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thanx alot superman,
i increase its size and its working fine now......it is what we say a great answer.... 
Thanks A Ton
Ash_VCPP
walking over water is just knowing where the stones are.....
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You should consider using the safe string functions like _tcscpy_s and other C runtime functions that end with _s. Or you must use safe string APIs like StringCchCopy.
«_Superman_»
I love work. It gives me something to do between weekends.
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Keep in mind that you may have simply masked the problem rather than actually solved it. Find the code that writes to that variable to make sure it is indeed big enough.
"Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
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I suspect you've forgotten to add "+1" for the null terminator - looking at your code, it looks like you've added the maximum sizes of constituent strings, but not the '0' at the end.
I would suggest you think about using a string class (std::string or CString) rather than char arrays wherever possible - that way you don't need to worry about managing memory like this.
Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p
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here it is the C code , it prints the base filename
I want to modify it to print the following
/work1/data/xxxx/yyy/
const char * path = "/work1/data/xxxx/yyy/file_name.txt";
const char * filename; filename = path+strlen(path);
while (filename != path && *(filename) != '/')
filename--;
if ( filename != path)
filename++;
cout << filename;
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it didn't work
I need to print the path without the baseile name
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this logic worked for me perfectly.
const char * path = "/work1/data/xxxx/yyy/file_name.txt";
char path1[256];
strcpy(path1,path);
cout << path <<"\n";
int l=strlen(path);
for(int i=l;i>0;i--)
{
if(path1[i]=='/')
{
path1[i]='\0';
break;
}
}
cout << path1<<"\n";
the output is as you desired.
--------------------------------------------
Suggestion to the members:
Please prefix your main thread subject with [SOLVED] if it is solved.
thanks.
chandu.
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sorry,
it didn't work
why?
look at the way you are using strcpy() function
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ksaw123 wrote: look at the way you are using strcpy() function
whats the problem?
--------------------------------------------
Suggestion to the members:
Please prefix your main thread subject with [SOLVED] if it is solved.
thanks.
chandu.
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You don't need to parse. Use SHString apis.
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it is C/C++ program not vasuil C++
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Use PathRemoveFileSpec() or _splitpath().
"Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
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Which .h file those functions is in?
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See here.
"Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
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my boss
I don't want to use Microsoft C++ , I am using the lagacy C/C++
actually , my code is working but i wanna print the path without the file name as your suggested function.
Thanks
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You might want to consider strrchr() to find the last backslash. Put a '\0' character there.
"Old age is like a bank account. You withdraw later in life what you have deposited along the way." - Unknown
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
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And what is the question?
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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How can I print the path without the base filename
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The code you posted does it.
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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the code i posted prints the base file name not the path
I want to print the path without file name
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you're right:
const char * path ="/work1/data/xxxx/yyy/file_name.txt";
char * basename;
char * filename;
basename = _strdup(path);
if ( !basename){}
filename = basename+strlen(basename);
while (filename != basename && *(filename) != '/')
filename--;
if ( filename != basename)
{
*(filename+1)='\0';
}
else
*basename='\0';
printf("%s\n", basename);
free(basename);
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke
[My articles]
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Hi
I have a class like:
class CMyclass1
{
public
CMyclass2 myclass;
.....
}
class CMyclass2
{
public
TCHAR Var[SOMEVALUE];
.....
}
CMyclass2 ::CMyclass2
{
memset(Var, '\0',sizeof(Var));
strcpy_s(Var,"some value");
}
----------- When I did following, program crashed ---
CMyclass1 * pclass = new CMyclass1()
delete pclass;
How can fix this problem?
Best regards,
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