C / C++ / MFC

char *a,*b;
char *temp, *dest;
dest=new char[5];
temp = dest;
a="aa";
b="bb";
while(*a!='\0')
{
  *temp++ =*a++ ;
}
while(*b!='\0')
{
  *temp++= *b++ ;
}
*temp = '\0';
printf("%s",dest); 

himangshuS wrote:

I wont be knowing the no of characters after contcatination(ie the size of the temp) in advance.

int strlen(const char* s)
{
   int count;
   while (*(s++))
      ++count;
}

Divyang Mithaiwala wrote:

Because if you have taken temp as array (char temp[XX]) then you might get error

Divyang Mithaiwala wrote:

But a code that we are sawing has no that kind of error.

You need to google first, if you have "It's urgent please" mentioned in your question.
_AnShUmAn_