Problem reading xml string and convert into a data table - XML / XSL Discussion Boards

krieath6-Mar-09 19:36

6-Mar-09 19:36

Ok so im new to XML importing with visual basic 6. I do a little programming on the side. So heres my question. I need to Import a specific Variable off of a bare xml webpage and need help figuring up the code. Im going to use a database of items with a unique Item id to get the exact page but i need to know how to extract a specific value off the automatically generated page.

For example when i click the update button in my program it will build the url string, then connect to the net to the specific page grab the value needed and move onto the next id number.

The generated pages will all look the same except for the values in the generated page will change and the only part of the url that will change is the item id number

I.E. http://eve-central.com/api/marketstat?typeid=34
http://eve-central.com/api/marketstat?typeid=35 etc. etc

Now the specific value im interested in is the median value under the buy group of the page.

!!! Big Grin | :-D

Any code or simple tutorials on the subject are GREATLY APPRECIATED Big Grin | :-D

!!!

Krieath

Re: Web based XML import help

led mike10-Mar-09 6:00

led mike

10-Mar-09 6:00

One often used method of working with XML in a Microsoft environment is to use the MSXML ActiveX object. To learn how to use MSXML and all the XML technologies associated with your problem I suggest you start looking at some of the tutorials at www.w3schools.com

Output to text file

shortdog6-Mar-09 17:28

shortdog

6-Mar-09 17:28

I am new to XML. I have tried to search for an answer to this question but haven't found any good answers.

I have created an XSD that describes a programming language (in this case C).
I have created a simple XML file that describes a simplistic hello world type program.
I have created a XSLT file that will transform that XML file into a c program.

What I would like to do is transform the XML and save the output a text or more specifically my .c file. Then I should be able to create another XSLT that would generate my .h file.

<xsl:output method="text" /> in my XSLT file.
When I load the XML file in IExplorer, the output is text on the screen, and I can copy and paste the text into a text file, but when I save as in IE it saves the original untransformed XML.

Is there a way to save the transformed output? Do I need to transform it outside of a browser somehow?

Re: Output to text file

led mike9-Mar-09 4:53

led mike

9-Mar-09 4:53

shortdog wrote:
Do I need to transform it outside of a browser somehow?

Copy/Paste from the browser might work.

Otherwise you can do a transform to a file using a XSLT utility or tool, or you might build one yourself. In most languages that have access to an XML library it takes about 5 lines of code to build a XSLT command line program.

Re: Output to text file

shortdog11-Mar-09 3:01

shortdog

11-Mar-09 3:01

Thanks, I was making this harder than it needed to be. A simple 2 line C# program was all I needed.

string manipulation in xsl - concatinating

Sree Raj5-Mar-09 14:25

Sree Raj

5-Mar-09 14:25

Hi,
Could someone plz help in generating the out put from the xml given below...

The XML Input is given below
- <Assessment>
- <Respiratory>

  <Forced>false</Forced> 
  <Irregular>false</Irregular> 
  <Kussmal>true</Kussmal> 
  <Labored>true</Labored> 
  <NasalFlaring>true</NasalFlaring> 
  <Normal>false</Normal> 
  <Rapid>false</Rapid> 
 
  </Respiratory>
</Assessment>

The Output should be the following (based on the value of true/false) as 
HTML..

Respiratory condition: Kussmal condition,Labored condition, Nasal Flaring

Re: string manipulation in xsl - concatinating

led mike6-Mar-09 4:43

led mike

6-Mar-09 4:43

Try the XSLT Tutorials at www.w3schools.com, the are tailored to beginners.

