C# Discussion Boards - CodeProject

16-Nov-06 1:07

So I have a text file in my projects resources that I need to read into an array.

It's path is:
global::Project1.Properties.Resources.rar

it returns byte[]

How would I get information from this file?

- Munty

JoeSharp16-Nov-06 1:24

JoeSharp

16-Nov-06 1:24

Hi
try this

using (Stream s = this.GetType().Assembly.GetManifestResourceStream("Project1.Properties.Resources.rar"))
{
// Read the content into byte array.
}

Muntyness16-Nov-06 1:55

16-Nov-06 1:55

Hi,

Thanks for replying.

this.GetType().Assembly.GetManifestResourceStream("string") keeps on returning null.
Doesnt matter what I use it with, even files that I successfully use elsewhere will always return a null :/

Here are one of the tests that returned a null:
Object o = this.GetType().Assembly.GetManifestResourceStream("Project1.Properties.Resources._01")

This shouldnt have returned a null because I've used that resource elsewhere for an image.

Here is the code I used that resource for that worked:
imagePanel[0] = Project1.Properties.Resources._01;

- Munty

JoeSharp16-Nov-06 2:01

JoeSharp

16-Nov-06 2:01

hi munty

have you set the build action property of the file to Embedded Resource?

Muntyness16-Nov-06 2:28

Re: Reading text file from Resources [modified]

16-Nov-06 2:28

Tried it as Embedded Resource, Content and None in the Build Action property.

Null on all of them :/

- Munty

Muntyness17-Nov-06 6:27

Catching the Exception thrown from a property that change throu DataBinding [modified]

17-Nov-06 6:27

Finally got the damned thing to work.

Turns out I could use this line:
TextReader tr = new StreamReader(GetType().Assembly.GetManifestResourceStream("Project1.Resources.rar.txt"));
After I fiddled with the properties file so that it returned a string instead of a byte array.

Wierdly enough I can still get properties and stuff from the file from:
Project1.Properties.Resources.rar
I just cant do anything like read in from it when using that line.

Well it's finished. Thank god for that.

- Munty

-- modified at 12:46 Friday 17th November, 2006

NassosReyzidis16-Nov-06 0:40

NassosReyzidis

16-Nov-06 0:40

Hello All,
i have a property in my DataClass and i bound it to a control

<br />
Binding adminBind = new Binding("Checked", user, "IsAdministrator");<br />
this.chkIsAdmin.DataBindings.Add(adminBind);<br />

this Property throw an Exception when some conditions not meet (this code is inside the set of the Property).

<br />
public bool IsAdministrator<br />
		{<br />
			get { return Convert.ToBoolean(_Record.WL_ISADMIN.Value); }<br />
			set<br />
			{<br />
				//If the New value is true<br />
				if (value)<br />
				{<br />
					if (CanBeTheUserAdmin())//Check if the Garage Has Admin User<br />
					{<br />
						//No Admin User, This Becomes Admin<br />
						_Record.WL_ISADMIN.Value = value;<br />
					}<br />
					else//If the Garage Has Admin User throw Exception<br />
						throw new Exception("Δεν Μπορείτε να κάνετε τον Χρήστη Administrator διότι Υπαρχει ήδη Administrator για το Συνεργείο!!");<br />
				}else//If the New value is False, applying it to the user<br />
					_Record.WL_ISADMIN.Value = value;<br />
			}<br />
		}<br />

right now when the exception is thrown the control just DON'T lose Focus, and the user get confused.

How can i cath the Exception in order to show the Exception Message to the User??
Any Saggestion is most Wellcome!
Nassos

-- modified at 7:41 Thursday 16th November, 2006

GanDad

Why do we have properties?

Russell Jones15-Nov-06 23:26

Russell Jones

15-Nov-06 23:26

From everything I read the compiler doesn't create properties in the IL it creates, it creates a method for setting a value and a method for getting the value. In the java world using accessor methods in the code is the way things are done and it works fine. Apart from the syntax of setting or getting a property value from code, which may be a bit nicer than the method syntax and the fact that people should learn to behave themselves in get{} code (I once worked with someone who changed the selected index of a combo in a VB6 Property Get for a comboBox, great fun when putting watches on things) I can see no advantages in using properties over accessor methods. At the same time I can see problems like the inability of c# to create Property delegates (i'm talking well behaved ways here) encouraging me to use accessor methods.

Can anyone think of reason why I should use properties in my code? Do we just blindly do things this way because we always used them in VB or because the books teach it that way?

Russ

Martin#15-Nov-06 23:35

Martin#

15-Nov-06 23:35

Hello,

One reason could be the user support over the designer (VisualStudio Designer).

arachnoid wrote:
Do we just blindly do things this way because we always used them in VB or because the books teach it that way?

