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Ricardo Mendes18-Apr-06 6:42
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QuestionDynamically loadning Menu Items Pin
sjpjs18-Apr-06 5:52
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AnswerRe: Dynamically loadning Menu Items Pin
Robert Rohde18-Apr-06 6:03
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GeneralRe: Dynamically loadning Menu Items Pin
sjpjs18-Apr-06 7:01
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AnswerRe: Dynamically loadning Menu Items Pin
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AnswerRe: Dynamically loadning Menu Items Pin
vatzcar18-Apr-06 18:17
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QuestionRe: Dynamically loadning Menu Items Pin
sjpjs18-Apr-06 23:09
sjpjs18-Apr-06 23:09 
Thank you vatzcar for your time and kind helpRose | [Rose] . After going through your code, I changed my strategy. Previously I was planning a show method in a class file (in DLL) will take the reference of the MDI form, after that it will show the menu form, in the DLL as child form. Now I am planning to standardise the main form name as frmMenu in all the DLL files. With this the code will be moved to the click event of the menu in the main application. The click event of the menu will call LoadDLL with corresponding assembly name.
private void LoadDLL(string assemblyName)
{
    Assembly assembly = Assembly.LoadFrom (assemblyName);
    // Walk through each type in the assembly
    foreach (Type type in assembly.GetTypes ())
    {
        if (type.IsClass == true)
        {
            object ibaseObject = null ;
            if (type.Name == "frmMenu")
            {
                ibaseObject = Activator.CreateInstance(type);
                Form frmT = (Form)ibaseObject;
                frmT.MdiParent = this;
                frmT.Show();
            }
        }
    } // for each
}



It is working fineBig Grin | :-D . Is it optimized code?


Thank you.
AnswerRe: Dynamically loadning Menu Items Pin
vatzcar19-Apr-06 0:26
vatzcar19-Apr-06 0:26 
QuestionWebservice Pin
dj_jay_smith18-Apr-06 4:48
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QuestionWebservice Pin
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Questionpassing array byval versus byref Pin
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