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Hi All,
Can anybody tell me what the meaning of this code snippet is?
<System.Diagnostics.DebuggerStepThrough()> Private Sub InitializeComponent()
In the above what this ‘<’ and ‘>’ indicates.
Thanks in advance.
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they specify the opening and closing declaration for an Attribute (in this case DebuggerStepThroughAttribute) which adornes the method.
Current blacklist
svmilky - Extremely rude | FeRtoll - Rude personal emails | ironstrike1 - Rude & Obnoxious behaviour
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It's a metatag. there are certian tags taht handle specifics about how a class compiles and integrates into the VS Environment. for instance
<catagory()>
before a public property causes the propety to show up in the forms designer properties window. that is evidence that VS is prebuilding certian parts of an object to facilitate its WYSIWYG interfaces (like to provide intellisense on new components, custo user controls etc.) the metadata tells the environment which parts to pre-compile in this case.
Web service methods use a similar tag to indicate that teh code gen should create an XML interface and description of the method so it can be enumerated to clients and called via soap.
Think of it as Code defining Code. that is what meta means in any sense. metadata is data about or describing data. gives me a headache myself...
hope that satisifies your curiosity,
Frank
hey...slang is the vernacular for the vernacular...wow
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Thank for giving such a good explanation. 
Regards,
Krishnaraj
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currency that can calculate with currency.
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WTF? How about writing a proper question that we can answer?
...Steve
1. quod erat demonstrandum
2. "Give a man a fish and you've fed him for a day. Teach him how to fish and you've fed him for life." I read that somewhere once
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Hi all,
In aspx file I have a Data grid. Of which two columns are Template columns. Both of these columns contain Label and Drop down list. On non-edit mode label will display the current information present in the DB. On clicking edit, it will change to Drop down list, giving option to make changes to that particular column value. Now list of items in the second template column drop down list must be populated on the basis of first column drop down box selection.
Eg: first column lists countries then on selecting particular country, second column must display states which belong to the selected country.
Also I have set the drop down list property AutoPostBack = True. So eah time when I change the country it sends it back o the server. But I am not getting any even handlers to handle the even triggered.
Can anybody help me out?
Thank in advance,
Regards,
Krishnaraj
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ASP is not my specialty so I can't address the edit-mode or the postback, but for the events, the short answer is to:
create a custom control that inheirts your first Template collumn.
add a public delegate and event within it. raise the custom event on the first templatecollumns changed event.
public delegate sub delIndexChanged(sender as object, e as system.eventargs)
public event evtIndexChanged as delIndexChanged
Private thing(sender as object, e as system.eventargs) handles me.selectedindexchanged
RaiseEvent me.evtIndexChanged(sender,e)
End sub
in your mainpage (the one with the grid), Replace the template col reference with one to your custom control.
once you instantiate the grid cols, add a handler for the evtIndexChanged that points to a sub with
AddHandler MyGrid.cols(idx).evtIndexChanged , AddressOf <subname>
where <subname> has the appropo parameter list for the delegate signature.
that will fire whenever the first col changes. I would use it to gen a filterstatement for a dataview.
to fire the col directly you can just RaiseEvent Object.Event(parameters...) I think. postbacks will complicate this.
I just read somthing about the asp2.0 callback model, and they claim there are now ways to update stuff on the UI (via server side processing) without posting back on the client. you may want to look into it but as I said web isnt my area of expertise.
Hope That Helps,
FrankyT
hey...slang is the vernacular for the vernacular...wow
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I have not tried the solution u have given. Coz most of the things u mentioned did not go into my mind. It may take some time to understand. But anyway thanks a lot for taking trouble to give me a solution.
Regards,
Krishnaraj
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I have installed Visual Studio 6.0.
While I am opening a VB project, it is displaying only the code behind; not the user interface. While double-clicking the form in the project window, it displays the message-<The instruction at "0x004581f1" referenced memory at "0x00000000".The memory could not be read.>
& as I am clicking ok,the project is closed.
Although, a new project can be created & run properly.
Kindly help...
Padma Gahlot
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Something is seriously wrong with either the project or the installation of VB6.
Are you sure the project was created in VB6?
Also from where did you install VB6 in the first place? Was it an original CD from Microsoft? Try uninstalling and then reinstalling (not a repair).
...Steve
1. quod erat demonstrandum
2. "Give a man a fish and you've fed him for a day. Teach him how to fish and you've fed him for life." I read that somewhere once
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I have 1 application and I want to count it one time a day by using Proces Control, If user have run it for 30days the application not possible to use and Process Control is maximame
Please anyone know give a code
................
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An easy way would be to write an installation date to the registry (or a hidden file somewhere on the hard drive) and then do a datediff function. If it returns < 30 then run regular code, if not, go to a form that shows how they can register. If you're going to do this tho, you should do some type of encryption of the date so your general user isn't changing the date every 30 days.
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Can u give one example?
................
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He just did.
...Steve
1. quod erat demonstrandum
2. "Give a man a fish and you've fed him for a day. Teach him how to fish and you've fed him for life." I read that somewhere once
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It should be from blue to red gradient color...
the backcolors of these rows return green gradient...
please help me revise the code...
thanks...
Protected Sub GridView1_DataBound(ByVal sender As Object, ByVal e As System.EventArgs) Handles GridView1.DataBound
Dim red As Integer = &HFF0000
Dim blue As Integer = &HFF
Dim green As Integer = &HFF00
Dim noRows As Integer
Dim incDiff As Integer
Dim currentColor As Integer
noRows = GridView1.Rows.Count
incDiff = (red / green) / noRows
currentColor = green
For x As Integer = 0 To noRows - 1
GridView1.Rows(x).BackColor = Color.FromArgb(currentColor)
currentColor += incDiff
Next
End Sub
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im' not really that good with VB.net but i dont see anything mentioning the color blue in that code. Maybe someone else knows what it is, but im not sure if that's it.