Never worked with VB before, but I'm also a fan of properties.

Martin

Russell Jones16-Nov-06 0:09

Russell Jones

16-Nov-06 0:09

I hadn't thought about that. I guess things like databinding use properties aswell.

Maybe if the compiler allowed you to use either Propertyname = value or set_Propertyname(value). That way the delegate problem would be solved without relying on c#'s underlying implementation and we would have the best of both worlds.

Russ

J4amieC15-Nov-06 23:55

J4amieC

15-Nov-06 23:55

Its just eye candy - as you rightly state, under the hood the IL is a get_PropertyName() and set_PropertyName(value) method.

I use properties as I prefer the look of

int myValue = myObject.MyProperty

than

int myValue = myObject.GetMyProperty();

---

How to get answers to your questions[^]

Martin2316-Nov-06 0:00

Martin23

16-Nov-06 0:00

You don't have to use properties if you prefer not to. Virtually everybody does though, as they make code much easier to understand.

iPod like menu for pocket pc development

V.16-Nov-06 2:34

16-Nov-06 2:34

One small adavantage is you can do something like this:
MyStringProperty += " Concatenate this...";

for getters and setters this would be SetStringProperty(GetStringProperty() + " Concatenate this...");

Same for other type (int, double,...)

V.
Stop smoking so you can: enjoy longer the money you save.

HRiazi15-Nov-06 23:07

HRiazi

15-Nov-06 23:07

Hi guys
anyone could help me or give me a hint on How to develope an iPod like menu for a pocket pc program?

thanks
Riazi

Problem in building DirectShow Application

alpa shah15-Nov-06 22:06

alpa shah

15-Nov-06 22:06

Hello all,
I'm new to DirectShow application. I've build a normal application that can run .avi file. I've got an error in RenderFile(), like problem in file loading. so please anyone can help me out how to solve this problem? File path is correct and to load .jpg file it's working fine but in loading .avi files I got problem.... Cry | :((

...And ya I'm building this application in C# using visual studio 2005.

Please reply soon...

Thanks for reading my question...

alpa shah

AB777115-Nov-06 22:33

AB7771

15-Nov-06 22:33

Which version of DirectShow are u using?
Have you referenced the dll in ur app?

Thanks & Regards,
Pramod
"Everyone is a genius at least once a year"

alpa shah15-Nov-06 22:46

alpa shah

15-Nov-06 22:46

All dll's i've included in that. I'm using platform SDK that is server 2003 sp1. I think it is most recent one for DirectShow application. Cry | :((

alpa shah

Amar Chaudhary15-Nov-06 23:01

Amar Chaudhary

15-Nov-06 23:01

is your hardware accelertion turned on

It is Good to be Important but!
it is more Important to be Good

[My Question]

AB777115-Nov-06 23:01

AB7771

15-Nov-06 23:01

Is it giving any exception?
Which method have u called to play the .avi file?

can u paste some code so we can get to the problem.

Thanks & Regards,
Pramod
"Everyone is a genius at least once a year"

alpa shah15-Nov-06 23:07

alpa shah

15-Nov-06 23:07

yes, it's throwing me exception.

I've implemented the sample application from this site only...

sample code is:

try{
//get the graph filter ready to render
OpenFileDialog ofg = new OpenFileDialog();
if (ofg.ShowDialog() == DialogResult.OK)
{
String fileName;
fileName = ofg.FileName;
graphBuilder.RenderFile(fileName);
Text = fileName;
//set the trackbar
isSeeking = (graphBuilder.CanSeekForward() == -1) &&
(graphBuilder.CanSeekBackward() == -1);
if (isSeeking)
trackBar1.Enabled = true;
else
trackBar1.Enabled = false;
trackBar1.Minimum = 0;
trackBar1.Maximum = (int)(graphBuilder.Duration * 100.0);

Text = fileName;

//prepare and set the video window
videoWin = graphBuilder as IVideoWindow;
videoWin.Owner = (int)panel1.Handle;
videoWin.WindowStyle = WS_CHILD | WS_CLIPSIBLINGS | WS_CLIPCHILDREN;
Rectangle rc = panel1.ClientRectangle;
videoWin.SetWindowPosition(0, 0, rc.Right, rc.Bottom);
mediaEvt.SetNotifyWindow((int)this.Handle, WM_GRAPHNOTIFY, 0);

//set the different values for controls
trackBar1.Value = 0;

minutes = (int)graphBuilder.Duration / 60;
seconds = (int)graphBuilder.Duration % 60;
statusBar1.Panels[0].Text = "Duration: " + minutes.ToString("D2")
+ ":m" + seconds.ToString("D2") + ":s";
graphState = State.Playing;

//start the playback
mediaCtrl.Run();
}
}
catch( Exception ) { Text = "Error loading file"; }

alpa shah