Problem reading xml string and convert into a data table

Renukapadhamanaban4-Mar-09 12:38

Renukapadhamanaban

4-Mar-09 12:38

Hi,

I am wanted to convert/store a string, which has XML elements, into a dataset or data table. The string that I am reading from a service is the result of my query. I have written the following code,

{
DataSet ds = new DataSet();

StringReader stream = new StringReader(xmlString);

ds.ReadXml(stream);

DataTable dt = ds.Tables[0];

dg.DataSource = dt;

return dt;
}

I am receiving two different type of strings, they are

xmlString1:

<?xml version="1.0" encoding="UTF-8"?>
<nh:rows xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:nh="http://nhdb">
<nh:urnumber>0123456</nh:urnumber>
<nh:surname>xxxxx</nh:surname>
<nh:forename>yyy</nh:forename>
<nh:middlename></nh:middlename>
<nh:dob>1958-10-05</nh:dob>
<nh:address>Mxaxixlx</nh:address>
<nh:suburb>Prxxxx</nh:suburb>
<nh:state>Vxxx</nh:state>
<nh:postcode>3072</nh:postcode>
<nh:patientphone>phone</nh:patientphone>
<nh:gender>Female</nh:gender>
<nh:unit>Sxxxxx Oxxxx</nh:unit>
<nh:ward>Bxxx DPxx</nh:ward>
</nh:rows>

xmlString2:

<?xml version="1.0" encoding="UTF-8"?>
<nh:rows xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:nh="http://nhdb">
<nh:urnumber>0123450</nh:urnumber>
<nh:surname>Cxxxxxx</nh:surname>
<nh:forename>RxxxxxT</nh:forename>
<nh:middlename></nh:middlename>
<nh:dob>1954-07-19</nh:dob>
<nh:address>'ANNANDALE'</nh:address>
<nh:suburb></nh:suburb>
<nh:state></nh:state>
<nh:postcode></nh:postcode>
<nh:patientphone></nh:patientphone>
<nh:gender>Male</nh:gender>
<nh:unit></nh:unit>
<nh:ward></nh:ward>
<nh:urnumber>0123451</nh:urnumber>
<nh:surname>KROL</nh:surname>
<nh:forename>ANILLA</nh:forename>
<nh:middlename></nh:middlename>
<nh:dob>1958-12-10</nh:dob>
<nh:address>68A CLARENCE</nh:address>
<nh:suburb></nh:suburb>
<nh:state></nh:state>
<nh:postcode></nh:postcode>
<nh:patientphone></nh:patientphone>
<nh:gender>Female</nh:gender>
<nh:unit></nh:unit>
<nh:ward></nh:ward>
<nh:urnumber>0123452</nh:urnumber>
<nh:surname>GEYER</nh:surname>
<nh:forename>MAUREEN</nh:forename>
<nh:middlename></nh:middlename>
<nh:dob>1948-06-02</nh:dob>
<nh:address>19 JAYSON</nh:address>
<nh:suburb></nh:suburb>
<nh:state></nh:state>
<nh:postcode></nh:postcode>
<nh:patientphone></nh:patientphone>
<nh:gender>Female</nh:gender>
<nh:unit></nh:unit>
<nh:ward></nh:ward>
</nh:rows>

The above code works perfectly for the xmlString1 and it is converting a data table with single row of data for the cloumns urnumber, surname, forename, middlename, dob, address, suburb,state, postcode,patientPhone, gender, unit, ward.

When I am receiving the xmlString2, the data table is populated with only one column urnumber_Text(for all ur numbers in the xml string).

What am I missing here? Is there any other genuine way of doing it?

Thanks a Lot for your valuable time and invaluable advice.

Looking for advice,
Renu

Re: Problem reading xml string and convert into a data table

led mike5-Mar-09 4:22

led mike

5-Mar-09 4:22

Renukapadhamanaban wrote:
What am I missing here?

The XML is not formatted as required for generalized recognition of the records. Each set of records would need a parent element to form a collection. This appears to be absent in what you posted.

Renukapadhamanaban wrote:
Is there any other genuine way of doing it?

Yes you could write code to transform the XML into the more standard form then it should load fine. This might be accomplished with XSLT but it might be simpler to use like a SAX parser or whatever the .NET equivalent is.

