C# Discussion Boards - CodeProject

Re: trim away last 4 characters of a string

Stefan Troschuetz21-Sep-06 21:34

Stefan Troschuetz

21-Sep-06 21:34

Simplest solution I can think of is using SubString method:

strName.SubString(0, strName.Length - 4);

"Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning." - Rick Cook

www.troschuetz.de

Re: trim away last 4 characters of a string

Support12321-Sep-06 21:46

Support123

21-Sep-06 21:46

thank you...

i used that example to get rid of one caracter aswell.

so am i understanding this right if i say that the "-4" or "-1" would be the amount of caracter to be left out from the end?

"Many of life's failures are people who did not realize how close they were to success when they gave up." Thomas A. Edison

Re: trim away last 4 characters of a string

Stefan Troschuetz21-Sep-06 21:51

Stefan Troschuetz

21-Sep-06 21:51

NarutoFan#1 wrote:
so am i understanding this right if i say that the "-4" or "-1" would be the amount of caracter to be left out from the end?

In case the first parameter (startIndex) equals 0, that's true.

Re: trim away last 4 characters of a string

Support12321-Sep-06 21:53

Support123

21-Sep-06 21:53

Okay, Great.

Thank you...

"Many of life's failures are people who did not realize how close they were to success when they gave up." Thomas A. Edison

Re: trim away last 4 characters of a string

Guffa22-Sep-06 0:04

Guffa

22-Sep-06 0:04

NarutoFan#1 wrote:
would it work, if i use one of the examples someone gave me, to do it like this...

strName[strName.Length-1] = string.Empty;

Who gave you that example? That is not even close to something that would work.

The indexer property of a string returns a character, so the value of strName[strName.Length-1] is a character value. The property is read only (as strings can not be changed), so you can not give the character a new value. Even if you could, you would not be able to change the length of the string, and you would not be able to put in a string in place of the character.

As you can not change a string, the only way to get a string with a different contents is to create a new string that contains what you want. The SubString method (as suggested by Stefan) does this. The Remove method can also be used:

strName = strName.Remove(strName.Lenght - 4, 4);

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b { font-weight: normal; }

Re: trim away last 4 characters of a string

Support12322-Sep-06 0:17

Support123

22-Sep-06 0:17

it was this part....

On another note, something faster, and optimized than substring or trimending<br />
(think what shall happen calling substring on a very huge string?)<br />
<br />
strNum[strNum.Length-1] = string.Empty;<br />
<br />
There are few scenarios where this will be the best and others where this wont be a better idea.<br />
<br />
Excelsior<br />
Arjun Bahree<br />
"By The Might of Mjolnir"<br />
<br />
I Came! I Coded! I Conquered!

its from the following post i made a while back....

http://www.codeproject.com/script/comments/forums.asp?forumid=1649&XtraIDs=1649&searchkw=trimend&sd=1+jan+1995&ed=22+Sep+2006&stype=1&select=1662836&df=100&fr=1642.5#xx1662836xx[^]

"Many of life's failures are people who did not realize how close they were to success when they gave up." Thomas A. Edison

Re: trim away last 4 characters of a string

Guffa22-Sep-06 0:34

Guffa

22-Sep-06 0:34

I see.

As lmoelleb already pointed out at the time, the code is utter nonsense.

The only scenario where this code might be the useful is if you deliberately want to produce a compiler error. Even then it's hardly the best code, as the same result can be obtained with much simpler code, e.g.:

char c = "";

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b { font-weight: normal; }

Re: trim away last 4 characters of a string

Support12322-Sep-06 0:42

Support123

22-Sep-06 0:42

LOL

So i won't even think of using that piece of code....

Thank yo for your help.

"Many of life's failures are people who did not realize how close they were to success when they gave up." Thomas A. Edison

Re: trim away last 4 characters of a string

Support12322-Sep-06 0:20

Support123

22-Sep-06 0:20

I see you are the one who gave me this example, and this is the one i used...
so i suppose no harm done......

strNum = strNum.SubString(0, strNum.Length - 1);

"Many of life's failures are people who did not realize how close they were to success when they gave up." Thomas A. Edison

check boxes in C#.net 2005

Rohit Dev21-Sep-06 21:13

Rohit Dev

21-Sep-06 21:13

hi all,
how can i create checkboxes dynamically in a C#.net2005 WEindows application..
Thanks in advance..

Re: check boxes in C#.net 2005

Guffa21-Sep-06 21:23

Guffa

21-Sep-06 21:23

Create a CheckBox control and add it to the form.

---
b { font-weight: normal; }

Re: check boxes in C#.net 2005

Malcolm Smart21-Sep-06 21:38

Malcolm Smart

21-Sep-06 21:38

<br />
<br />
//create a new checkbox<br />
CheckBox myBox = new CheckBox();<br />
<br />
//set if (if required)<br />
myBox.Checked = true;<br />
<br />
//add it to the parent<br />
myPanel.Controls.Add( myCheckBox );<br />
//assumes myPanel exists<br />
<br />

Regards

Malc
*********************************************

Re: check boxes in C#.net 2005

Christian Graus22-Sep-06 0:13

Christian Graus

22-Sep-06 0:13

The example you were given is sort of right, but if you want to see the checkbox whre you want it, you need to set the Left, Top, Width and Height properties as well.

