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string source = "1,2,3,4";
string[] parts = source.Split(',');
Array.Sort(parts);
string result = string.Join(",", parts);
NB: This will sort using string comparison. That means that the string "9" will come after the string "10". If that's not what you want, then you'll need to expand your specification.
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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Try this:
string reversedString = new string("4,3,2,1".Reverse().ToArray());Note that this just literally reverses the order of the characters; it doesn't really "sort" in the technical sense of that word.
Google CEO, Erich Schmidt: "I keep asking for a product called Serendipity. This product would have access to everything ever written or recorded, know everything the user ever worked on and saved to his or her personal hard drive, and know a whole lot about the user's tastes, friends and predilections." 2004, USA Today interview
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Just what i needed. Thank you.
If you don't mind me asking, how did you learn about this way to solve the problem? How long did it take you to figure out?
Instead of creating a new variable, i tried to reverse the existing variable, and put into a ViewState variable. That did not work. so, i went to what you have written, which works!!
of the form:
ViewState["questionumber"] = myquestionumber.Reverse().ToArray();
How did you know we have to create a new variable to do this? The fact we are treating it as new string?
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vkEE wrote: How did you know we have to create a new variable to do this? The fact we are treating it as new string?
Funny question actually. My personal evolution in this, is that I started out using new variables and copies for everything. As we tend to divide a problem in smaller problems, transforming data (eg sorting a string) or other problems result in the creation of new variables to keep track of things (solutions to each smaller problem).
The more experience you gain through the years, the more compact I would start to develop, creating less and less variables.
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LINQ - var sorted = new List<int>(str.Split(',').Select(s => int.Parse(s))).OrderBy(x=>x);
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Anyone help me how can i handle multiple sensors fitted in chairs in auditorium that sends data that these chairs are busy or not ................................pls help ASAP 
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Please supply more information:
What type of sensor?
What type of interface?
=========================================================
I'm an optoholic - my glass is always half full of vodka.
=========================================================
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The first thing you need to do is look at the interface provided by the sensor, and how it communicates with a computer. It's most unlikely that this would be via a COM port.
Veni, vidi, abiit domum
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DateTime[] start = new DateTime[] { new DateTime(1990, 1, 1), new DateTime(1995, 1, 1), new DateTime(1995, 1, 1),new DateTime(2003, 1, 1) };
DateTime[] end = new DateTime[] { new DateTime(2000, 1, 1), new DateTime(2005, 1, 1), new DateTime(2005, 1, 1), new DateTime(2007, 1, 1)};
i cannot explain what i what to do in earlier question so i have array that contain start days and another array contain end day. and i should calculate lenght of days i dont need calculate overlap days
|-------------------|
|-----------------------|
|-----------------------|
|---------------------|
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You can do this very easily using LINQ and TimeSpan.
First, get the minimum DateTime from the array(Min()).
Then get the maxumim DateTime from the array (Max()).
Using TimeSpan get the difference.
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sorry but i did not understand you
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Something like
accepted
If you want to find the earliest or latest Date:
DateTime earliest = arr.Min(record => record.Date);
DateTime latest = arr.Max(record => record.Date);
TimeSpan examples to calculate datetime difference - http://www.dotnetperls.com/timespan[^].
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Try this:
List<TimeSpan> dateIntervals = endDates.Select((eDate, ndx) => eDate - startDates[ndx]).ToList(); The Linq 'Select function overload that supplies an index is available as of .NET FrameWork 3.5.
Google CEO, Erich Schmidt: "I keep asking for a product called Serendipity. This product would have access to everything ever written or recorded, know everything the user ever worked on and saved to his or her personal hard drive, and know a whole lot about the user's tastes, friends and predilections." 2004, USA Today interview
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Try this:
for (int i = start.Length - 2; i > -1; --i)
{
if (start[i+1] >= start[i] && start[i+1] <= end[i])
{
start[i + 1] = end[i];
}
}
for (int i = 0; i < start.Length; ++i)
{
timespan = end[i] - start[i];
timeDifference += timespan.Days;
}
Veni, vidi, abiit domum
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yes but it is not remove overlap for the next time i mean for this one it is good |-----------|
|-------------|
but here |--------1-----|
}-----------2---------|
}==========3==========} here it should not add 3 because value od 3 contains in 2 one
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I tried my suggested code with your original data and it produced the correct answer.
Veni, vidi, abiit domum
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how can make the telerik radTreeListView only allow selection of items under the same rootItem/ParentItem?
UK
-london
-london 1
-london --
-london 100
-Newcastle
-Newcastle 1
-Newcastle 2
-Newcastle 3
-liverpool
USA
-New york
-califonia
China
-one
-two
From above sample menu of a radTreeListView, user should be allowed to select only
UK, USA or China. OR London, Newcastle, Liverpool, OR Newcastle 1, Newcastle 2, Newcastle 3 BUT NOT Newcastle 1, London 1, UK ALSO NOT UK, Newcastle, Newcastle 1.