Re: Problem reading xml string and convert into a data table

Renukapadhamanaban9-Mar-09 15:37

Renukapadhamanaban

9-Mar-09 15:37

Hi Mike,

Thanks a lot for your valuable advice.

I tried with the parent element to each row and now it is working alright. Now I am working on XSLT to format the XML string.

THanks for your time.
Renu

Adding Header an datetime when User prints excel Sheet.

vikram_asv4-Mar-09 9:22

vikram_asv

4-Mar-09 9:22

I need to add header and datetime and orientation in excel when user print the excel document.

public static void excelprint(DataSet source, string fileName)
{
bool status = false;
try
{
System.IO.StreamWriter excelDoc;
excelDoc = new System.IO.StreamWriter(fileName);
const string startExcelXML = "<xml version>\r\n<Workbook " +
"xmlns=\"urn:schemas-microsoft-com:office:spreadsheet\"\r\n" +
" xmlns Blush | :O

=\"urn:schemas-microsoft-com:office:office\"\r\n " +
"xmlns:x=\"urn:schemas- microsoft-com:office:" +
"excel\"\r\n xmlns:ss=\"urn:schemas-microsoft-com:" +
"office:spreadsheet\">\r\n <Styles>\r\n " +
"<Style ss:ID=\"Default\" ss:Name=\"Normal\">\r\n " +
"<Alignment ss:Vertical=\"Bottom\"/>\r\n <Borders/>" +
"\r\n <Font/>\r\n <Interior/>\r\n <NumberFormat/>" +
"\r\n <Protection/>\r\n </Style>\r\n " +
"<Style ss:ID=\"BoldColumn\">\r\n <Font " +
"x:Family=\"Swiss\" ss:Bold=\"1\"/>\r\n </Style>\r\n " +
"<Style ss:ID=\"StringLiteral\">\r\n <NumberFormat" +
" ss:Format=\"@\"/>\r\n </Style>\r\n <Style " +
"ss:ID=\"Decimal\">\r\n <NumberFormat " +
"ss:Format=\"0.00\"/>\r\n </Style>\r\n " +
"<Style ss:ID=\"Integer\">\r\n <NumberFormat " +
"ss:Format=\"0\"/>\r\n </Style>\r\n <Style " +
"ss:ID=\"DateLiteral\">\r\n <NumberFormat " +
"ss:Format=\"mm/dd/yyyy;@\"/>\r\n </Style>\r\n " +
"</Styles>\r\n ";
const string endExcelXML = "</Workbook>";
int rowCount = 0;
int sheetCount = 1;

excelDoc.Write(startExcelXML);

for (int worksheet = 0; worksheet < source.Tables.Count; worksheet++)
{

excelDoc.Write("<Worksheet ss:Name=\"" + source.Tables[worksheet].TableName + "\">");
excelDoc.Write("<Table>");
excelDoc.Write("<Row>");

for (int x = 0; x < source.Tables[worksheet].Columns.Count; x++)
{
excelDoc.Write("<Cell ss:StyleID=\"BoldColumn\"><Data ss:Type=\"String\">");
excelDoc.Write(source.Tables[worksheet].Columns[x].ColumnName);
excelDoc.Write("</Data></Cell>");
}
excelDoc.Write("</Row>");

