAttriName == "firstname")
{
iHTMLEle.setAttribute("value", FirstName, 0);
continue;
}
if (strAttriName == "lastname")
{
iHTMLEle.setAttribute("value", LastName, 0);
continue;
}
if (strAttriName == "reg_email__")
{
iHTMLEle.setAttribute("value", EmailID, 0);
continue;
}
if (strAttriName == "reg_passwd__")
{
string s = GetRandomString();
Random ran = new Random();
iHTMLEle.setAttribute("value", s+ran.Next(1111,9999), 0);
break;
}
}
}
iHTMLCol = HTMLDoc.getElementsByTagName("option");
foreach (IHTMLElement iHTMLEle in iHTMLCol)
{
try
{
if (iHTMLEle.innerText.Contains("Male"))
{
iHTMLEle.setAttribute("selected", "selected",0);
} if (iHTMLEle.innerText.Contains("Jun"))
{
iHTMLEle.setAttribute("selected", "selected", 0);
}
Random ran = new Random();
if (iHTMLEle.innerText.Contains("4"))
{
iHTMLEle.setAttribute("selected", "selected", 0);
}
Random ran1 = new Random();
if (iHTMLEle.innerText.Contains(ran1.Next(1920,1985).ToString()))
{
iHTMLEle.setAttribute("selected", "selected", 0);
}
}
catch { }
}
iHTMLCol = HTMLDoc.getElementsByTagName("input");
int i = 0;
foreach (IHTMLElement iHTMLEle in iHTMLCol)
{
string s = iHTMLEle.className;
if (iHTMLEle.className == "UIButton_Text" && iHTMLEle.getAttribute("value", 0).ToString() == "Sign Up")
{
if (i != 0)
{
iHTMLEle.click();
break;
}
i++;
}
}
private void WBrowser_DocumentCompleted(object sender, WebBrowserDocumentCompletedEventArgs e)
{
if (CurrentSocial == "facebook")
{
FacebookRegistration();
}
}
in the registration page of facebook.com, there is captcha and if you go to page source then you will see only this:
yogesh
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Basically, the idea is that they are trying to stop exactly what you're trying to do, and seem to be doing so successfully.
Christian Graus
Driven to the arms of OSX by Vista.
Read my blog to find out how I've worked around bugs in Microsoft tools and frameworks.
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So you are making a windows application which will load the Facebook application to its web browser control. First of all, you need to remember, if you are going to call the server again, it will load the CAPTCHA again. This is the basic feature of CAPTCHA. Rather if your motive is to zoom the image, you need to find the img control which loads the captcha and then apply CSS width and height.
Just try to find the actual img control that loads the captcha. I am sure that must be one.
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yogesh_softworld123 wrote: I need to zoom the captcha image for the visualy impaired users.
Why not go for the audio facility? Wouldn't that be better?
It's not necessary to be so stupid, either, but people manage it. - Christian Graus, 2009 AD
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I have a datagridview with for columns. the datagridview is dinamically added. the 4th column is needed for an cellClick event so I have to have it. But I do not want to display it so I set the Visible property for that column to false. and it does not show. Cool right? Except in the process of making this column not visible the header text for all the columns dis appear;
I could set the with of the DataGrid to chop off the last column so its still there but no one can see it. and this is probably what im going to do but was wondering if anyone had this problem or a resolution to this.
Mike
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ok Never mind. The headerText was not showing because I did not set the foreColor in the column that was not to be visible.
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Then, please mark your question as [solved]. if it is!
♫ 99 little bugs in the code,
99 bugs in the code
We fix a bug, compile it again
101 little bugs in the code ♫
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hi friends, I tried to send Image through a network .... I can send text data...it is easy one .... but when I try to convert the Image in to byte.
This is the code that converts String to bye
String message;
Byte[] data = System.Text.Encoding.ASCII.GetBytes(message);
This is the code that converts byte to string
String responseData = String.Empty;
Int32 bytes = stream.Read(data, 0, data.Length);
responseData = System.Text.Encoding.ASCII.GetString(data, 0, bytes);
But I cant find any method that converts image to byte .... can any body help me?
Thank you for your time.
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Hello,
I want to make a tabpage invisible, but not disposing or hiding 'cause I want to re-open it later. Any idea's? I tried this:
tabControl1.SelectedTab.Hide();
But this code still shows the header 
plz help me!
Madmatt.
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The onyl way to make the tab invisible is to remove it from the TabPages collection. You can keep a reference to it in a storage location and readd it to the collection when you need to make it visible again.
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Looking for an easy way or infact any way to pop event for unmanaged code via csharp com interop wrapper.....
Any one knows a good site for c# COM technologies? I have a serious trouble with this issue....
modified on Saturday, October 24, 2009 4:40 PM
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hi there,
i have an application that i want to send raw packets through dial up,
i have a lan that i can send packets to easily, but it does not work for dial up
i know the ways such as WinPcap, SharpPcap(managed code working with WinPcap), NDIS Driver API, that allows to send and capture packets but they only can send raw packets to lan! not to my dial up connection! any one knows how to do that?
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Message Closed
modified 23-Nov-14 7:30am.
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i don't think that we can communicate with 56-Kbps Dial up Modem using cat3 twisted pair(telephone line ) with SerialPort! , by the way thanks
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Message Closed
modified 23-Nov-14 7:30am.
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but when i am connected at the internet through dialup, i can not bind to its com port, and open the port to send and recieve.
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driving license (class)
+number: string (constructor)
+renewelperiod: int (constructor)
+ GetLicenseInfo():void (mrthod)
+ CalculateLicensePrice(): double (method)
+ DisplayLicenseInfo() : void (method)
Based on the above, create a program with the following requirement
• GetLicenseInfo() method that input license number and renewal period from user. Display an information to the user either to renew the license for 1,2,3 or 5 years.
• CalculateLicensePrice() method that will calculate price for driving license depends on the renewal period of 1,2,3 or 5 years. The renewal fee is RM30 per year
• A method DisplayLicenseInfo() that will display each details including license number,renewal period and license price.
Create an object and invoke necessary method
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why?
Did you tried it?
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