C# Discussion Boards - CodeProject

Re: Pop a Context Menu Anywhere on Screen???

12-Mar-09 3:24

Have you looked?

[hem hem http://msdn.microsoft.com/en-us/library/system.windows.forms.contextmenu.popup(VS.71).aspx[^]]

Panic, Chaos, Destruction.
My work here is done.

Xmen Real 12-Mar-09 3:52

Xmen Real

12-Mar-09 3:52

Use Show() of CMS

eg

contextMenuStrip1.Show();
contextMenuStrip1.Show(x, y);
contextMenuStrip1.Show(textbox, x, y);

TVMU^P[[IGIOQHG^JSH`A#@`RFJ\c^JPL>;"[,*/|+&WLEZGc`AFXc!L
%^]*IRXD#@GKCQ`R\^SF_WcHbORY87֦ʻ6ϣN8ȤBcRAV\Z^&SU~%CSWQ@#2
W_AD`EPABIKRDFVS)EVLQK)JKSQXUFYK[M`UKs*$GwU#(QDXBER@CBN%
Rs0~53%eYrd8mt^7Z6]iTF+(EWfJ9zaK-iTV.C\y<pjxsg-b$f4ia>
--------------------------------------------------------
128 bit encrypted signature, crack if you can

Re: Pop a Context Menu Anywhere on Screen???

User 238229212-Mar-09 19:17

User 2382292

12-Mar-09 19:17

Doh!, Thanks guys! Smile | :)

KitKat - A Very Simple Pseudo-RootKit (unedited)
SpyNet - An Application Specific Keylogger(unedited)
Shove - Shell Shoveler (like NetCat) (unedited)
GzTx - Compress and Transfer Files (unedited)

modified 20-Oct-19 21:02pm.

Moving a panel between a picturebox

Deabdy2112-Mar-09 3:19

Deabdy21

12-Mar-09 3:19

I have a picturebox on the screen. I also have a panel with some information on the panel.
I can move/drag the panel over the screen. But I want that the panel only moves between the borders
of the picturebox. I don't now how to do this?

Can anyone help me to solve this problem?

Nagy Vilmos12-Mar-09 3:22

12-Mar-09 3:22

As the panel 'moves' check in the event handler that it is in the correct area.
Have a go, if it doesn't work then post a code snippet.

Code helps. Nearly as well as gin.

Panic, Chaos, Destruction.
My work here is done.

Deabdy2112-Mar-09 3:44

Deabdy21

12-Mar-09 3:44

thanks

Xmen Real 12-Mar-09 3:58

Xmen Real

12-Mar-09 3:58

well, its easy...

if (pictureBox1.ClientRectangle.Contains(x, y))
{
// move the panel
}

Luc Pattyn12-Mar-09 4:40

Luc Pattyn

12-Mar-09 4:40

Xmen wrote:
if (pictureBox1.ClientRectangle.Contains(x, y))

It is not sufficient to keep the cursor position inside the PictureBox, that way the Panel can still stick out on any of 4 sides.

One needs to check PictureBox.Bounds.Contains(Z) where Z is either the new Panel.Bounds
or the new Location of two Points (e.g. topleft and bottomright).

Smile | :)

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Member 349379912-Mar-09 2:37

12-Mar-09 2:37

Below is my code to add a chat message to a multiline text box.

I have tested the parameters, when I run them on messagebox's they output the proper value, but
when I combine them:

"chatView.Text = chatView.Text + Environment.NewLine + myName + ": "+ myText;"

Only "myName" shows up on each line.

What am i doing wrong?

public delegate void chatMessageCallBack(string myName, string myText);
        private void chatMessage(string myName, string myText)
        {
            chatView.Text = chatView.Text + Environment.NewLine + myName + ": "+ myText;
        }
        private void addChatMessage(string myName, string myText)
        {
            if (chatView.InvokeRequired)
            {
                chatMessageCallBack d = new chatMessageCallBack(chatMessage);
                Invoke(d, new object[] { myName, myText });
            }
            else
            {
                chatView.Text = chatView.Text + Environment.NewLine + myName + ": " + myText;
            }
        }

musefan12-Mar-09 2:54

musefan

12-Mar-09 2:54

well if your getting the myName part, i would have to say that your myText value is null or empty.

Try putting in a MessageBox in your chatMessage function and output the two values to make sure they contain the data you expect.

I assume you are getting the ": " along with myName?

Member 3493799 wrote:
I have tested the parameters, when I run them on messagebox's they output the proper value, but
when I combine them:

my bad, i missed that line

Life goes very fast. Tomorrow, today is already yesterday.

musefan12-Mar-09 3:09

musefan

12-Mar-09 3:09

very strange,

try replacing the environment.newline with something else to see if the text shows

Life goes very fast. Tomorrow, today is already yesterday.

Member 349379912-Mar-09 3:11

12-Mar-09 3:11

I know!

Nothing works in combination.

Heck, even when I remove the newline stuff and just have myName + myText, it only shows myName...

weirdest thing ever..

musefan12-Mar-09 3:13

musefan

12-Mar-09 3:13

what about just textBox.Text = myText;?

Life goes very fast. Tomorrow, today is already yesterday.

Luc Pattyn12-Mar-09 3:12

Luc Pattyn

12-Mar-09 3:12

Member 3493799 wrote:
Invoke(d, new object[] { myName, myText });

IMO should be chatView.Invoke(...)

