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Hi
Does anyone know What this function actually does. I've created a Setup Program which adds various entries for file types which are Seldomly used, but, which are crucial files to unravel a screwup.
All the client has to do, is, under guidance of our support team, double click the file with the requisite extension, and the recovery program should run. The Only thing that may never have happened is the Prior running of 'EnableShellOpen' from within the particular App. How would this affect things. I do not use anything like DDE, COM, OLE, or whatever other incantations. All Apps communicate by directly reading from, or writing to Files on the Server.
Regards, 
Bram van Kampen
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Bram van Kampen wrote: Does anyone know What this function actually does.
Are you using it in conjunction with RegisterShellFileTypes()? You could also supply a .reg file with your application for manual registration of document types.
"Love people and use things, not love things and use people." - Unknown
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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No, I culled items from MFC, and am generally 'Rolling my Own'
I am not using the 'MFC Document type architecture'
I've written the code to emulate 'RegisterShellFileTypes()'
All I require is that the shell launches the App, with the File name on the Command line. See also my conversation with Mark Salsburry on this.
Regards,
Bram van Kampen
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According to the source code, it sets things up so DDE can
be used by the shell to pass an open command to your app if it's
already running.
See CWinApp::OnDDECommand()
Mark
Mark Salsbery
Microsoft MVP - Visual C++
![Java | [Coffee]](https://codeproject.global.ssl.fastly.net/script/Forums/Images/coffee.gif)
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Hey y'all,
How would I make a DialogBox a child window of the main View window in an SDI project?, or am I going about this wrong?
By the way I'm using C++ 6.0
Mike
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Mike Hankey wrote: How would I make a DialogBox a child window...
The CDialog constructor takes a parent as one of its arguments.
"Love people and use things, not love things and use people." - Unknown
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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David,
You are right...is my thinking right;
CCeDBTestView::CCeDBTestView()
{
poutputDlg = new COutputDlg;
poutputDlg->ShowWindow(SW_SHOW);
}
I get an ASSET failed in winocc.cpp
I show be able to create it then show it? I'm obviously missing something?
Mike
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You need to call Create with the pointer created by new.
Try this:
CCeDBTestView::CCeDBTestView()
{
poutputDlg = new COutputDlg;
if (poutputDlg != NULL)
{
if (poutputDlg->Create(COutputDlg::IDD,this))
poutputDlg->ShowWindow(SW_SHOW);
}
else
AfxMessageBox("Error creating OutputDlg!");
}
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NO still no luck...Thats basically what I had to begin with but tried to narrow things down, same error goes south on the ShowWindow staement?
Thanks for your help
Mike
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Does your child dialog include an ActiveX control?
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No right now it doesn't contain anything. What I wanted to use it for is a container for controls and have several where I could switch views.
Mike
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Come to think of it, creating the child dialog in the view constructor is not the right place. The view window has not been created yet.
Try creating the child dialog in the OnInitialUpdate handler for the view. Alternatively you can create your child dialog in the OnCreate handler (after you have called CView::OnCreate).
I just created a simple SDI app and tried creating a child dialog in the constructor and saw the same ASSERT you are getting. I then moved the child creation code into OnInitialUpdate and the child dialog was created successfully.
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Your right my bleary mind didn't pick up it til you mentioned it.  )
Thanks,
Mike
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For a modal dialog box, try:
CCeDBTestView::CCeDBTestView()
{
COutputDlg poutputDlg(this);
poutputDlg.DoModal();
}
"Love people and use things, not love things and use people." - Unknown
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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the below function tokenize the string "ram,red,orange,,blue,,yellow,white" as
ram
red
orange
blue
yellow
white
but I want a "sapce" if no value is present between commas. So that result should be
ram
red
orange
blue
yellow
white
- Nandu
void Tokenize(const string& str, vector<string>& tokens, const string& delimiters )
{
// Skip delimiters at beginning.
string::size_type lastPos = str.find_first_not_of(delimiters, 0);
// Find first "non-delimiter".
string::size_type pos = str.find_first_of(delimiters, lastPos);
while (string::npos != pos || string::npos != lastPos)
{
// Found a token, add it to the vector.
tokens.push_back(str.substr(lastPos, pos - lastPos));
// Skip delimiters. Note the "not_of"
lastPos = str.find_first_not_of(delimiters, pos);
// Find next "non-delimiter"
pos = str.find_first_of(delimiters, lastPos);
}
}
int main(int argc, char* argv[])
{
vector<string> tokens;
vector<string>::iterator it;
string str = "ram,red,orange,,blue,,yellow,white";
Tokenize(str,tokens,",");
cout<<str;
for (it = tokens.begin(); it <tokens.end(); it++)
cout<<*it<<'\n';
getch();
return 0;
}
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Hi,
Below code shows how to get the last occurrence of a string. But in this case string::rfind reads the string from the starting and gives the last occurrence.
string str ("The sixth sick sheik's sixth sheep's sick.");
string key ("sixth");
size_t found;
found=str.rfind(key);
if (found!=string::npos)
str.replace (found,key.length(),"seventh");
cout << str << endl;
(EXAMPLE:1)
But I need a code to find the last occurrence of a string reading it from the last rather than reading it from starting. Using only string operations.
This is because I have a requirement where I need to read a string from the end, improve the performance as below shown scenario
#STAR
Data…
Data..
…………
……….
Data……
#END
We will receive a huge string (about 10mb) of data from server as show above (in the above format). To confirm that we have received the whole set of data, just check for #START and #END tag. As of now I am reading the #END using string::rfind(), which takes some time to give the result. So is there any to find a word in a string reading from end. Reading from the end will reduce the time for finding the #EDN tag.
So please proved a solution to read a string from the end.
-Nandu
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Hi,
how about searching only the last part of the string, by getting its length, then adding say len-20
to the string pointer, then do a "find last occurence"? And as a safety net (if one is needed) if
no match, try the normal approach.
However, if the length has to be obtained by scanning for a NULL (as strlen would do), not much
may be gained!
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Thanks for your reply,
But this approach will not help, boz some tags may also present at the end as show below.
#START
data
....
....
#END
#DATE
#TIME
That's why I need an approach to find a word in a string from end.
-Nandu
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Hi,
assuming you get the length in an inexpensive way, search the last N1, on failure the last N2,
on failure the last N3 characters, where it is up to you to decide what appropriate values for
N1, N2, N3 are. You might go for 10%, 20%, 30% or something similar. The basic idea is to
have more than 50% chance N1 will find a match.
if the length is as expensive as strlen, IMO there is nothing you can do once all the data is
in a single string.
Whatever the case be, I would tend to avoid having such big strings to begin with.
There must be better ways to store the data. If, before being turned into a big string, it
comes in in buckets, why not search the last bucket, or possibly the last two?
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above suggestion will not help.
Can help me in this regard. Is there any other solution.?
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Is there any external data available that indicates the length of the string.
I would consider it sort of nasty to send anyone a \0 terminated string of upto 10 MByte.( A bit Error prone too) If it comes to that type of size, an extra 4 bytes to indicate the length of the string at the start would help, (i.e. Make it a Pascal String) and will hardly hit performance.)
But, How does your Receiving Software know to allocate buffer of sufficient size to hold the data in the first place. Drill into that with your debugger, and you might find your answer.
Regards,
Bram van Kampen
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