Christian Graus - Microsoft MVP - C++
Metal Musings - Rex and my new metal blog

Reading from a text

cnr36921-Sep-06 21:06

cnr369

21-Sep-06 21:06

Hi all,
I am working on DXF formats in c#.NET in windows applications.i was struck with reading data from dxf formats i.e.,importing data.how to import the data according to the requirement of the values....Plz help me ASAP.

advance in thanks,
cnr.

Re: Reading from a text

Stefan Troschuetz21-Sep-06 21:42

Stefan Troschuetz

21-Sep-06 21:42

1. Search the net for a specification of the dxf format to learn how data are organized.
2. Choose an appropriate reader (binary, text, xml, ..) according to the way data are stored in dxf format.
3. Finally read the data with the chosen reader in a way the dxf format specification implies.

how to move form in a main form

Parshant Verma21-Sep-06 20:58

Parshant Verma

21-Sep-06 20:58

Hi i want to make a application just like setup wizard.
form are should be appear by a next click in a main form one by one .
but next button shold be static for all form

how can i do that
Plz tell me simple solution

Parshant

Re: how to move form in a main form

Nader Elshehabi21-Sep-06 21:55

Nader Elshehabi

21-Sep-06 21:55

Hello

Instead of making a form for each step; make a single form for your wizard. Now in the design mode, make each page's controls -textboxes, comboboxes, listboxes, etc..- in a container such as Panel, or a GroupBox. Put all Panels on top of each other -It will be a bit of a miss in the design mode I know Big Grin | :-D

-, and hide them all except the first page. Under the panels make you next/back buttons to hide/show pages asd requested by the user.

Regards

RichEditCtrl

shan2k21-Sep-06 20:11

shan2k

21-Sep-06 20:11

RichEditCtrl
Is it possible to create a richeditcontrol with ruler on top and row number on left side using Visual Studio .Net 2005 C# with the following features?

1.RichEditCtrl should allow bytewise cursor movement ( not characterwise)
2.Inside the control, horizontal and vertical lines need to be drawn along with the other language text.

Shanthi.M

Re: RichEditCtrl

Stefan Troschuetz21-Sep-06 21:46

Stefan Troschuetz

21-Sep-06 21:46

shan2k wrote:
Is it possible to create a richeditcontrol with ruler on top and row number on left side using Visual Studio .Net 2005 C# with the following features?

Impossible is nothing Big Grin | :-D

Problem set parameter value in Crystal report

hieunts21-Sep-06 19:31

hieunts

21-Sep-06 19:31

Hi All,

I use this code to set value for store procedure parameter. Then it is OK.

report.Load(@"..\..\Reports\CrystalReport2.rpt");
report.SetParameterValue(0, "test");
crystalReportViewer1.ReportSource = report;

But when I use SetConnection for this report then the parameter can't get value which I set.

report.Load(@"..\..\Reports\CrystalReport2.rpt");
report.SetParameterValue(0, "test");
foreach (CrystalDecisions.Shared.IConnectionInfo connection in report.DataSourceConnections)
{
connection.SetConnection(serverName1, database, userID, password);
}
crystalReportViewer1.ReportSource = report;

Could any one help me what wrong of this code.

Reg: Webservies projects

guru_41821-Sep-06 18:44

guru_418

21-Sep-06 18:44

Hi Every body,

This is prasad. i want some information about webservies.i want to know how to call the webservies . i did the webservices in my local system but i don't know how to call the weather & Time webservies form their providers. So ,Please can any bosy hepl me regarding in this concept .

Thanks & Regards,
T.GuruPrasad Reddy.

Re: Reg: Webservies projects

Christian Graus21-Sep-06 18:49

Christian Graus

21-Sep-06 18:49

You add a reference to your webservice in the IDE, which creates classes that handle connecting to the service, you call the classes as if they were local to you, there's no additional work required.

Christian Graus - Microsoft MVP - C++
Metal Musings - Rex and my new metal blog

Re: Reg: Webservies projects

guru_41821-Sep-06 18:57

guru_418

21-Sep-06 18:57

Webservies

Remoting problems with ArrayList return

drinkingbird21-Sep-06 15:25

drinkingbird

21-Sep-06 15:25

I've got an application up and running, using remoting.

Things generally seem to work, but there seem to be problems with returning ArrayLists from the remote object.

I have some small helper classes to use in passing around data, and if I add any of these to an ArrayList, and then try to return the ArrayList, I get a RemotingException on the client side. Returning an empty ArrayList, or one that contains only .NET builtin types works though.

Is there something special I need to do to allow classes I've defined to be returned in the ArrayList?

Re: Remoting problems with ArrayList return

Dave Kreskowiak21-Sep-06 15:58

Dave Kreskowiak

21-Sep-06 15:58

Your class has to be attributed Serializable, just like if you were going to serialize it to an XML file.

Dave Kreskowiak
Microsoft MVP - Visual Basic

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