for (int x = 0; x < source.Tables[worksheet].DefaultView.Count; x++)
{
rowCount++;
if (rowCount == 64000)
{
rowCount = 0;
sheetCount++;
excelDoc.Write("</Table>");
excelDoc.Write(" </Worksheet>");
excelDoc.Write("<Worksheet ss:Name=\"Sheet" + worksheet + "\">");
excelDoc.Write("<Table>");
}
excelDoc.Write("<Row>"); //ID=" + rowCount + "
for (int y = 0; y < source.Tables[worksheet].Columns.Count; y++)
{
System.Type rowType;
rowType = source.Tables[worksheet].DefaultView[x][y].GetType();
switch (rowType.ToString())
{
case "System.String":
//string XMLstring = x[y].ToString();
string XMLstring = source.Tables[worksheet].DefaultView[x][y].ToString();
XMLstring = XMLstring.Trim();
XMLstring = XMLstring.Replace("&", "&");
XMLstring = XMLstring.Replace(">", ">");
XMLstring = XMLstring.Replace("<", "<");
excelDoc.Write("<Cell ss:StyleID=\"StringLiteral\">" +
"<Data ss:Type=\"String\">");
excelDoc.Write(XMLstring);
excelDoc.Write("</Data></Cell>");
break;
case "System.DateTime":
// DateTime XMLDate = (DateTime)x[y];
DateTime XMLDate = (DateTime)source.Tables[worksheet].DefaultView[x][y];
string XMLDatetoString = "";
XMLDatetoString = XMLDate.Year.ToString() +
"-" +
(XMLDate.Month < 10 ? "0" +
XMLDate.Month.ToString() : XMLDate.Month.ToString()) +
"-" +
(XMLDate.Day < 10 ? "0" +
XMLDate.Day.ToString() : XMLDate.Day.ToString()) +
"T" +
(XMLDate.Hour < 10 ? "0" +
XMLDate.Hour.ToString() : XMLDate.Hour.ToString()) +
":" +
(XMLDate.Minute < 10 ? "0" +
XMLDate.Minute.ToString() : XMLDate.Minute.ToString()) +
":" +
(XMLDate.Second < 10 ? "0" +
XMLDate.Second.ToString() : XMLDate.Second.ToString()) +
".000";
excelDoc.Write("<Cell ss:StyleID=\"DateLiteral\">" +
"<Data ss:Type=\"DateTime\">");
excelDoc.Write(XMLDatetoString);
excelDoc.Write("</Data></Cell>");
break;
case "System.Boolean":
excelDoc.Write("<Cell ss:StyleID=\"StringLiteral\">" +
"<Data ss:Type=\"String\">");
//excelDoc.Write(x[y].ToString());
excelDoc.Write(source.Tables[worksheet].DefaultView[x][y].ToString());
excelDoc.Write("</Data></Cell>");
break;
case "System.Int16":
case "System.Int32":
case "System.Int64":
case "System.Byte":
excelDoc.Write("<Cell ss:StyleID=\"Integer\">" +
"<Data ss:Type=\"Number\">");
// excelDoc.Write(x[y].ToString());
excelDoc.Write(source.Tables[worksheet].DefaultView[x][y].ToString());
excelDoc.Write("</Data></Cell>");
break;
case "System.Decimal":
case "System.Double":
excelDoc.Write("<Cell ss:StyleID=\"Decimal\">" +
"<Data ss:Type=\"Number\">");
// excelDoc.Write(x[y].ToString());
excelDoc.Write(source.Tables[worksheet].DefaultView[x][y].ToString());
excelDoc.Write("</Data></Cell>");
break;
case "System.DBNull":
excelDoc.Write("<Cell ss:StyleID=\"StringLiteral\">" +
"<Data ss:Type=\"String\">");
excelDoc.Write("");
excelDoc.Write("</Data></Cell>");
break;
default:
throw (new Exception(rowType.ToString() + " not handled."));

}
}

excelDoc.Write("</Row>");
}
excelDoc.Write("</Table>");
excelDoc.Write(" </Worksheet>");

}
excelDoc.Write(endExcelXML);
excelDoc.Close();
status = true;
// MessageBox.Show("Data exported to excel file successfuly");
}

catch (Exception)
{
status = false;// MessageBox.Show("Error in exporting data to excel file");
}
}

Re: Adding Header an datetime when User prints excel Sheet.

Curtis Schlak.4-Mar-09 9:42

Curtis Schlak.

4-Mar-09 9:42

@vikram_asv:

Please repost and use the <pre> tag to allow us to easily read your code. Thanks!

