C#

M. Nauman Yousuf wrote:

Now when I select multiple files, it opens up multiple console windows displaying path of each file in each console window.

myapp.exe filename1.txt
myapp.exe filename2.txt
myapp.exe filename3.txt
myapp.exe filename4.txt

myapp.exe filename1.txt filename2.txt filename3.txt filename4.txt

private System.Windows.Forms.ContextMenu emptymenu = new ContextMenu();
private System.Windows.Forms.ContextMenu oldmenu;
private void button1_MouseDown(object sender, System.Windows.Forms.MouseEventArgs e)
{
    if(e.Button == MouseButtons.Right)
    {
        if(button1.ContextMenu!=emptymenu)
            oldmenu = button1.ContextMenu;  //this will save the original menu.

        button1.ContextMenu = emptymenu; //this setts a empty menu to the property, which has the effect that no menu is shown.
    }
    else if(e.Button == MouseButtons.Left)
    {
        if(oldmenu!=null)   //the right mouse button was already pressed
        {
            button1.ContextMenu = oldmenu;
        }
        button1.ContextMenu.Show(button1, new Point(e.X,e.Y));
    }
}

private void button1_MouseDown(object sender, System.Windows.Forms.MouseEventArgs e)
{
    if(e.Button == MouseButtons.Left)
    {
        if(button1.ContextMenu!=null)
        {
            button1.ContextMenu.Show(button1, button1.Location);
        }
    }
}

private void button1_MouseDown(object sender, System.Windows.Forms.MouseEventArgs e)
{
    if(e.Button == MouseButtons.Left)
    {
        if(button1.ContextMenu!=null)
        {
            button1.ContextMenu.Show(button1, new System.Drawing.Point(e.X, e.Y));
        }
    }
}

button1.ContextMenu.Show(button1, Cursor.Current.Position);

Stefan Troschtz wrote:

button1.ContextMenu.Show(button1, Cursor.Current.Position);