Database

DECLARE @PERIOD TABLE (start_time DATETIME, end_time DATETIME)

INSERT INTO @PERIOD(start_time)
SELECT t.start_time FROM (
  SELECT act_start_time_utc AS start_time, state_cd AS new_state, LAG(state_cd, 1) OVER (ORDER BY act_start_time_utc ASC) AS last_state
  FROM SRPMES901007.WWMESDB.dbo.job
  WHERE act_start_time_utc IS NOT NULL) AS t
WHERE t.new_state = 4 AND t.last_state <> 4

UPDATE period
SET end_time = (SELECT TOP(1) act_start_time_utc FROM SRPMES901007.WWMESDB.dbo.job WHERE state_cd <> 4 AND act_start_time_utc > period.start_time ORDER BY act_start_time_utc ASC)
FROM @PERIOD period 

SELECT * FROM @PERIOD ORDER BY start_time ASC

UPDATE @temp
SET formula_name = r.name, formula_version = r.version
FROM dbo.fn_GetFormulaForJob(wo_id, oper_id,seq_no) r

UPDATE T
SET formula_name = r.name, forumula_version = r.verion
FROM @TEMP As T
CROSS APPLY dbo.fn_GetFormulaForJob(T.wo_id, T.oper_id, T.seq_no) As r;

Member 14136263 wrote:

i used your app sqlite compare

Member 14136263 wrote:

Any idea ?

Always Encrypted (Database Engine) - SQL Server | Microsoft Docs[^]:

Always Encrypted allows clients to encrypt sensitive data inside client applications and never reveal the encryption keys to the Database Engine (SQL Database or SQL Server).
...
Decryption occurs via the client. This means that some actions that occur only server-side will not work when using Always Encrypted.