"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty

Re: Adding Header an datetime when User prints excel Sheet.

Ankur19784-Mar-09 13:26

Ankur1978

4-Mar-09 13:26

Hello Curtis,

I am sending u code which i used and modify with my criteria.I am able to export data to a different worksheets. But all i need is when user prints the excel sheet i need to put header, footer , date and orientation - landscape dynamically . I search but no luck may be anyone can help me about this . Here is the link
http://www.codeproject.com/KB/dotnet/ExportToExcel.aspx

Re: Adding Header an datetime when User prints excel Sheet.

Curtis Schlak.4-Mar-09 15:08

Curtis Schlak.

4-Mar-09 15:08

I don't use Microsoft Office, so I can't answer this directly. However, if you look at this article Dive into SpreadsheetML (Part 1 of 2)[^], they will show you how to set print options and what not.

Also, set the header and footer of an Excel spreadsheet to some distinct values, save it in the XML format, and look for those nodes.

Reverse engineering is the way to go, here.

"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty

Re: Adding Header an datetime when User prints excel Sheet.

vikram_asv4-Mar-09 17:03

vikram_asv

4-Mar-09 17:03

Hello Curtis, I am again reposting the code with pre tag so that it can to easy to read what u say
I need to add header and datetime and orientation in excel when user print the excel document.I am not able to add datetime ,orientation,header programmatically .if u could help me greatly appreciated where i can add this items in my code so that i can see when i print excel document.

public static void excelprint(DataSet source, string fileName)
{
bool status = false;
try
{
System.IO.StreamWriter excelDoc;
excelDoc = new System.IO.StreamWriter(fileName);

const string startExcelXML =
<xml version="">
<workbook xmlns="urn:schemas-microsoft-com:office:spreadsheet">
xmlns Blush | :O

="urn:schemas-microsoft-com:office:office"
xmlns:x="urn:schemas-microsoft-com:office:excel"
xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet">
<styles>

<alignment ss:vertical="Bottom">
<borders>
<font />
<interior />
<numberformat />
<protection />
</borders></alignment>

<font x:family="Swiss" ss:bold="1" xmlns:x="#unknown" />

<numberformat ss:format="@" />

<numberformat ss:format="0.0000" />

<numberformat ss:format="0" />

<numberformat ss:format="mm/dd/yyyy;@" />

const string endExcelXML = "</Workbook>";
int rowCount = 0;
int sheetCount = 1;

excelDoc.Write(startExcelXML);

for (int worksheet = 0; worksheet < source.Tables.Count; worksheet++)
{

excelDoc.Write("<Worksheet ss:Name=\"" + source.Tables[worksheet].TableName + "\">");
excelDoc.Write("<Table>");
excelDoc.Write("<Row>");

for (int x = 0; x < source.Tables[worksheet].Columns.Count; x++)
{
excelDoc.Write("<Cell ss:StyleID=\"BoldColumn\"><Data ss:Type=\"String\">");
excelDoc.Write(source.Tables[worksheet].Columns[x].ColumnName);
excelDoc.Write("</Data></Cell>");
}
excelDoc.Write("</Row>");