User should only select things/items at the same hierarchy. Basically, they should not select a parent and a child, THEY either select from parents or children or sub-children.
This is the control am using : http://www.telerik.com/help/silverlight/radtreelistview-overview.html
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Presumably you have a TreeNode object that you stuff your objects into (you are displaying Country and City here). I would put a Nodelevel property on the TreeNode object and manage your SelectedItems collection using that property.
We use the HeirarchyID concept in our TreeNode that automatically knows it's level.
Take a read through some of Mr Smiths articles[^] I have quite a few bits of his code in my apps.
Never underestimate the power of human stupidity
RAH
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Hi Mycroft,
I use a TreeView (the excellent IntegralUI TreeView from Lidor Systems) that also has a "Level" property for every Node; it's very useful.
However, in this case, knowing the Level would not be adequate to determine which are "acceptable" selected nodes: "-california" and "-liverpool," for example, are at the same level; while that may have some "historic poetic truth" in terms of the music scene  ... that would not work for the OP.
Bill
Google CEO, Erich Schmidt: "I keep asking for a product called Serendipity. This product would have access to everything ever written or recorded, know everything the user ever worked on and saved to his or her personal hard drive, and know a whole lot about the user's tastes, friends and predilections." 2004, USA Today interview
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Ok now I see where you are coming from, however I would bet the OP (coming from Uganda) may have considered california a city rather than a state. Certainly I did not pick it up until you pointed it out 
Never underestimate the power of human stupidity
RAH
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I don't use the Telerik Treeview (I use one from Lidor Systems), so I don't know exactly what special features ... compared to any other Control ... it offers, or the exact syntax of Events it exposes, but this is pretty simple to do.
The Microsoft TreeView does not, of course, offer multiple selection, but the following code for the MS TreeView will demonstrate a general solution:
TreeNode firstSelectedNode;
TreeNode firstSelectedNodeParent;
private void treeView1_BeforeSelect(object sender, TreeViewCancelEventArgs e)
{
if (firstSelectedNode == null)
{
firstSelectedNode = e.Node;
firstSelectedNodeParent = firstSelectedNode.Parent;
}
else
{
if (e.Node.Parent != firstSelectedNodeParent) e.Cancel = true;
}
}
This code will confine selection to the sibling nodes of the first selected TreeNode. Obviously, in real-world use, you will need to reset the variable 'firstSelectedNode to null after you have "handled" the current selection.
Google CEO, Erich Schmidt: "I keep asking for a product called Serendipity. This product would have access to everything ever written or recorded, know everything the user ever worked on and saved to his or her personal hard drive, and know a whole lot about the user's tastes, friends and predilections." 2004, USA Today interview
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using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace WindowsFormsApplication7
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
DateTime[] start = new DateTime[] { new DateTime(2000, 1, 1), new DateTime(2004, 1, 1),
new DateTime(2004, 1, 1), new DateTime(2008, 1, 1) };
DateTime[] end = new DateTime[] { new DateTime(2002, 1, 1), new DateTime(2006, 1, 1),
new DateTime(2006, 1, 1), new DateTime(2010, 1, 1) };
int timeDifference = 0;
TimeSpan timespan;
private void button1_Click(object sender, EventArgs e)
{
for (int i=0; i<end.Length-2; i++)
{
if (end[i] < end[i + 1] && start[i] <start[i +="" 1]="" &&="" start[i="" 1]<="end[i])
" {
="" timespan="(end[i]" -="" start[i])="" (end[i="" end[i]);
="" }
="" if="" (end[i]="">= end[i + 1] && start[i] <= start[i + 1])
{
timespan = (end[i] - start[i]);
}
if (end[i] > end[i + 1] && start[i] > start[i + 1] && start[i] <= end[i + 1])
{
timespan = (end[i] - start[i]) + (end[i + 1] - end[i]);
}
if (end[i] <= end[i + 1] && start[i] >= start[i + 1])
{ timespan = (end[i + 1] - start[i + 1]);
}
timeDifference = timespan.Days + timeDifference;
}
MessageBox.Show(timeDifference.ToString());
}
}
}
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What is the question?
Veni, vidi, abiit domum
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i should find the length of days in the array but in my code |--- Date 1 ---|
|--- Date 2 ---| dont calculate in right way
|--- Date 1 ---|
| --- Date 2 --- |
| --- Date 1 --- |
| --- Date 2 ---- |
| -------- Date 1 -------- |
| --- Date 2 --- |
| --- Date 1 --- |
| -------- Date 2 -------- |
|--- Date 1 ---|
|--- Date 2 ---|
| --- Date 2 --- |
| --- Date 1 ----|
| --- Date 1 --- |
| -------- Date 2 -------- |
| --- Date 1 --- |
| --- Date 2 --- |
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i should find the length of days in the array but in my code |--- Date 1 ---|
|--- Date 2 ---| dont calculate in right way
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