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fine then.
could u not find the bounding rectangle of your town.
to find it, just draw a virtual rectangle around ur town in GE (ggl erth)
take the longi and lati of the top left corner of the rect and bottom right corner of the rect.
parallelly, experiment drawing a rectangle(0,0,700,700) on your screen and lines 0,0 to 100,100 to 100,150 to 150,200. if you are stuck up, let me know i shall help u.
gpsmercato wrote: my deadline is on july second week.
far more than sufficient.
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 well ...ya it took long time..actually i went for friday prayer in between......
ok so rectangle with the lines done.
in GE the values are 25d17m28.90sc & 55d18m31.07sec
25d11m32.57sec & 55d24m17.68sec
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can you convert these into integers for me please.
make it quick.
25d17m28.90sc & 55d18m31.07sec
25d11m32.57sec & 55d24m17.68sec
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thanks.
chandu.
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9104890 and 19911100.7
9069257 and 19945768
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plz verify them that .7 is not supposed to come.
and also write a function which will convert ge format to int(pix) format.
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thanks.
chandu.
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sorry the value is 19911107.
function to convert ge format? u mean radian to degree format?
if so then ok. done
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no man,
some function like
int ConvertGratitoPix(int d,int m,int s,int sf)
{
return d*60*60*100+m*60*100+s*100+sf;
}
here graticule in general means latitude and/or longitude.
pix refers to an integer.
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thanks.
chandu.
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so, your towns bounds are as follows.
top-9104890 and left-19911107
bottom-9069257 and right-19945768
now, the width of your town is
19945768-19911107=34661
and height is
9069257-9104890 =-35633
temporarily we will ignore the - sign for height. theresult would be reversed display of the map. we will correct at the end.
finally,
width=34661
and
height=35633
did you understand till here.
if so i shall proceed further otherwise ask ur doubt.
be quick.
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thanks.
chandu.
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good.
now
width=34661
and
height=35633
it is evident that, if we draw the abovepattern, it will be a rectangle, not a square.for our convinience we want to make it a square.
so out of width and height, which is more?
obviously height.
so we will subtract
height-width=35633-34661
=972.
means width is 972 units less than height.
so if we adjust 972/2 units to the left and 972/2 units to the right of our original rectangle, then it would become a square.
now, i want you to explain those caluculations for me.
do it fast.
--------------------------------------------
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thanks.
chandu.
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what happened are you there?
make a habbit of acknowleding my post after you read it.
later you can edit it with your comments.
i should atleast know weather u r on this job or some thing else?
--------------------------------------------
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thanks.
chandu.
modified on Friday, June 19, 2009 7:51 AM
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ok so wht i understand is the scaling of image inorder to fit it as square.. in programming it is mapping..
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perfect
so can you caluculate the left,top,right and bottom of your town in terms of pix data such that it will be a square?
be fast.
ive got to leave for the day.
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thanks.
chandu.
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yes i can..ok if its the time for u to leave thn we will continue the class on monday.. thankyou verymuch
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19910639,9104890
19946236,9069257
this would be your town bounds.
--------------------------------------------
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thanks.
chandu.
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now, what is themaximum size of a square that you can draw on your screen?
that will be your drawing area of the map.
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thanks.
chandu.
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any size ..ok let it b (2.5,2.5,0)
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what is this 2.5,2.5,0
explain in detail
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thanks.
chandu.
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bye for today.
try to map the bounds of the town to the bounds of the rectangle on your screen.
then take the digital data that is set of longitudes and latitudes from ge for some of the roads,
i mean take a sample at each road turning,
put them sequentially in a file,
convert them into pix data,
scale them to the square on your screen,
plot lines from one point to other.
now u will see the map that u have extracted from ge.
now you should be able to plot the value you have received from ur usb gps device.
all the best
bye.
--------------------------------------------
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thanks.
chandu.
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bye i will b back on monday only..thanku
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