Re: Retrieving multiple items from listview [modified] - C# Discussion Boards

mrithula86-Apr-09 5:28

6-Apr-09 5:28

Hi I have a TableLayoutPanel and i have added label controls to the each cell of its 1st column.Also i have used a listview control to display the list of all files from a directory.For a design purpose, i want the name of the file to be displayed in the 1st label in the 1st cell of the table when i select any file name from the listview control.Similarly when the 2nd item from listview is selected it should appear in the 2nd label.

Currently i have a design which has a mapping like when i select on the 1st filename it appears in the 1st label,2nd file name in the 2nd label...the drawback that i face here is that suppose if by random i select 5th filename from listview it appears on the 5th label.

I hope im making myself clear.Please help me with this

mrithula87-Apr-09 18:35

7-Apr-09 18:35

Hi I used the following code.Whichever item i select from the listview appears on the 1st label.The item that is selected 2nd does not appear in the 2nd label.Im not clear what sl[1] will contain?Can you tell me the mistake?

Label[] lb = new Label[4];
           lb[0] = lb4;
           lb[1] = lb5;
           lb[2] = lb6;
           lb[3] = lb7;
           for (int h = 0; h &lt; sl.Count; h++)
           {
               lb[h].Text = sl[h].Text;
           }

King Julien7-Apr-09 19:56

Re: Retrieving multiple items from listview [modified]

7-Apr-09 19:56

ofcourse.... the code is working according to what it was written.

I assume that you are calling this code after you select the item from the listview.
In that case, have a close look at the for loop. every time the for loop counter initializes to 0

mrithula8 wrote:
for (int h = 0; h < sl.Count; h++)

it means that whatever you select, that will be assigned in order from the first label. Thats wat is happening....

If you want to display the listview item 1 in label 1, then you try getting the item number of the list view and use the same number as the index for the label control array and i think your problem could be solved.

for (int h = 0; h < sl.Count; h++)
 {
   lb[sl[i].Index].Text = sl[i].Text;
 }

Make sure that you have n number of labels if there are n number of items... otherwise it may throw you an exception....

Have a Happy Coding.....

mrithula87-Apr-09 20:10

7-Apr-09 20:10

Hi Thanks for reply.I do not want to display the 1st item in the 1st label.Suppose for the 1st time i select the 10th item that should appear in the 1st label.The 2nd time if i select the 5th item it should be displayed in the 2nd the label......Actually i uesd the code in the selected indexchanged event
<pre> private void listView1_SelectedIndexChanged(object sender, EventArgs e)
{
ListView.SelectedListViewItemCollection sl = this.listView1.SelectedItems;
Label[] lb = new Label[4];
lb[0] = lb4;
lb[1] = lb5;
lb[2] = lb6;
lb[3] = lb7;
for (int h = 0; h <= sl.Count; h++)
{
lb[h].Text = sl[h].Text;
}

}

modified on Wednesday, April 8, 2009 2:18 AM

King Julien7-Apr-09 20:21

7-Apr-09 20:21

Oh!!!

then use a wild way...

declare a static int and use that as label index

static int counter = 0;

for (int h=0; h<sl.count;>{
   if (counter < lb.Length)
   {
     lb[counter].Text = sl[h].Text;
     counter++;
   }
}

Have a Happy Coding.....

mrithula87-Apr-09 20:50

7-Apr-09 20:50

Hi When i used this, it says invalid static modifier for this item.So i used <pre>static int counter=0</pre> outside the method but im not able to select any item from listview.

King Julien7-Apr-09 20:58

Re: Retrieving multiple items from listview [modified]

7-Apr-09 20:58

Not sure how you have implemented it.

i suggest declare the counter(static int counter = 0) not inside any methods. Just declare inside it inside the class. That would do...

But how does this matter when selecting an item from the List View????

can you place the entire code block or atleast how you call this method after selecting the items.....???

