C / C++ / MFC

Re: Dynamic creation of EditBox problem

10-Jul-06 1:29

Hi all,

I have created a CEditBox dynamically, while i am entering some text it is accepting only with in the range of the CEditBox. i can't enter beyond the Range of the CEditBox.

But this is not with CEditBox of the ToolBar, because when we run the Application with CEditBox Choose statically from the ToolBar to CDialog. When you run the Application the CEditBox takes as many Charaters you want.

I used Set SetLimitText(...) to set the Length of the CEditControl but it is not taking, Please help me Out.

//==========================================================================
CEdit *ptr = new CEdit;
ptr->Create(WS_VISIBLE|WS_CHILD|WS_BORDER,CRect(point.x,point.y,point.x +100, point.y +20),this,NULL);

ptr->SetLimitText(100); //Not Working ---> it is not taking 100 Chars Why !
//==========================================================================

uday.

Naveen10-Jul-06 1:38

Naveen

10-Jul-06 1:38

just give ES_AUTOHSCROLL style too

CEdit *ptr = new CEdit;
ptr->Create(WS_VISIBLE|WS_CHILD|WS_BORDER|ES_AUTOHSCROLL ,CRect(point.x,point.y,point.x +100, point.y +20),this,NULL);

nave

Re: Dynamic creation of EditBox problem

Uday Janaswamy10-Jul-06 1:40

10-Jul-06 1:40

hi nave,

i got it very much thanks to you.

uday.

PlaySound Usage

Manjunath S10-Jul-06 1:18

Manjunath S

10-Jul-06 1:18

hi
i want to play .wav audio file using win32 api, and i am using following code.

#include<windows.h>
#include<mmsystem.h.>

int main()
{
PlaySound((LPCWSTR)"tada.wav", NULL, SND_FILENAME | SND_LOOP);
return 0;
}

the code compiles correctly. tada.wav is present in its exact location(code project). this code is not playing the file. it is returning 1.
one small beap comes and exits.

is the code correct?? if yes why it is not playing complete file.
if no, what is the exact method.

Manjunath S
GESL
Bangalore

RockyJames10-Jul-06 1:32

RockyJames

10-Jul-06 1:32

The sound specified by pszSound must fit into available physical memory and be playable by an installed waveform-audio device driver. PlaySound searches the following directories for sound files: the current directory; the Windows directory; the Windows system directory; directories listed in the PATH environment variable; and the list of directories mapped in a network. For more information about the directory search order, see the documentation for the OpenFile function.

If it cannot find the specified sound, PlaySound uses the default system event sound entry instead. If the function can find neither the system default entry nor the default sound, it makes no sound and returns FALSE

Naveen10-Jul-06 1:34

Naveen

10-Jul-06 1:34

Manjunath S wrote:
PlaySound((LPCWSTR)"tada.wav", NULL, SND_FILENAME | SND_LOOP);

try giving the full path..Also no need to typecast like this

just copy the file to c:\ and try executing the below code

PlaySound( _T("c:\\tada.wav"), NULL, SND_FILENAME | SND_LOOP);

nave

Manjunath S10-Jul-06 2:10

Manjunath S

10-Jul-06 2:10

hi

if i remove the typecast the following error will come:
error C2664: 'PlaySoundW' : cannot convert parameter 1 from 'const char [12]' to 'LPCWSTR'

If i use _T("c:\\tada.wav"): error C3861: '_T': identifier not found

The file tada.wav is present in current directory, c:\, c:\windows\media
If i give the full path, no change in output.
If i give some invalid filename say "afsdfasdf.wav", then also no change in output: one small beap comes.

Manjunath S
GESL
Bangalore

Ștefan-Mihai MOGA10-Jul-06 2:53

Ștefan-Mihai MOGA

10-Jul-06 2:53

I think you need to convert the string from ANSII to UNICODE. It should work this way Smile | :)

David Crow10-Jul-06 3:00

David Crow

10-Jul-06 3:00

Manjunath S wrote:
error C2664: 'PlaySoundW' : cannot convert parameter 1 from 'const char [12]' to 'LPCWSTR'

Precede the string literal with an L.

