C / C++ / MFC

14-Jul-06 8:12

Can I open solution in created in VS2005 professional in VS2005 Team Developer is any migration or any know issues going?

Smile | :)

Jun Du14-Jul-06 8:22

14-Jul-06 8:22

Do you mean Visual Stuio Team System (VSTS)? Visual Studio.NET is the majort part of VSTS. Besides, VSTS also incorporated project management, source control, bug reporting and so on.

Best,
Jun

Alex_Y14-Jul-06 8:43

14-Jul-06 8:43

Imagine I created my project in VS2005 professional at the moment when Team Edition wasn't released yet. Now I got Team Developer if I open solution/project in Team developer created in VS2005Prof is it going to migrate project or no migration needed?

Smile | :)

Jun Du14-Jul-06 9:23

14-Jul-06 9:23

No migration to your Visual Studio.NET projects. The Team System uses the very same VC++.NET as its compiler. Of course, you need to set up Team System, such as Microsoft Fundation Server. But this has nothing to do with project migration. Project migration is only required when your compiler is upgraded, such as VC6 to VC7 to VC8.

Best,
Jun

Alex_Y14-Jul-06 9:36

14-Jul-06 9:36

Thanks. Any tips convering projects fom VC6 -> VC8

Smile | :)

Jun Du14-Jul-06 9:49

14-Jul-06 9:49

In most cases, just load the VC6 project to VC8. The migration will be performed by VC8 automatically.

Best,
Jun

Alex_Y14-Jul-06 11:25

What's the best way to do this?

14-Jul-06 11:25

Yes thanks. I mean didyou discover any obvious issues I need to take care?

Thanks anyway for usefull info.

Smile | :)

Alex Cutovoi14-Jul-06 8:07

Alex Cutovoi

14-Jul-06 8:07

Hi fellows

I'm creating a app that reads data from a database and creates a graphic to show the results. I have a problem with this. I'll have a lot of registers, about 50000. I've think to sum the quantities of the registers and adjust the x-axis and the y-axis according this values. But for this I need to have a big screen resolution. How can I do this to show for the user adjusting in the window program? If anyone knows please tell me. I just want to get an idea, only this, not the entire solution.
I put a piece of code if anyone gets interesting

<br />
RECT tempRect, myRect;<br />
         GetClientRect(hwnd, &tempRect);<br />
         HBRUSH rectBrush;<br />
         char cTemp3[10];<br />
         int iSize = sizeof(tempPoint)/sizeof(POINT);<br />
         int iXMarquees, iYMarquees, iXSpace, iYSpace = 0;<br />
         POINT points[iSize], tmpPoint;<br />
         LOGPEN LogPen;<br />
         HPEN GraphicPen, LinesPen;<br />
         tmpPoint.x = 2;<br />
         LogPen.lopnStyle = PS_SOLID;<br />
         LogPen.lopnWidth = tmpPoint;<br />
         LogPen.lopnColor = 0x00000000;<br />
         GraphicPen = CreatePenIndirect(&LogPen);<br />
         for(int i = 0 ; i < iSize ; i++)<br />
         {<br />
            points[i].x = (ixClient * tempPoint[i].x)/400;<br />
            points[i].y = (int)(((iyClient * tempPoint[i].y)/450)-iLine)+iYConst;<br />
         }<br />
         hdc = BeginPaint(hwnd, &ps);<br />
         SelectObject(hdc, GraphicPen);<br />
         SetBkMode(hdc, TRANSPARENT);<br />
         TextOut(hdc, ixClient/2, iLine, TEXT("Olá"), sizeof("Olá"));<br />
         Polyline(hdc, points, (sizeof(points)/sizeof(POINT)));<br />
         //Eixo x-y<br />
         iXGraphLine = tempRect.right-80;<br />
         iYGraphLine = (tempRect.bottom-150)-iLine;<br />
         //Pen do eixo x-y<br />
         tmpPoint.x = 2;<br />
         LogPen.lopnStyle = PS_SOLID;<br />
         LogPen.lopnWidth = tmpPoint;<br />
         LogPen.lopnColor = 0x00FF0000;<br />
         LinesPen = CreatePenIndirect(&LogPen);<br />
         SelectObject(hdc, LinesPen);<br />
         iXSpace = iXGraphLine/(iSize*2);<br />
         iYSpace = iYGraphLine/(iSize*2);<br />
         for(int i = 0, iXpos = iXSpace, iYpos = iYSpace, iXFont = 10 ; i < iSize*2 ; i++)<br />
         {<br />
            SelectObject(hdc, LinesPen);<br />
            char cTemp10[5];<br />
            //Desenha as linhas divisórias do eixo X<br />
            MoveToEx(hdc, (iXpos-15), iYGraphLine-10-iLine, NULL);<br />
            LineTo(hdc, (iXpos-15), iYGraphLine+10-iLine);<br />
            itoa(iXpos, cTemp10, 10);<br />
            cTemp10[5]='\0';<br />
            /* Calcula a posição do texto de acordo com o tamanho entre *<br />
             * as divisões da linha horizontal e do tamanho do texto    */<br />
            SetTextAlign(hdc, TA_CENTER);<br />
            TextOut(hdc, iXpos-(((strlen(cTemp10)*iXCaps)+iXChar)/strlen(cTemp10))-2, iYGraphLine+10-iLine, cTemp10, strlen(cTemp10));<br />
            iXFont+=iXSpace/2;<br />
            iXpos+=iXSpace;<br />
            //Desenha as linhas divisórias do eixo Y<br />
            MoveToEx(hdc, 5, (iYpos-15)-iLine, NULL);<br />
            LineTo(hdc, 25, (iYpos-15)-iLine);<br />
            itoa(iYpos, cTemp10, 10);<br />
            TextOut(hdc, 40, (((iYSpace*((iSize*2)-i))-4)-(((strlen(cTemp10)*iXCaps)+iYChar)/strlen(cTemp10))-2)-iLine, cTemp10, strlen(cTemp10));<br />
            iYpos+=iYSpace;<br />
            SelectObject(hdc, GraphicPen);<br />
            SelectObject(hdc, CreateSolidBrush(0x00000000));<br />
            if(i < 5)Pie(hdc, points[i].x-4, points[i].y-4, points[i].x+4, points[i].y+4, 10,10,0,0);<br />
         }<br />
         SelectObject(hdc, LinesPen);<br />
         //Linha Vertical<br />
         MoveToEx(hdc, 15, -iLine, NULL);<br />
         LineTo(hdc, 15, iYGraphLine-iLine);<br />
         //Linha Horizontal<br />
         MoveToEx(hdc, 15, iYGraphLine-iLine, NULL);<br />
         LineTo(hdc, iXGraphLine, iYGraphLine-iLine);<br />
         rectBrush = CreateSolidBrush(0x00FFFFFF);<br />
         myRect.top    = (tempRect.bottom-100-iLine*2);<br />
         myRect.bottom = (tempRect.bottom-10-iLine*2);<br />
         myRect.left   = 50;<br />
         myRect.right  = 200;<br />
         FillRect(hdc, &myRect, rectBrush);<br />
         SelectObject(hdc, GraphicPen);<br />
         MoveToEx(hdc, 60, ((myRect.bottom+myRect.top)/2)-30, NULL);<br />
         LineTo(hdc,  130, ((myRect.bottom+myRect.top)/2)-30);<br />
         TextOut(hdc, 160, ((myRect.bottom+myRect.top)/2-30-(((strlen("Lalala")*iXCaps)+iYChar)/strlen("Lalala"))+2), "Lalala", strlen("Lalala"));<br />
         EndPaint(hwnd, &ps);<br />
         DeleteObject(GraphicPen);<br />
         DeleteObject(LinesPen);<br />
         DeleteObject(rectBrush);<br />
         ReleaseDC(hwnd, hdc);<br />
<code>