-Think not of the problem But of the solution!
-Mind what people do, not what they say, for deeds will betray an lie.
-The only sovereign you can allow to rule you is reason.
-Contradictions don't exist, in whole or in part.
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Why are you asking the same question again? Follow up in the thread that is already active instead.
---
b { font-weight: normal; }
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I used WebBrowser Contorl in my application when i run it the application run webbrowser to display page correctly, unfortunately the page that contain javascript, ... it alert message as normal.
How can i chnge title bar of alert message?
................
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Hi.... guys
I need a favor from you who have an experience in Overtime calculation, I want to build a program which could counting overtime for each employee in my company,
I need to know how to count the overtime which is over than two days as well , I mean if the overtime is start from 17:00 until 04:00 following days.
Thank you fro your attetnion and your support in advance.
Best regards
ICE
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Include the date in the data, then you can calculate the time difference without problem.
The difference between 2006-06-01 17:00 and 2006-06-02 04:00 is 11 hours or 660 minutes:
Dim start As DateTime = New DateTime(2006,6,1,17,0)
Dim finish As DateTime = New DateTime(2006,6,2,4,0)
Dim minutes As Integer = finish.Subtract(start).TotalMinutes
---
b { font-weight: normal; }
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Hi Guffa
Thank a lot for your advise and I have tried to write and run those command into a small program but it doesn't working well. I made Three Text box ( textbox1,textbox2 and textbox3), and here is the structure of my program
dim start as datetime
dim finish as datetime
dim minutes as integer
start=textbox1.text
finish =textbox2.text
minutes=finish.subtract(start).totalminutes
textbox3.text=minutes
I tried to run this program but it wont be runing propherly it just has 0 as the result came up on the textbox3
I am affraid that I have made a mistake, but I have no idea how to write the right logic program for this case. If you don't mind please let me get your next advise
Thank you
Best regards
ICE
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Despite the total disregard for data types, it looks like the code should work. What did you enter in the textboxes?
---
b { font-weight: normal; }
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Hi every body,
I'm workin on a vb.net 2003 ,and on an Access db.
I've the table :"CarParts" has these columns(PartNo,PartName,Price)
and I've a question I hope someone could help me to solve it.
I've a checkedlistbox,and I binded it to (PartName)column .
when I check an item I want it's name to be added to a textbox to save in a specivic column,and it's price to be added in another txtbox just to get the sum of all the checked items.then I would be able to save the whole selected items written in this textbox to save them in another column and I will be abel to save the sum of all the selected items in another column .
I did it by usuing the checkbox tool and it succeeded,according to the next code where i binded the Price column to one Label just to help me doing the sum,this label work even if i updated the prices:
if checkbox1.checked the <br />
bmb.position=0 <br />
sum += Val(Label 1 .text) <br />
textbox1.text & = " the 1st car part name" <br />
end if <br />
if checkbox2.checked the <br />
bmb.position=1<br />
sum += Val(Label 1 .text) <br />
textbox1.text & = " the 2nd car part name" <br />
end if <br />
.<br />
.<br />
.<br />
etc..<br />
Here is my CheckedListBox code it's just loading the (PartName)column data ,what Should I add to make it do the checklistbox job, pleeeeease help me:
Code:
Private Sub Button5_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button5.Click <br />
Dim strcon As String <br />
Try <br />
strcon = " provider=microsoft.jet.oledb.4.0;datasource=Cars.mdb " Dim con As New OleDbConnection(strcon) con.Open() <br />
Dim adapter As New OleDbDataAdapter("select * from CarParts", con) <br />
Dim cn As OleDbConnection = New OleDbConnection Dim dset1 As New DataSet <br />
Dim dt As New DataTableadapter.Fill(dt) CheckedListBox1.DataSource = dt CheckedListBox1.DisplayMember = "PartName" <br />
Catch ex As Exception <br />
MessageBox.Show(ex.Message) <br />
<br />
End Try <br />
End Sub
-- modified at 2:28 Friday 2nd June, 2006
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 I was given this code when I asked if anyone knew how to check if a user of my Visual Basic program is connected to the internet so that I can handle "Page cannot be displayed" errors, however I am a newbe to visual basic and this code does not make any sence to me, nor do I know how to use it...
Can someone explain what steps I would follow to impliment this code? For example, where do I put this code? How do I call the function?
Thanks.
Private Declare Function InternetGetConnectedState Lib "wininet.dll" (ByRef _
lpSFlags As Long, ByVal dwReserved As Long) As Long
Const INTERNET_CONNECTION_MODEM = 1
Const INTERNET_CONNECTION_LAN = 2
Const INTERNET_CONNECTION_PROXY = 4
Const INTERNET_CONNECTION_MODEM_BUSY = 8
' return True if there is an active Internect connection
'
' optionally returns the connection mode through
' its argument (see INTERNET_CONNECTION_* constants)
' 1=modem, 2=Lan, 4=proxy
' 8=modem busy with a non-internet connection
Function IsConnectedToInternet(Optional connectMode As Integer) As Boolean
Dim flags As Long
' this ASPI function does it all
IsConnectedToInternet = InternetGetConnectedState(flags, 0)
' return the flag through the optional argument
connectMode = flags
End Function
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