Have a Happy Coding.....

mrithula87-Apr-09 21:05

7-Apr-09 21:05

Hi,
I used this code in the selectedIndexchanged().Is this right?I declared the conuter variable inside the class.When i execute the code the form does not respond.
<pre>private void listView1_SelectedIndexChanged(object sender, EventArgs e)
{
ListView.SelectedListViewItemCollection sl = this.listView1.SelectedItems;
Label[] lb = new Label[4];
lb[0] = lb4;
lb[1] = lb5;
lb[2] = lb6;
lb[3] = lb7;

for (int h = 0; h < sl.Count;){
if(counter<lb.Length)
{
lb[counter].Text=sl[h].Text;
counter++;
}
}

}

modified on Wednesday, April 8, 2009 5:18 AM

King Julien7-Apr-09 23:32

7-Apr-09 23:32

Declare a label control array in the Form class like this

public Label[] lblArray = null; 
static int counter = 0;

Inside the form load method add your labels like this.....

this.lblArray = new Label[] { label4, label5, label6 };

Then the event should look like this...

private void ListView1_SelectedIndexChanged_1(object sender, EventArgs e)
        {
            ListView.SelectedListViewItemCollection sl = ListView1.SelectedItems;
           
            for (int h = 0; h < sl.Count; h++)
            {
                if (counter < lblArray.Length)
                {
                    lblArray[counter].Text = sl[h].Text;
                    counter++;
                }
            }
        }

I have even checked this myself... Its working for me... without any problem...

Have a Happy Coding.....

mrithula88-Apr-09 0:04

8-Apr-09 0:04

Hi Thanks its working now

King Julien8-Apr-09 0:12

8-Apr-09 0:12

unmaiyavae work aagutha... illa summa solringla...????

what did you do for decrementing the counter....?????

Have a Happy Coding.....

mrithula88-Apr-09 1:12

8-Apr-09 1:12

Hi Its working the way i wanted.I dont understand why the counter should be decremented?

King Julien8-Apr-09 1:14

8-Apr-09 1:14

I dont know exactly about your application....

So no comments,....

Anyway!!

Cheers...

Have a Happy Coding.....

mrithula88-Apr-09 1:30

8-Apr-09 1:30

hi I have another doubt.If i want to find the selected index of a listbox or a listview control i can use listbox.SelectedIndex; Similarly if i have 5 checkboxes and if i want to find the index of the checkbox that is checked how do i do this?There is no Selected Index property for checkbox.

I have the exe files listed and each one is assigned a checkbox.I want to start only those exe files that i select.I am able to do this.After starting the exe files i want the client to send message to only those exe files that have been started.

I used the following code to send message to different ports
<pre>public void SendMessage()
{

try
{

label1.Text = "Enter the number of times to send the message:";
String ns = textBox1.Text;
int c = Convert.ToInt32(ns);

int[] a = new int[4];
XmlTextReader xtr1 = new XmlTextReader("p1.xml");
XmlTextReader xtr2 = new XmlTextReader("p2.xml");
XmlTextReader xtr3 = new XmlTextReader("p3.xml");
XmlTextReader xtr4 = new XmlTextReader("p4.xml");
int p1 = 0, p2 = 0, p3 = 0, p4 = 0;
while (xtr1.Read())
{
switch (xtr1.NodeType)
{
case XmlNodeType.Text:

String rv = xtr1.Value;
p1 = Convert.ToInt32(rv);
break;
}
}

while (xtr2.Read())
{
switch (xtr2.NodeType)
{
case XmlNodeType.Text:

String rv1 = xtr2.Value;
p2 = Convert.ToInt32(rv1);
break;
}
}

while (xtr3.Read())
{
switch (xtr3.NodeType)
{
case XmlNodeType.Text:

String rv2 = xtr3.Value;
p3 = Convert.ToInt32(rv2);
break;
}
}

while (xtr4.Read())
{
switch (xtr4.NodeType)
{
case XmlNodeType.Text:

