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What have you tried?
Where are you stuck?
What help do you need?
"I have no idea what I did, but I'm taking full credit for it." - ThisOldTony
"Common sense is so rare these days, it should be classified as a super power" - Random T-shirt
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I dont know how to convert this equation into c#. i cant understand this per in the type Ρ(y,x) = (y per x)*(80-y per 20-x)/ (80 per 20) is. what per means.
I havent try anything since i cant udnerstand it. i already said where i am stuck and what help i need
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Well, where did you get the equation from? They will probably define y per x for you. Did you look?
"I have no idea what I did, but I'm taking full credit for it." - ThisOldTony
"Common sense is so rare these days, it should be classified as a super power" - Random T-shirt
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No, that's a mess of pixels with no meaning to anybody...
And as for the Greek, either look for an English language description or use Google Translate.
Did you try Wikipedia: Hypergeometric distribution - Wikipedia[^] ?
"I have no idea what I did, but I'm taking full credit for it." - ThisOldTony
"Common sense is so rare these days, it should be classified as a super power" - Random T-shirt
AntiTwitter: @DalekDave is now a follower!
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Yes i tried all that, here is exactly what i want Kino Statistics Mathematical Analysis[^]
I want this equation in c#. i show online some c# codes for Hypergeometric distribution but they dont give probability and are very complex
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I think i have managed to convert it to a simpler equation: what i want is this to c# now:
(n!/(k!*(n-k)!)*(80-n)!/((20-k)!*((80-n)-(20-k))!))/(80!/(20!*(80-20)!))
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So what's the problem? that link leads you through the process of getting a probability from the inputs, so what have you tried to implement it?
Where are you stuck?
What help do you need? (Other than "somebody else to do all the work for me" which isn't the idea of this site at all.)
"I have no idea what I did, but I'm taking full credit for it." - ThisOldTony
"Common sense is so rare these days, it should be classified as a super power" - Random T-shirt
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I think i was pretty clear to what i want. I dont know how a equation is being translated to c#. If this to you is translated "to someone else do the work for me" then i cant do anyhting about that, just skip this topin, you dont HAVE to answer something. asking the same question again and again how it helps?
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Yeah, it's pretty clear: you want someone else to do the work for you.
I'm trying to avoid the derision that can attract to you by getting you to think about your task and actually try to do the work yourself, or at least try. But so far, you've shown no sign at all of trying to implement anything yourself!
We are more than willing to help those that are stuck: but that doesn't mean that we are here to do it all for you! We can't do all the work, you are either getting paid for this, or it's part of your grades and it wouldn't be at all fair for us to do it all for you. Plus, if we just "hand you the solution" you don't learn anything useful from that, and the next time you have to do a similar task you have to ask again, and again, and again ... people learn by doing, not by looking at results!
So we need you to do the work, and we will help you when you get stuck. That doesn't mean we will give you a step by step solution you can hand in!
Start by explaining where you are at the moment, and what the next step in the process is. Then tell us what you have tried to get that next step working, and what happened when you did.
"I have no idea what I did, but I'm taking full credit for it." - ThisOldTony
"Common sense is so rare these days, it should be classified as a super power" - Random T-shirt
AntiTwitter: @DalekDave is now a follower!
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we dont have to do this converstation. i dont want you to solve anything for me or toexplain what solving for me means.
Lets take it from the beginning
Facts: nobody wants to do the work for the other
Problem: how to convert equation to c#
With those facts in this problem where someone starts? as i pointed already in a previous post i try to convert this equation to maths (n!/(k!*(n-k)!)*(80-n)!/((20-k)!*((80-n)-(20-k))!))/(80!/(20!*(80-20)!))
and you said it is pretty clear i want you to do the work for me.. you are obvious wrong but lets not discuss that either if you still want to think im trying to find someone to do my the job.. great. (you should REALLY check what you think is pretty clear since you are posting very often here, my messages didnt at all show what you are saying, i have share many and many informations)
Now to the point: i used this tool (as i methioned already in the previous posts) Converting math equations to C#[^] and it has create some Factorial() procedures, c# cant recognise them, those exist in a library or something
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That's because C# doesn't contain a factorial function - but it's trivial to create one yourself, it's one of the first exercise beginners are often given. Recursive or iterative, it's simple either way:
private static int FactorialRecursive(int x)
{
return (x > 1 ? x * FactorialRecursive(x - 1) : 1);
}
private static int FactorialIterative(int x)
{
int f = 1;
while (x > 1)
{
f *= x--;
}
return f;
}
So why couldn't you just write those? Or google for them?
