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GeneralRe: why the data been sent out after socket.close(), not socket.send(). Pin
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AnswerRe: why the data been sent out after socket.close(), not socket.send(). Pin
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QuestionProblem with string array? Pin
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AnswerRe: Problem with string array? Pin
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AnswerRe: Problem with string array? Pin
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GeneralRe: Problem with string array? Pin
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QuestionPredicateBuilder Question Pin
Kevin Marois30-Jun-23 8:54
professionalKevin Marois30-Jun-23 8:54 
AnswerRe: PredicateBuilder Question Pin
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James Curran5-Jul-23 10:41
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QuestionUnable to Receive data from Cobas e411 Serial Port Pin
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AnswerRe: Unable to Receive data from Cobas e411 Serial Port Pin
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AnswerRe: Unable to Receive data from Cobas e411 Serial Port Pin
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AnswerRe: Unable to Receive data from Cobas e411 Serial Port Pin
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AnswerRe: Unable to Receive data from Cobas e411 Serial Port Pin
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GeneralRe: Unable to Receive data from Cobas e411 Serial Port Pin
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AnswerRe: Unable to Receive data from Cobas e411 Serial Port Pin
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QuestionGoogle PeopleAPI & HttpListener Redirect URI Pin
Kevin Marois22-Jun-23 10:03
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AnswerRe: Google PeopleAPI & HttpListener Redirect URI Pin
jschell23-Jun-23 10:45
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GeneralRe: Google PeopleAPI & HttpListener Redirect URI Pin
Kevin Marois23-Jun-23 12:18
professionalKevin Marois23-Jun-23 12:18 
GeneralRe: Google PeopleAPI & HttpListener Redirect URI Pin
Richard Andrew x6425-Jun-23 11:44
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GeneralRe: Google PeopleAPI & HttpListener Redirect URI Pin
Kevin Marois25-Jun-23 17:41
professionalKevin Marois25-Jun-23 17:41 
GeneralRe: Google PeopleAPI & HttpListener Redirect URI Pin
jschell26-Jun-23 5:31
jschell26-Jun-23 5:31 
Kevin Marois wrote:
The port needs to be random at runtime


Then you will need to put in in the URL.

As I noted the URL allows for a port in it. So you can indeed put it in there.

But that means you will need to fly the server every time. No idea what that will do to your security model. Certainly won't work without a range since some ports are required and some are considered high security risks (even when something else it attached.)

And for some reason that it will not accept a perfectly valid URL with a port then you are done. Your solution will not work.

Summarizing above.
1. You say the server port must be random.
2. You must include the port in the URL
3. Either 1 is false, or 2 must be true or your solution will not work
GeneralRe: Google PeopleAPI & HttpListener Redirect URI Pin
Kevin Marois26-Jun-23 8:20
professionalKevin Marois26-Jun-23 8:20 

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