for (int x = 0; x < source.Tables[worksheet].DefaultView.Count; x++)
{
rowCount++;
if (rowCount == 64000)
{
rowCount = 0;
sheetCount++;
excelDoc.Write("</Table>");
excelDoc.Write(" </Worksheet>");
excelDoc.Write("<Worksheet ss:Name=\"Sheet" + worksheet + "\">");
excelDoc.Write("<Table>");
}
excelDoc.Write("<Row>"); //ID=" + rowCount + "
for (int y = 0; y < source.Tables[worksheet].Columns.Count; y++)
{
System.Type rowType;
rowType = source.Tables[worksheet].DefaultView[x][y].GetType();
switch (rowType.ToString())
{
case "System.String":
//string XMLstring = x[y].ToString();
string XMLstring = source.Tables[worksheet].DefaultView[x][y].ToString();
XMLstring = XMLstring.Trim();
XMLstring = XMLstring.Replace("&", "&");
XMLstring = XMLstring.Replace(">", ">");
XMLstring = XMLstring.Replace("<", "<");
excelDoc.Write("<Cell ss:StyleID=\"StringLiteral\">" +
"<Data ss:Type=\"String\">");
excelDoc.Write(XMLstring);
excelDoc.Write("</Data></Cell>");
break;
case "System.DateTime":
// DateTime XMLDate = (DateTime)x[y];
DateTime XMLDate = (DateTime)source.Tables[worksheet].DefaultView[x][y];
string XMLDatetoString = "";
XMLDatetoString = XMLDate.Year.ToString() +
"-" +
(XMLDate.Month < 10 ? "0" +
XMLDate.Month.ToString() : XMLDate.Month.ToString()) +
"-" +
(XMLDate.Day < 10 ? "0" +
XMLDate.Day.ToString() : XMLDate.Day.ToString()) +
"T" +
(XMLDate.Hour < 10 ? "0" +
XMLDate.Hour.ToString() : XMLDate.Hour.ToString()) +
":" +
(XMLDate.Minute < 10 ? "0" +
XMLDate.Minute.ToString() : XMLDate.Minute.ToString()) +
":" +
(XMLDate.Second < 10 ? "0" +
XMLDate.Second.ToString() : XMLDate.Second.ToString()) +
".000";
excelDoc.Write("<Cell ss:StyleID=\"DateLiteral\">" +
"<Data ss:Type=\"DateTime\">");
excelDoc.Write(XMLDatetoString);
excelDoc.Write("</Data></Cell>");
break;
case "System.Boolean":
excelDoc.Write("<Cell ss:StyleID=\"StringLiteral\">" +
"<Data ss:Type=\"String\">");
//excelDoc.Write(x[y].ToString());
excelDoc.Write(source.Tables[worksheet].DefaultView[x][y].ToString());
excelDoc.Write("</Data></Cell>");
break;
case "System.Int16":
case "System.Int32":
case "System.Int64":
case "System.Byte":
excelDoc.Write("<Cell ss:StyleID=\"Integer\">" +
"<Data ss:Type=\"Number\">");
// excelDoc.Write(x[y].ToString());
excelDoc.Write(source.Tables[worksheet].DefaultView[x][y].ToString());
excelDoc.Write("</Data></Cell>");
break;
case "System.Decimal":
case "System.Double":
excelDoc.Write("<Cell ss:StyleID=\"Decimal\">" +
"<Data ss:Type=\"Number\">");
// excelDoc.Write(x[y].ToString());
excelDoc.Write(source.Tables[worksheet].DefaultView[x][y].ToString());
excelDoc.Write("</Data></Cell>");
break;
case "System.DBNull":
excelDoc.Write("<Cell ss:StyleID=\"StringLiteral\">" +
"<Data ss:Type=\"String\">");
excelDoc.Write("");
excelDoc.Write("</Data></Cell>");
break;
default:
throw (new Exception(rowType.ToString() + " not handled."));

}
}

excelDoc.Write("</Row>");
}
excelDoc.Write("</Table>");
excelDoc.Write(" </Worksheet>");

}
excelDoc.Write(endExcelXML);
excelDoc.Close();
status = true;
// MessageBox.Show("Data exported to excel file successfuly");
}

catch (Exception)
{
status = false;// MessageBox.Show("Error in exporting data to excel file");
}
}

Re: Adding Header an datetime when User prints excel Sheet.

vikram_asv4-Mar-09 17:06

vikram_asv

4-Mar-09 17:06

xml version

/*
<xml version>
<Workbook xmlns="urn:schemas-microsoft-com:office:spreadsheet"
xmlns Blush | :O