"I have no idea what I did, but I'm taking full credit for it." - ThisOldTony
"Common sense is so rare these days, it should be classified as a super power" - Random T-shirt
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Because maybe im missing something and this function exists. I dont prefer always solving anything by my own because im not sure if it the best approach. Thanks, i think ive got it from here.
I will post again here only if i have code to post since i see that if i dont have code people here believe that i intentionally dont have code and i dont those negative situations.
Thanks
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I'm curious what your code will look like; you are in for a couple of surprises when you discover the difference between theory and practice...
Luc Pattyn [My Articles]
If you can't find it on YouTube try TikTok...
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Right now im at this:
private int CalculateProbabilityOfDrawNumbersFromAllNumbers(int drawNumbers, int allNumbers)
{
return ((Factorial(allNumbers) * Factorial(80 - allNumbers)) / (((Factorial(80) * ((Factorial(drawNumbers) * Factorial(allNumbers - drawNumbers)) * (Factorial(20 - drawNumbers) * Factorial(((80 - allNumbers) - (20 - drawNumbers)))))) / (Factorial(20) * Factorial(80 - 20)))));
}
private static int Factorial(int x)
{
int f = 1;
while (x > 1)
{
f *= x--;
}
return f;
}
which gives division by zero and i try to understand if something have gone wrong with all those parenthesis
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investigate and learn!
Luc Pattyn [My Articles]
If you can't find it on YouTube try TikTok...
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thats what i said first!!!
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Small hint: 80! is a number of about 120 decimal digits. An int can hold numbers up to roughly 9 digits.
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that wasnt a hint!!! it appears to be the solution cause now this works
using System.IO;
using System;
class Program
{
static void Main()
{
Console.WriteLine(CalculateProbabilityOfDrawNumbersFromAllNumbers(1,1));
}
private static double CalculateProbabilityOfDrawNumbersFromAllNumbers(double drawNumbers, double allNumbers)
{
return Factorial(allNumbers) / (Factorial(drawNumbers) * Factorial(allNumbers - drawNumbers)) * (Factorial(80 - allNumbers) / (Factorial(20 - drawNumbers) * Factorial(80 - allNumbers - (20 - drawNumbers)))) / (Factorial(80) / (Factorial(20) * Factorial(80 - 20)));
}
private static double Factorial(double x)
{
double f = 1;
while (x > 1)
{
f *= x--;
}
return f;
}
}
im not sure why i was getting division by zero error. the int has surpass its largest number and return 0?
i will use this crazy code to display it as a percentage without any unnecessary zeros in the end
Console.WriteLine((CalculateProbabilityOfDrawNumbersFromAllNumbers(12,12) * 100).ToString("F7").TrimEnd(new Char[] { '0' } ).TrimEnd(new Char[] { '.' } )+"%");
modified 23-Aug-20 20:04pm.
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Quote: im not sure why i was getting division by zero error. the int has surpass its largest number and return 0?
Don't just let that go, think, think until you figured it out!
Luc Pattyn [My Articles]
If you can't find it on YouTube try TikTok...
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im 99,99 percent sure that on overflow int will return 0 or -1 :P so this should be the issue
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It depends what it overflows from. For example if you add 1 to 2147483647 you will get -2147483648.
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Wow it really works as the counters we have in cars that counts kilometers? They start all over again from the beginning, only for integers we also have negative ones
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Exoskeletor wrote: Wow it really works as the counters we have in cars that counts kilometers?
Ehr.. no.
Just look up how a PC stores numbers in binary, and the limitations of each number-"type".
Bastard Programmer from Hell 
"If you just follow the bacon Eddy, wherever it leads you, then you won't have to think about politics." -- Some Bell.
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There was a time i new all those things in university but years have passed since, ok i have look them up
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