Re: Custom control's property problem - C# Discussion Boards

31-Dec-08 18:35

i have developed a custom control that have some property to show/hide its child controls. When i set their Visible prop to False the get Hide. But when i run it or just reopen that control they appear again. Any solution ?

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beatles169231-Dec-08 23:28

beatles1692

31-Dec-08 23:28

Hi Can you send us some code ?

Xmen Real 31-Dec-08 23:31

31-Dec-08 23:31

didnt think it would need, well here is it.

public bool ShowThing
{
get { return picturebox1.Visible; }
set { picturebox1.Visible = value; }
}

Pedram Behroozi1-Jan-09 0:49

Pedram Behroozi

1-Jan-09 0:49

Hi,
Unfortunately I couldn't get you. What do you mean by Run It? Or Reopen It?
When you create a new instance of a Control (User Controls too) its properties got their default values (I hope I could tell it right).

I died as a mineral and became a plant,
I died as plant and rose to animal,
I died as animal and I was Man.
Why should I fear? When was I less by dying?
-- Rumi[^]

My blog

Xmen Real 1-Jan-09 0:55

1-Jan-09 0:55

i know that...'run it' mean run the application

Pedram Behroozi1-Jan-09 1:21

Pedram Behroozi

1-Jan-09 1:21

Ummm... So you set the ShowThing value to false but when you run your application they're visible?
Maybe you changed some values in PropertyBinding or DataBinding. Make sure their values are set to none.
I have a UC like you. It has a property named TextMultiLine, here:

public partial class LabeledTextBox : UserControl
{
    public bool TextMultiLine
    {
        get { return txtText.Multiline; }
        set { txtText.Multiline = value; }
    }
}

And I have no problem with it:

public partial class frmMain : Form
{
    public frmMain()
    {
        InitializeComponent();
        LabeldTextBox ltxt = new LabeledTextBox();
        
        ltxt.TextMultiLine = true; // And it works in runtime and everywhere else
    }
}

I think your problem is in somewhere else. I hope you can find it Smile | :)

I died as a mineral and became a plant,
I died as plant and rose to animal,
I died as animal and I was Man.
Why should I fear? When was I less by dying?
-- Rumi[^]

My blog

Xmen Real 1-Jan-09 1:51

1-Jan-09 1:51

dude, its works after InitializeComponent() called but not before. Dunno whats the cause

Eddy Vluggen2-Jan-09 2:07

Eddy Vluggen

2-Jan-09 2:07

Do you by any chance have a private field that looks like this?

private bool ShowThing = true;

I are troll Smile | :)

Xmen Real 2-Jan-09 3:22

2-Jan-09 3:22

it wont showup in propertygrid

Eddy Vluggen2-Jan-09 21:53

Eddy Vluggen

2-Jan-09 21:53

[Browsable(true)]
public bool TextMultiLine
{
        get { return txtText.Multiline; }
        set { txtText.Multiline = value; }
}

This?

I are troll Smile | :)

Xmen Real 2-Jan-09 22:02

Datagrid Combo box binding

2-Jan-09 22:02

well, i got it work...I just needed to make a bool variable that hold the value and i return its value in property and in set i set both(the visible property and that variable). It worked like charm

mrcooll31-Dec-08 2:46

mrcooll

31-Dec-08 2:46

hi ,
i have this problem,
i have a grid contains project combo box and projectStage combo,when i select the project from first combo it will filter the second combo values,
i got it but when i m selecting the project for the next row it filter all second combo values even in the first row, here is my code

private void FrmMain_Load(object sender, EventArgs e)
{
EMS.Timesheet timesheet = new WindowsApplication1.EMS.Timesheet();
dsInitialData = timesheet.GetInitialData(UserProfile.EmployeeId);

bscProject.DataSource = dsInitialData.Tables["Projects"];
dgvTimeAttProject.DataSource = bscProject;
dgvTimeAttProject.DisplayMember = "ProjectRef";
dgvTimeAttProject.ValueMember = "ProjectId";