Manjunath S wrote:
If i use _T("c:\\tada.wav"): error C3861: '_T': identifier not found

Did you include <tchar.h>?

"The largest fire starts but with the smallest spark." - David Crow

"Judge not by the eye but by the heart." - Native American Proverb

Win32 application

Anu_Bala10-Jul-06 0:24

Anu_Bala

10-Jul-06 0:24

#include <afxwin.h>
class CExerciseApp : public CWinApp
{
public:
virtual BOOL InitInstance();
};
class CMainFrame : public CFrameWnd
{
public:
CMainFrame();
};
CMainFrame::CMainFrame()
{
Create(NULL, "MFC Fundamentals");
}
BOOL CExerciseApp::InitInstance()
{
m_pMainWnd = new CMainFrame;
m_pMainWnd->ShowWindow(SW_NORMAL);
return TRUE;
}
This is my basic Win32 application.Its shows unhandled ecxeption error.I set MFC as use MFC as shared DLL.i dnt know why the error occurs.Its mot console appliaion, it is win32 applcation.

RockyJames10-Jul-06 0:31

RockyJames

10-Jul-06 0:31

update the window......m_pMainWnd->UpdateWindow ();

ThatsAlok10-Jul-06 1:29

ThatsAlok

10-Jul-06 1:29

where is the object of CMainFrame!

Anu_Bala wrote:
BOOL CExerciseApp::InitInstance()
{
m_pMainWnd = new CMainFrame;
m_pMainWnd->ShowWindow(SW_NORMAL);
return TRUE;
}

this should be something like this
CMainFrame *MyPtr=new CMainFrame;
   MyPtr->ShowWindow(SW_NORMAL);
   m_pMainWnd=MyPtr;

"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow

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Alok Gupta
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David Crow10-Jul-06 3:09

David Crow

10-Jul-06 3:09

Anu_Bala wrote:
This is my basic Win32 application.

No, it's an MFC application that you've tried to create manually. Use AppWizard to create the application. You'll save yourself much time and grief.

"The largest fire starts but with the smallest spark." - David Crow

"Judge not by the eye but by the heart." - Native American Proverb

Basic Doubt in CMutex Class.

Zac Howland10-Jul-06 4:54

Zac Howland

10-Jul-06 4:54

Anu_Bala wrote:
CMainFrame::CMainFrame()
{
Create(NULL, "MFC Fundamentals");
}

Do not call Create from within the constructor. You will be trying to use objects that haven't been fully initialized yet. Instead, make your constructor empty and call Create in InitInstance:

#include "stdafx.h"

class CExerciseApp : public CWinApp
{
public:
	virtual BOOL InitInstance();
};

class CMainFrame : public CFrameWnd
{
public:
	CMainFrame();
};

CMainFrame::CMainFrame()
{
}

BOOL CExerciseApp::InitInstance()
{
	CMainFrame* pFrame = new CMainFrame;
	pFrame->Create(NULL, _T("My Non-AppWizard MFC App"));
	m_pMainWnd = pFrame;
	m_pMainWnd->ShowWindow(SW_NORMAL);
	return TRUE;
}

CExerciseApp theApp;

If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week

Zac

Uday Janaswamy10-Jul-06 0:23

Re: Basic Doubt in CMutex Class.

10-Jul-06 0:23

Hi All,

I have created a Mutex Object using

CreateMutex(...) Api, in One Machine and i want to Open the Mutex Handle what i have Created using

OpenMutex(...) Api, because Mutex Handle is Accessed across the Boundaries.

But I am not able to Open the CMutex Object what i have Created.

Please provide a Snippet of code to Open the CMutex Object from Different Machine.

uday.

Zac Howland10-Jul-06 4:56

Zac Howland

10-Jul-06 4:56

Mutex's are not designed for this behavior. If you want to synchronize information across network boundaries, you will have to come up with your own techniques (or google for some).

If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week

Zac

Re: Basic Doubt in CMutex Class.

Uday Janaswamy10-Jul-06 18:43