Smile | :)

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Member 349379912-Mar-09 3:20

12-Mar-09 3:20

Tried it, didnt work Frown | :(

Heres the packet decoding scheme:

myName = dataSender
myText = dataMessage

[StructLayout(LayoutKind.Sequential, Pack = 1)]
                public struct rawCncPacket
                {
                    // IP
                    public byte IPVerLen;
                    public byte IPTOS;
                    public short IPLength;
                    public short IPID;
                    public short IPOffset;
                    public byte IPTTL;
                    public byte IPProtocol;
                    public short IPChecksum;
                    public int IPSrcAddr;
                    public int IPDestAddr;
                    // UDP
                    public short UDPsourcePort;
                    public short UDPdestPort;
                    public short UDPLength;
                    public short UDPcheckSum;
                    // CNC
                    public int CNCpacketDirection;
                    public int CNCpacketNumber;
                    public int CNCpacketSource;
                    public int CNCpacketDest;
                    public short CNCpacketPort;
                    public short CNCpacketHeaderEnd;
                    // Data
                    public byte dataType; // 1
                    public byte[] dataSenderBytes;
                    public string dataSender; // 12
                    public byte[] dataMessageBytes;
                    public string dataMessage; // 24
                    public int dataPackOne;
                    public int dataPackTwo;
                    public byte dataPackEnd;

                    public rawCncPacket(byte[] packet)
                    {
                        // IP Header section
                        System.IO.MemoryStream stm = new System.IO.MemoryStream(packet, 0, 94);
                        System.IO.BinaryReader rdr = new System.IO.BinaryReader(stm);
                        IPVerLen = rdr.ReadByte();
                        IPTOS = rdr.ReadByte();
                        IPLength = rdr.ReadInt16();
                        IPID = rdr.ReadInt16();
                        IPOffset = rdr.ReadInt16();
                        IPTTL = rdr.ReadByte();
                        IPProtocol = rdr.ReadByte();
                        IPChecksum = rdr.ReadInt16();
                        IPSrcAddr = rdr.ReadInt32();
                        IPDestAddr = rdr.ReadInt32();
                        // UDP header section
                        UDPsourcePort = rdr.ReadInt16();
                        UDPdestPort = rdr.ReadInt16();
                        UDPLength = rdr.ReadInt16();
                        UDPcheckSum = rdr.ReadInt16();
                        // CNC header section
                        CNCpacketDirection = rdr.ReadInt32();
                        CNCpacketNumber = rdr.ReadInt32();
                        CNCpacketSource = rdr.ReadInt32();
                        CNCpacketDest = rdr.ReadInt32();
                        CNCpacketPort = rdr.ReadInt16();
                        CNCpacketHeaderEnd = rdr.ReadInt16();
                        // Data section
                        dataType = rdr.ReadByte();
                        dataSenderBytes = rdr.ReadBytes(12);
                        dataMessageBytes = rdr.ReadBytes(24);
                        dataSender = System.Text.ASCIIEncoding.ASCII.GetString(dataSenderBytes);                      
                        dataMessage = System.Text.ASCIIEncoding.ASCII.GetString(dataMessageBytes);
                        dataPackOne = rdr.ReadInt32();
                        dataPackTwo = rdr.ReadInt32();
                        dataPackEnd = rdr.ReadByte();
                    }
                }

Luc Pattyn12-Mar-09 4:26

Luc Pattyn

12-Mar-09 4:26

Hi,

not sure why I am getting all this, thanks anyway.

some remarks:

1.
either this struct has strict requirements or it has not.
if it has, I doubt it should hold both public byte[] dataSenderBytes; and public string dataSender; // 12
same for public byte[] dataMessageBytes; and public string dataMessage; // 24
if it has not, don't see why it should need a Pack=1 attribute

2.
your problem is with string handling.
in the native world (C, C++) strings consist of 8-bit characters (or 16-bit wide characters) and they end on the first ASCII NULL character (byte value zero), which means the NULL character itself cannot be embedded in a string.
in the managed world strings can contain any character you choose; if you give 12 bytes (dataSenderBytes) to ASCII.GetString() it probably returns a 12-character string of which several could be NULL (or \0).

So I suggest you get the meaningful length of those strings somehow from the byte[] or from the native world, then use ASCIIEncoding.GetString(Byte[], 0, length)

Smile | :)

Luc Pattyn [Forum Guidelines] [My Articles]

Nagy Vilmos12-Mar-09 3:19

12-Mar-09 3:19

Running it within the IDE, put some breakpoints in on the entry to each of your methods.
Step through and see what the values are that are being received.
Maybe instead of:

chatView.Text = chatView.Text + Environment.NewLine + myName + ": "+ myText;

Try:

String newText = chatView.Text + Environment.NewLine + myName + ": "+ myText;
chatView.Text = newText;

Then after newText has been created you can be sure the correct value is going ito the RHS of the expession.
This is debug problem, you just need to establish the values at every step of the process.

Panic, Chaos, Destruction.
My work here is done.

Member 349379912-Mar-09 3:30

12-Mar-09 3:30

Used breakpoints, saw the values and they were correct.

newText was highlighted in red though when I got to the" chatView.Text = newText" (dont know what that means: VS2008).

myName = "test"
myText = "ETST13245"

newText	"\r\Test\0\0\0\0\0\0\0: ETST13245\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0"	string

Nagy Vilmos12-Mar-09 3:35

12-Mar-09 3:35

Member 3493799 wrote:
\0\0\0\0\0\0\0

As soon as it's hitting the null char, the display is being truncated.

Panic, Chaos, Destruction.
My work here is done.

Member 349379912-Mar-09 3:36

12-Mar-09 3:36

Cheers, that makes sense, will change it accordingly.

Nagy Vilmos12-Mar-09 3:42

12-Mar-09 3:42

You are welcome. Blush | :O

After yesterday's retardfest it is nice to have a real question to answer.

BTW My first port of call when code is not behaving is to debug the thing to smithereens until I find the problem. My second is a call for Port.

Panic, Chaos, Destruction.
My work here is done.

Member 349379912-Mar-09 3:45