C / C++ / MFC

SnaKeBeD wrote:

this program made by myself is creating a file in the application path

Mark Salsbery
Microsoft MVP - Visual C++

raju.k wrote:

i have one doubt with my project regarding with CFile ..how to write serial number in a file regarding with file size.

the file contains data like this ..

abs
der
con
foj
etc..


this is the file structure the output file like this only..

1.abs
2.der
3.con
4.foj
etc..

how its possible.?

CStdioFile csf;
CFileException cfe;
CString str, sTemp;
CStringArray csa;
int iSize=0, iVer=0;


if ( !csf.Open(_T("E:\\Some.txt"), CFile::modeReadWrite, &cfe) )
    AfxMessageBox(_T("Failed to open the file"));

while(csf.ReadString(str))
{
    sTemp = str;
    str.Format(_T("%d. %s"), iVer+1, sTemp);
    csa.Add(str);
    ++iVer;
}

csf.SeekToBegin();
iSize = csa.GetSize();

for(int i=1; i<=iSize; ++i)
{
    sTemp.Format("%s\n", csa.GetAt(i-1));
    csf.WriteString(sTemp);
}
csf.Close();

George_George wrote:

1.

I think it means an operator &, which returns const Inner* type and takes no arguments, right?

const Inner* pInner = &objOuter\\ object of Outer or the class within which the operator is defined
error C2440

const Outer::Inner * operator &();

Outer OuterObj;
const   Outer::Inner *   innerObj = (const   Outer::Inner * )(OuterObj);
or
const   Outer::Inner *   &innerObj = (const   Outer::Inner * &)(OuterObj);

Rajkumar_R wrote:

const Outer::Inner * innerObj = (const Outer::Inner * )(OuterObj);

Rajkumar_R wrote:

const Outer::Inner * &innerObj = (const Outer::Inner * &)(OuterObj);

class O
{
public:
  class I
  { } m;
  const I* operator &() {
    printf("const I* operator & \n");
    return &m;
  }
};
void main()
{
  O  v;
  const O::I* p = &v;
}

const I* operator &

Maxwell Chen wrote:

This does not compile.

Maxwell Chen wrote:

class I { } m;
const I* operator &()
{
printf("const I* operator & \n");
return &m;
}

public:  
class I  { } m;  
operator const I* &() 
{    
printf("const I* operator & \n");    
return &m;  
}

class I  { } 
	const *m;  

	operator const I*  &()  
	{    printf("const I* typecast operator & \n");    
	return m;  
	}

Maxwell Chen wrote:

This compiles, but the member operator function is not invoked.

Rajkumar_R wrote:

class I { } const *m;
operator const I* &() {
printf("const I* typecast operator & \n");
return m;
}

class O
{
public:
  class I
  {} const* m;
  O() : m(new I()) {}
  operator const I* &() {
    printf("operator const I* & \n");
    return m;
  }
};
void main()
{
  O v;
  const O::I* &p = v; // got it!
  const O::I* &q = (const O::I* & )v; // the same.
}

Rajkumar_R wrote:

So now you can compile without error

pther wrote:

I do not have any idea of shell menu.