="urn:schemas-microsoft-com:office:office"
xmlns:x="urn:schemas-microsoft-com:office:excel"
xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet">
<Styles>
<Style ss:ID="Default" ss:Name="Normal">
<Alignment ss:Vertical="Bottom"/>
<Borders/>
<Font/>
<Interior/>
<NumberFormat/>
<Protection/>
</Style>
<Style ss:ID="BoldColumn">
<Font x:Family="Swiss" ss:Bold="1"/>
</Style>
<Style ss:ID="StringLiteral">
<NumberFormat ss:Format="@"/>
</Style>
<Style ss:ID="Decimal">
<NumberFormat ss:Format="0.0000"/>
</Style>
<Style ss:ID="Integer">
<NumberFormat ss:Format="0"/>
</Style>
<Style ss:ID="DateLiteral">
<NumberFormat ss:Format="mm/dd/yyyy;@"/>
</Style>
</Styles>
<Worksheet ss:Name="Sheet1">
</Worksheet>
</Workbook>
*/

Re: Adding Header an datetime when User prints excel Sheet.

AndyInUK4-Mar-09 23:28

AndyInUK

4-Mar-09 23:28

use pre tag mate as curtis asked you. Look around for pre tag before you post and post once again.

All the best

XML/XSL transformation question.

Maximilien4-Mar-09 9:08

Maximilien

4-Mar-09 9:08

Howdy'

I'm generating some XML files with MSXML; The text is all put on one single line;
so I'm trying to transform the document with some XSL "black" magic.

The stylesheet (taken from some google-search):

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" />
<xsl:template match="*">
   <xsl:copy>
      <xsl:copy-of select="@*" />
      <xsl:apply-templates />
   </xsl:copy>
</xsl:template>
</xsl:stylesheet>

This works well, except for one minor thing.

For empty "tags", the transformation transform :

<MyTag attribute="value"/>

<MyTag attribute="value"></MyTag >

I'm not quite familiar with XSL, and was wondering if there's a way to not create the empty closing tags ?

I hope it makes sens.
Thanks.
Max.

This signature was proudly tested on animals.

Re: XML/XSL transformation question.

Curtis Schlak.4-Mar-09 9:17

Curtis Schlak.

4-Mar-09 9:17

Is there a reason why you don't want the closing tag? Both of the nodes, the one with the /> and the one with the ></MyTag> have the same meaning in XML and should parse the same way....

"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty

Re: XML/XSL transformation question.

Maximilien4-Mar-09 9:29

Maximilien

4-Mar-09 9:29

For no other reason than "aestheticism"

This signature was proudly tested on animals.

Re: XML/XSL transformation question.

Curtis Schlak.4-Mar-09 9:40

Curtis Schlak.

4-Mar-09 9:40

Yeah, I like it that way, too.

No, if you're using MSXML, there's no way to force it to output />. It's hard-coded to do that, as far as I know, having used it for quite a long time.

"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty

AndyInUK4-Mar-09 3:59

AndyInUK

4-Mar-09 3:59

how can i setup a parser to log in to particular page and grab a cookie ?

Thanks
Andyyy

Re: cookies

Curtis Schlak.4-Mar-09 9:20

Curtis Schlak.

4-Mar-09 9:20

Most likely, Andy, you'll have to do the following in the programming language of your choice:

Create the content for the login POST request.
Stream the post request to the server over the applicable port.
Read the response.
Parse out the Set-Cookie lines from the HTTP response.

Here's the HTTP RFC[^] for reference.

"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty

Re: cookies

AndyInUK4-Mar-09 23:35

AndyInUK

4-Mar-09 23:35

Thanks for your reply.
is there any psudo code which i can follow in xsl or xml ?
Cheers
Andyy Smile | :)

Re: cookies

Curtis Schlak.5-Mar-09 10:59

Curtis Schlak.

5-Mar-09 10:59

This really isn't an XML or XSL problem.

"we must lose precision to make significant statements about complex systems."
-deKorvin on uncertainty

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