bscStage.DataSource = dsInitialData.Tables["Stages"]; ;
//bscStage.Filter = "ProjectTypeId=-1";
dgvTimeAttStage.DataSource = bscStage;
dgvTimeAttStage.DisplayMember = "StageName";
dgvTimeAttStage.ValueMember = "ProjectStageId";
}

private void dgvTimeAtt_CellValueChanged(object sender, DataGridViewCellEventArgs e)
{
try
{
if (e.RowIndex == -1)
return;

if (dgvTimeAttProject.Index == e.ColumnIndex)
{
int ProjectId = (int)dgvTimeAtt.Rows[e.RowIndex].Cells[dgvTimeAttProject.Index].Value;
int projectTypeId = GetProjectType(ProjectId);
bscStage.Filter = "ProjectTypeId=" + projectTypeId.ToString();
bscActivity.Filter = "ProjectTypeId= " + projectTypeId.ToString();

//dgvTimeAttStage.DataSource = dsInitialData.Tables["Stages"].Select("ProjectTypeId=" + projectTypeId.ToString());
//dgvTimeAttActivity.DataSource = dsInitialData.Tables["Activities"].Select("ProjectTypeId= " + projectTypeId.ToString());
}
}

catch (Exception ex) { throw ex; }

}

so how can i overcome this problem?

Re: Datagrid Combo box binding

mrcooll31-Dec-08 5:13

mrcooll

31-Dec-08 5:13

i will ask it in other words,
if i have grid with tow DataGridViewComboBoxColumn first one for contries and second one for cities , when the user select a country the city combo will have the all cities in the country selected in first grid ,
i did it like that:

bscCountries.datasource=GetAllCountries();
dgvCol_Countries.DataSource =bscCountries;
dgvCol_Countries.DisplayMember ="Name";
dgvCol_Countries.ValueMember = "ID";

bscCities.datasource=GetAllCities);
dgvCol_Cities.DataSource =bscCities;
dgvCol_Cities.DisplayMember ="Name";
dgvCol_Cities.ValueMember = "ID";

private void dgvTimeAtt_CellValueChanged(object sender, DataGridViewCellEventArgs e)
{
bsc_Cities.filter="CountryId="+dgvCol_Countries.Rows[e.RowIndex].Cell[e.CellIndex].value;
}
that's work fine but , when i go to next row in the grid and select other country the selected city i choose is gone .
How can i fix it?

Need regular expression for spliting string

Ramesh Ramalingam31-Dec-08 1:45

Ramesh Ramalingam

31-Dec-08 1:45

Hi friends,
I need to split the line which I am reading from a csv file using ,(comma). But I need to skip the commas which are coming inside quote.For example for line
1,12/12/2008,"This is test, test2"
The result should be

1<br />
12/12/2008<br />
"This is test, test2"

not like

1<br />
12/12/2008<br />
"This is test, <br />
test2"

Please guide me to do this with regular expression or by any other method.
Thanks in advance
Ramesh Ramalingam

Rob Philpott31-Dec-08 1:50

Rob Philpott

31-Dec-08 1:50

Personally I'd iterate over each character in the string, adding it to a stringbuilder and outputting the result on a comma or end of line. Use a boolean toggle on double quotes to disable in quote commas.

Regards,
Rob Philpott.

PIEBALDconsult31-Dec-08 4:12

PIEBALDconsult

31-Dec-08 4:12

Yeah, that's what I do.

#realJSOP31-Dec-08 4:32

#realJSOP

31-Dec-08 4:32

I wrote a class for expressly that purpose.

http://www.codeproject.com/KB/recipes/qstringparser_net.aspx[^]

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-----
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User 665831-Dec-08 1:59

User 6658

31-Dec-08 1:59

You've not given enough information about the format of your string, so this regex will match the given string, but might not work on other strings:

(\d+),(\d+/\d+/\d+),(.+)

regards

modified 12-Sep-18 21:01pm.