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As we used to tell our users "Working as coded". AfxMessageBox is a wrapper for the Win32 MessageBox() function, whose job is to provide a simple dialog with a message and a couple of buttons. The box will resize itself to a certain extent based on the message to display, but its purpose is merely to display the information, and not to provide parameterisation: that function is provide by Dialog boxes q.v.
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No, except indirectly by inserting LF ('\n') characters.
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Didn't get it, will this make the box wider or taller?
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You can't make the message box wider. It will chose a size based on how big the display is and other internal constraints. The LF characters will help you keep the box skinnier and taller. (It may be different on Vista and 7, but XP and before sometimes makes message boxes so wide that they are hard to read and look silly.)
As someone else pointed out; if you need to control the size very specifically, write a dialog box.
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Hi All
I am making an application to play the video file using c++ builder. I am using directshow to play the any video file. I am Rendering the video on to the panel control. I want the first frame of this video and draw on to the another panel control. For getting the first frame I paused the video as start so that i got the first frame of the video but how i draw this frame to another panel pls help me
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Hi All
How can i store MySql DESCRIBE table command in CString?I am useing
_ConnectionPtr m_pConn,RecordsetPtr pRecordset
pRecordset=m_pConn->Execute(_bstr_t(dec), 0, adCmdText);
_variant_t talble = pRecordset->GetRows(adGetRowsRest);
How can i store like that
CString Filed=Name;
CString Type=Varchar(20);
....
Plz help me
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Hi Folks
Getpixel and setpixel methods are too slow ..what it is the alternative solution for that ...method ..and plz give me one samples
Thanks
~~~~~~~~~~~~~Raju~~~~~~~~~~~~~
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rajugis wrote: Getpixel and setpixel methods are too slow
Too slow for what? Please explain what you are trying to achieve.
rajugis wrote: and plz give me one samples
We have no idea what you are trying to achieve, nor what you have tried. Be specific about which part of your program does not work.
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I have one image file ..which contains the buildings i want to cut top of left corner building ..
before that i have read image in pixel - by - pixel so that its very slow ..
~~~~~~~~~~~~~Raju~~~~~~~~~~~~~
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What is the criteria to cut/crop the image?
Seems to be a hassle to look for pixels details to do that ?
This signature was proudly tested on animals.
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just check the below links, i think you are looking for these things
CImage with Performance[^]
and one more, more info about cropping and cutting CxImage[^]
Величие не Бога может быть недооценена.
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Hmm guys,is it possible to display number1+ number2+number3?
Eg,if a program prompts a user to input 3 numbers,N1,N2 and N3,is it possible for the program to display N1+N2+N3?As far as i know,we can use a while loop to straight away give us the final answer for N1+N2+N3.
To make it clear,if i input 5 as N1,10 as N2 and 15 as N3,can we make the program display
"total=5+10+15=30" instead of "total=30"?
Can someone guide me on this. xD
modified on Friday, September 11, 2009 10:31 AM
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UKM_Student wrote: Im currently writing a program which prompts the computer to calculate the sum of even integers between 2 numbers,namely Number_1 and Number_2.Anyone can help me with this?
Yes, lots of people but they may want to be paid for the effort. This is your program so you must at least try and make a start on it. Have you read this[^], especially point 2?
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Ok this is what i have tried so far since 2.5 hours ago...and failed >.<
#include<iostream>
using namespace std;
int main()
{
cout<<"c. The total sum of even integers between "<<firstNum<<" and "<<secondNum<<" is : ";
int total=0;
if(firstNum%2==0)
do
{
total=total+firstNum+2;
cout<<total;
firstNum=firstNum+2;
}while(firstNum<secondNum);
PS i chose the if(firstNum%2==0) to show that if the 1st value is an even number,that loop is to be executed.For The part where the first integer is an odd number,i should be able to write that program after you guys can help me solve the even number part 
modified on Friday, September 11, 2009 8:08 AM
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And what is your doubt?
(while statement knowledge should be enough for the task).
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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the doubt is i can't seem to execute the program >.<
Eg,if i put number1 as 2 and number2 as 10,instead of showing the value of 18,ie.(4+6+8),it shows 4101828
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Your (revised) code
#include <iostream>
using namespace std;
int main()
{
int firstNum = 2, secondNum = 10;
int k;
int total = 0;
k = firstNum + 1;
if (k % 2 == 1) k++;
while (k < secondNum)
{
total = total + k;
k += 2;
}
cout << "c. The total sum of even integers between " << firstNum << " and " << secondNum << " is : " << total;
}
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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Erm thanks but do u mind explaining the part where u said
if (k % 2 == 1) k++;???
And i thought that "if statement" needs to be paired with an "else"?
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UKM_Student wrote: if (k % 2 == 1) k++;???
if k is odd (an odd number modulus 2 gives 1) then increment k (i.e. k=k+1) to make it even.
(Just in case firstNum is odd).
UKM_Student wrote: And i thought that "if statement" needs to be paired with an "else"?
Actually the else clause is optional in the if statement, see, for instance, here.
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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Erm it says that "If the value of expression is nonzero, statement1 is executed. If the optional else is present, statement2 is executed if the value of expression is zero."
So what happens if the value of expression is zero and the optional else is NOT present?Will the compiler even able to compile it?Or will the compiler able to compile it but instead execute the If statement?Or nothing happens at all?
Oh and thanks for your help.
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And i got another question if u are free to help >.<
I nid to display number 1-10 and their squares.I managed to display the 1-10 part but couldn't display their squares >.<.The output should be smth like this
1 1
2 4
3 9
4 16
5 25
6 36
7 49
8 64
9 81
10 100
This is what i got so far xD
cout<<"d. Display the numbers 1-10 and their squares."<<endl;
int integer=1;
while(integer<=10)
{
cout<<integer<<endl;
integer++;
}
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Well, you know, squaring a number means multiplying it by itself... 
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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