String rv3 = xtr4.Value;
p4 = Convert.ToInt32(rv3);
break;
}
}
a[0] = p1;
a[1] = p2;
a[2] = p3;
a[3] = p4;
listBox2.Items.Add("Connecting....");
ch[0] = cb;
ch[1] = cb1;
ch[2] = cb3;
ch[3] = cb4;

//int r=cb

for (int i = 0; i <= c; i++)
//int i = 0;

//while (i <= 1)
{

UdpClient client = new UdpClient("127.0.0.1", a[i]);
listBox2.Items.Add("Connected");
Byte[] data = new Byte[256];
String snd = "hello";
data = Encoding.ASCII.GetBytes(snd);
IPEndPoint ipep = new IPEndPoint(IPAddress.Parse("127.0.0.1"), a[i]);
int n = client.Send(data, data.Length);
listBox2.Items.Add("Sent...");
listBox2.Items.Add("Message received from {0}:");
listBox2.Items.Add(ipep.ToString());
Byte[] received = new Byte[512];
received = client.Receive(ref ipep);
String dataReceived = System.Text.Encoding.ASCII.GetString(received);
listBox2.Items.Add(dataReceived);
listBox2.Items.Add("======================================================================");
if (dataReceived == "Welcome to the Server")
{
if (cb.Checked == true && lb4.Text != "")
{
lb8.Text = "Active";
lb8.BackColor = System.Drawing.Color.Green;
}
if (cb1.Checked == true && lb5.Text != "")
{
lb9.Text = "Active";
lb9.BackColor = System.Drawing.Color.Green;
}
if (cb3.Checked == true && lb6.Text != "")
{
lb10.Text = "Active";
lb10.BackColor = System.Drawing.Color.Green;
}
if (cb4.Checked == true && lb7.Text != "")
{
lb11.Text = "Active";
lb11.BackColor = System.Drawing.Color.Green;
}
}
else
{
lb8.Text = "Inactive";
lb8.BackColor = System.Drawing.Color.Red;

lb9.Text = "InActive";
lb9.BackColor = System.Drawing.Color.Red;

lb10.Text = "InActive";
lb10.BackColor = System.Drawing.Color.Red;

lb11.Text = "InActive";
lb11.BackColor = System.Drawing.Color.Red;
}

client.Close();

}

}
catch (Exception e)
{
listBox2.Items.Add("An Exception Occurred!");
listBox2.Items.Add(e.ToString());
}

}

King Julien8-Apr-09 2:45

How append css in html at run time

8-Apr-09 2:45

you can use the same slvi to get that.

slvi[index].checked will give you the corresponding checkbox of an item is checked or not.....

Have a Happy Coding.....

sushilabhanvar3-Apr-09 1:21

sushilabhanvar

3-Apr-09 1:21

Hi ,,

plz reply ;;;;;...........
how I can add css(cascading style sheet ) at run time in html..?????
thanks

Re: How append css in html at run time

Rajdeep.NET is BACK3-Apr-09 1:42

Rajdeep.NET is BACK

3-Apr-09 1:42

This is not the place for you Kid! Try a different forum Laugh | :laugh:

Install setup only on one PC

sjs4u3-Apr-09 1:00

sjs4u

3-Apr-09 1:00

Hi,

I developed windows application and now want to install that project only on one pc through CD.

So Is there any property want to set while creating the setup.

I want to use it only in one pc. Other people will not use it.

How can I do?

Thanks

King Julien3-Apr-09 1:14

3-Apr-09 1:14

If you want to protect your application from multiple installation use the licensing system.

you can create setup projects to start the installation only when a valid license data is entered. If not the setup will not continue.

Have a Happy Coding.....

Rajdeep.NET is BACK3-Apr-09 1:38

Rajdeep.NET is BACK

3-Apr-09 1:38

Can you please rectify what exactly you want to do with your Form? Why do u need to install your project only one one computer? Is it too bad? Poke tongue | ;-P

sjs4u3-Apr-09 1:42

sjs4u

3-Apr-09 1:42

Actually I want to prevent the copy of the project. client cant distribute it to other also. So thats why I want to do it.