Re: What's the best way to do this?

Jun Du14-Jul-06 8:27

Re: What's the best way to do this?

14-Jul-06 8:27

Where can we help? The number of registers? Adjusting x- and y-axis? What do you mean "a big screen"?

Please specify where your problem is.

Best,
Jun

Alex Cutovoi14-Jul-06 8:55

Alex Cutovoi

14-Jul-06 8:55

Thanks for your help Jun Du. I need a help exactly for the things that you said. How can I adjust the x and y axis accroding with the number of registers When I said big screen I mean the user will have a big screen resolution to view all the registers, right?
Can you help again?

Re: What's the best way to do this?

Jun Du14-Jul-06 9:47

Difference between debug and execution on open file

14-Jul-06 9:47

Alex Cutovoi wrote:
How can I adjust the x and y axis accroding with the number of registers

I hope you know the possibly largest number of registers (grids?) in advance. Of course, you probably only draw the plot for actual number of available registers.

Alex Cutovoi wrote:
When I said big screen I mean the user will have a big screen resolution to view all the registers, right?

You should know what Customer (or yourself) wants. There are two drawing options:
1) The size of plot is fixed.
2) The size of plot is proportional to the number of registers.

Either way, whenever the number of registers changed, you have to erase the plot and redraw everthing. There is no way to just "adjust". Since you are using GDI to draw, I assume you know how to draw and redraw. To avoid blinking, you probably want to use double-buffering, meaning drawing to a memory DC and copy to the screen when necessary.

Best,
Jun

hli114-Jul-06 7:52

Re: Difference between debug and execution on open file

14-Jul-06 7:52

Hi,

For some reason, the path of the .ini file is asked not be specified. The .ini file is located in the same place with .exe file. I tried the functions fopen(strIniFileName,"r") and GetPrivateProfileString( ..,..,..,..,..,strIniFileName), where strIniFileName = ".\\myINI.ini". Both functions worked well in debug process, but failed in execution. I am confused.

I am using VC++ 6, and working on Windows XP.

Could someone please give me an assistance. Many thanks in advance. Confused | :confused:

hli

eusto14-Jul-06 8:12

eusto

14-Jul-06 8:12

Call GetCurrentDirectory to see where your app runs from and go from there.

Things like this happen when you start your app from a shortcut (with the Start In param missconfigured)

Re: Difference between debug and execution on open file

hli114-Jul-06 8:35

Re: Difference between debug and execution on open file

14-Jul-06 8:35

Good idea. I will try. Thank you very much. Smile | :)

hli

PJ Arends14-Jul-06 8:42

PJ Arends

14-Jul-06 8:42

Actually one wants to use GetModuleFileName() if the ini file is in the same folder as the exe.

You may be right
I may be crazy
-- Billy Joel --

Within you lies the power for good, use it!!!

Re: Difference between debug and execution on open file

hli114-Jul-06 9:02

Re: Difference between debug and execution on open file

14-Jul-06 9:02

You are right GetCurrentDirectory works from .exe file itself, but fails from shortcut. My application must be used remotely from shortcut. ??? Confused | :confused:

hli

hli114-Jul-06 9:33

Re: Difference between debug and execution on open file

14-Jul-06 9:33

Run app from shortcut, getCurrentDirectory returns C:\Documents and Settings. I guess that GetModuleFileName is the same. I will try. Confused | :confused:

hli

hli114-Jul-06 10:03