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right. But I don't want to have to convert the stings to ints every time as i'm using around 15 for each calculation and doing what you suggested would make the code sort of confusing.
I think it can be done using operator overloading so that the developer can add two strings simply by writing
string3=string1+string2
Anyone with some other solution?
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public static string operator + ( string s1, string s2 )
{
return (Int32.Parse(s1) + Int32.Parse(s2)).ToString();
}
I'm not an expert yet, but I play one at work. Yeah and here too.
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Your solution
Ista wrote:
public static string operator + ( string s1, string s2 )
{
return (Int32.Parse(s1) + Int32.Parse(s2)).ToString();
}
doesn't work...I've had already tried it. The compiler generates an error: One of the parameters of a binary operator must be a containing type". So the + operator can't be overloaded in this way.
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This is the class
public class Class1
{
public string s;
public Class1()
{
//
// TODO: Add constructor logic here
//
}
public Class1( string stype )
{
s = stype;
}
public override string ToString()
{
return s;
}
public static string operator + ( Class1 s1, Class1 s2 )
{
string s1s = s1.ToString();
string s2s = s2.ToString();
return (Int32.Parse(s1s) + Int32.Parse(s2s)).ToString();
}
}
in your form type
private void button1_Click(object sender, System.EventArgs e)
{
Class1 c = new Class1("12");
Class1 c1 = new Class1("20");
string s = c + c1;
MessageBox.Show(s);
}
its rough but works
I'm not an expert yet, but I play one at work. Yeah and here too.
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Just want to point something out: Can you imagine the maintainance nightmare that would result from doing what you propose? If you read
string3 = string1 + string2;
in your code 6 or 12 months from now, would you know whether it meant "concatenate" or "treat the strings as numbers and add"? Would your replacement?
What I'm saying is that although the language might allow you to do what you want, do you really want to do it? It's great writing software that's only used once, to prove a point, as it were, but the reality of our game is that we generally have to write code that we'll have to maintain down the road (and if not us, then someone else). In that case, the simpler you express the intent of your program in code, the simpler it is to test and maintain, and the easier it is to go home at 5 o'clock.
My recommendation is to create a small class that encapsulates what you want to do. Override the + operator (and the += operator, and the - operator and the -= operator) to your heart's content at that point. It won't be as confusing as "sometimes in my code the + operator on strings means this, other times it means that".
Cheers, Julian
Program Manager, C#
This posting is provided "AS IS" with no warranties, and confers no rights.
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Hmm...I believe you're right about the maintinence...overloading would cause a lot of confusion so I guess I'll just use my Add & Sub functions.
However you've mentioned that "although the language might allow you to do what you want, do you really want to do it?"
and I'm curious how does the languge allow me to do what I want i.e how does it allow me to overload +, - operators etc. for primitive datatypes like int and sting.
Hasan
P.S. The part about going home at 5 went straight to my heart 
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P.S. The part about going home at 5 went straight to my heart
nice said
Muhammad Sarfraz
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The fact of the matter is, that unless you write your own CLR, you'll have to convert to numbers (Int32, Int64, whatever) even if you create your own class and overload the + operator - there is no way around it. All you'll be doing then, however, is making it look like you're not - it's still happening under the covers.
Using the Add(string, string) method you mentioned earlier is the best way - always modularize your code. This will allow you to use a simple, short statement to add the numeric values of the strings and will allow you to optimize the algorithm once in the future as opposed to finding all lines where you do this and change them. I recommend using a static method too, so you don't have to worry about instantiating some class just to add a couple of strings values.
-----BEGIN GEEK CODE BLOCK-----
Version: 3.21
GCS/G/MU d- s: a- C++++ UL@ P++(+++) L+(--) E--- W+++ N++ o+ K? w++++ O- M(+) V? PS-- PE Y++ PGP++ t++@ 5 X+++ R+@ tv+ b(-)>b++ DI++++ D+ G e++>+++ h---* r+++ y+++
-----END GEEK CODE BLOCK-----
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I'm curious. Assuming you could overload this operator, what would you do with the following code:
string1 = "12";
string2 = "10";
string3 = "abc";
string3 = string1 + string2 + string3;
Would you want this to be "22abc" or "1210abc"?
There's a good reason not to do this - it's confusing for developers maintaining your code. Personally, I think you should either create a new class and overload or you should just continue using the Add() method.
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I've decided to continue using my Add() method.
However your point about the "abc" string; since I would be converting the string to an int in my overloaded method, I'd get an error in case "abc" were used; so to avoid this I'd check that the user only enters numeric data.
that out of the way, I'd still like to know how to overload + for string or int. (just curios).
thanks....hasan
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Imagine if someone developed a language where any variable could be of any value type - now that would be just silly, but at least your scenario would work 
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actually it would equal zero but god if I was maintaining that could I would be throwing punches I mean really int32.Parse() is very short to right
I'm not an expert yet, but I play one at work. Yeah and here too.
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I need the ability to get/set permission attributes, such
as the ones you get when you right click
Properties/Security tab for a given file or dir in file manager...
How can this be done programmatically in .NET...???
thanks,
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int binToHex1=(0*2^3)+(1*2^2)+(0*2^1)+(1*2^0);
Howcome that won't evaluate the 5, the right answer... it always comes out to 6!?!
/\ |_ E X E GG
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That is because in C# ^ is not the exponentiation operator. It computes the bitwise exclusive-OR of its operands. Try this:
double binToHex=(0*Math.Pow(2,3))+(1*Math.Pow(2,2))+(0*Math.Pow(2,1))+(1*Math.Pow(2,0));
The result will be binToHex=5
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Thanks alot.
/\ |_ E X E GG
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passed 
"When the only tool you have is a hammer, a sore thumb you will have."
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Hello,
Is there an easy way to Enable the selection on the form?
I would like to allow selection on the form, e.g. when I mouseDown and move, there a rectangle dot frame displayed and resizing according to my mouse movement.
Or, I need to do my own code?
could anybody provide some for me, Thank you!!
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the man hands you a pencil and it magically writes. Did that trick work well in school?
I'm not an expert yet, but I play one at work. Yeah and here too.
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I want to display the bitmap of an active form, in a MDI app, in a picture box. The picture box control is on the MDI form, whenever user changes the current active form, the picture box control should show the picture of the active form. I want to know how do I get the picture of the active form.
One method I can think of is:
1. Get the Graphics object of the active form
2. Get the HDC from the graphics object
3. Create a blank bitmap of the same size as the size of the form.
3. Use Win32 function BitBlt and copy the pixel data from the form's hdc to the bitmap's hdc. Save the bitmap to a file and show the file in the picture box.
Is there any other (simpler) way to do this?
Thanks
suhas
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i did it that way above. I really dont know of a easyier way to do it though, either way its easy to do it above. the codeproject has a class that someone wrote that has all the api work done for your.
Jesse M
The Code Project Is Your Friend...
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Thanks for the response.
How do I get the class that has all the API work done.
Thanks
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Dundas Software is now hiring more .Net developers to work on an upcoming data visualization product.
If you take pride in the quality of your work and want to work with others who are not satisfied with second best, then Dundas may be the place for you.
Plus .... you get the satisfaction of walking by the CodeProject Server Room every day, as you head to the development department!!!
Click Here for more details.
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Hiya
1. How do I make the last line in the list view show and be visiable every time a new entry is input into the list view.( you know when the amount of lines entered is greater than visiable line space on screen )
2. How do I go to a specific line in the list view??
Thanks.
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