C#

<br />
[XmlIgnore()]<br />
public string FullName<br />
{<br />
get<br />
{<br />
return this.FirstName + " " this.LastName;<br />
}<br />
}<br />
<br />

beatles1692 wrote:

Hi
I'm affraid that's impossible but you can have a computed property ( which concats the first name and last name and returns the full name) and you can ignore it using XmlIgnore attribute.

        <br />
[XmlAttribute("firstname")]<br />
[System.ComponentModel.DefaultValue("----")]<br />
public string Firstname<br />
{<br />
  get<br />
  {<br />
    return ( "----" );<br />
  }<br />
  set<br />
  { <br />
     this.Firstname = value;<br />
  }<br />
}<br />

<br />
public class Teacher{<br />
 private ArrayList ClassList = new ArrayList();<br />
 private ArrayList StudentList = new ArrayList();<br />
 [XMLAttribute("name");<br />
 public string Name;<br />
 [XMLElement("class")]<br />
 public Class[] AddClasses {  // Note: this will not be called until after all Class objects <br />
                              //       have been deserialised<br />
  get {return new Class[0];} // ignore serialising for now<br />
  set {<br />
    foreach( Class newClass in (Class[])value) {<br />
      newClass.teacher = this.Name};  // Hydrodynamics 101 now knows it is taught by Johnson<br />
      this.ClassList.Add(newClass);   // Johnson now knows that he/she is instructing Hydrodynamics 101 <br />
    }<br />
  }<br />
}<br />
<br />
public class Class {<br />
 [XMLAttribute("name")<br />
 public string Name;<br />
<br />
 [XMLIgnore]<br />
 public string teacher; // set by Johnson when Hydrodynamics 101 is added to the Johnson's list of classes<br />
 [XMLElement("student")]<br />
 public Student[] AddStudent {  // Note: this will not be called until after all Student objects have<br />
                                //       been deserialised<br />
  get {return new Student[0];} // ignore serialisation for now<br />
  set {<br />
    foreach( Student newStudent in (Student[]value) {<br />
      newStudent.ClassesToGoTo = this.Name;  // Billy now knows he is attending Hydrodynamics<br />
      newStudent.MyInstructors = ?  // **** How do I find the Teacher? Class["Hydrodynamics 101"].Teacher<br />
                                    //      is null because Class["Hydrodynamics 101"].AddClasses has <br />
                                    //      not been called yet because we aren't done deserialising all<br />
                                    //      the students within the element (namely billy).<br />
                                    //      Additionally, Teacher["Johnson"].ClassList is empty for the<br />
                                    //      same reason.<br />
    }<br />
  }<br />
}<br />
<br />
public class Student{<br />
 [XMLAttribute("name");<br />
 public string Name;<br />
 private ArrayList ClassesToGoTo = new ArrayList();<br />
 private ArrayList MyInstructors = new ArrayList();<br />
}<br />
<\code><br />
<br />
I know it's not complete, but hopefully it will illustrate my dilemma. <br />
<br />
<br />
 -- modified at 13:39 Monday 6th November, 2006 <br />
<br />
<div class="ForumSig">Clive Pottinger,<br />
Hamilton ON</div>

<br />
private void dataGridView1_CellMouseDown(object sender, DataGridViewCellMouseEventArgs e)<br />
{<br />
   dataGridView1.CurrentCell = DataGridView1.Rows[e.RowIndex].Cells[e.ColumnIndex];<br />
   this.dataGridView1.ContextMenuStrip = this.contextMenuStrip1;<br />
}

DataRow dt = dataSet.Tables["customers"].Rows[0];<br />
dataGridView2.Rows.Add(dt[0] , dt[1] , dt[2] ....... );

DataGridViewComboBoxColumn cboColumn = new DataGridViewComboBoxColumn();<br />
cboColumn.Items.Add("a");<br />
cboColumn.Items.Add("b");<br />
dataGridView2.Rows.Add("", cboColumn, "");

Maercu wrote:

what if someone (an enduser) doesn't have say MS Project installed?
The sources won't compile,

Maercu wrote:

In fact we would like to test if MS Project (or another application) is installed and if not simply don't provide the functionality. I searched on MSDN, Google Groups, etc but did not find something useful...

string _test = _date + " " + _time;<br />
DateTime _dateTimeNew = Convert.ToDateTime(_test);

// Force the culture to English (GB).<br />
CultureInfo culture = new CultureInfo("en-GB");<br />
<br />
string dateTime = Convert.ToDateTime(_date + " " + _time, culture);