C# Discussion Boards - CodeProject

26-Apr-06 17:00

i use .net framework1.1, i would like to double-click notifyIcon to show a webbrowser,but the webbrowser always shows in the left and top of the screen,
i want your help, the code is follow :

namespace WindowsApplication8
{
///

/// Form1 的摘要说明。
///

public class Form1 : System.Windows.Forms.Form
{
private AxSHDocVw.AxWebBrowser axWebBrowser1;
private System.Windows.Forms.NotifyIcon notifyIcon1;
private System.Windows.Forms.ContextMenu contextMenu1;
private System.Windows.Forms.MenuItem menuItem1;
private System.ComponentModel.IContainer components;

protected override void Dispose( bool disposing )
{
if( disposing )
{
if (components != null)
{
components.Dispose();
}
}
base.Dispose( disposing );
}

private void InitializeComponent()
{
this.components = new System.ComponentModel.Container();
System.Resources.ResourceManager resources = new System.Resources.ResourceManager(typeof(Form1));
this.axWebBrowser1 = new AxSHDocVw.AxWebBrowser();
this.notifyIcon1 = new System.Windows.Forms.NotifyIcon(this.components);
this.contextMenu1 = new System.Windows.Forms.ContextMenu();
this.menuItem1 = new System.Windows.Forms.MenuItem();
((System.ComponentModel.ISupportInitialize)(this.axWebBrowser1)).BeginInit();
this.SuspendLayout();
//
// axWebBrowser1
//
this.axWebBrowser1.Dock = System.Windows.Forms.DockStyle.Fill;
this.axWebBrowser1.Enabled = true;
this.axWebBrowser1.Location = new System.Drawing.Point(0, 0);
this.axWebBrowser1.OcxState = ((System.Windows.Forms.AxHost.State)(resources.GetObject("axWebBrowser1.OcxState")));
this.axWebBrowser1.Size = new System.Drawing.Size(292, 266);
this.axWebBrowser1.TabIndex = 0;
//
// notifyIcon1
//
this.notifyIcon1.Icon = ((System.Drawing.Icon)(resources.GetObject("notifyIcon1.Icon")));
this.notifyIcon1.Text = "notifyIcon1";
this.notifyIcon1.Visible = true;
this.notifyIcon1.MouseDown += new System.Windows.Forms.MouseEventHandler(this.notifyIcon1_MouseDown);
this.notifyIcon1.DoubleClick += new System.EventHandler(this.notifyIcon1_DoubleClick);
//
// contextMenu1
//
this.contextMenu1.MenuItems.AddRange(new System.Windows.Forms.MenuItem[] {
this.menuItem1});
//
// menuItem1
//
this.menuItem1.Index = 0;
this.menuItem1.Text = "Exit";
this.menuItem1.Click += new System.EventHandler(this.menuItem1_Click);
//
// Form1
//
this.AutoScaleBaseSize = new System.Drawing.Size(6, 14);
this.ClientSize = new System.Drawing.Size(292, 266);
this.Controls.Add(this.axWebBrowser1);
this.Name = "Form1";
this.Text = "Form1";
this.Closing += new System.ComponentModel.CancelEventHandler(this.Form1_Closing);
this.Load += new System.EventHandler(this.Form1_Load);
((System.ComponentModel.ISupportInitialize)(this.axWebBrowser1)).EndInit();
this.ResumeLayout(false);

}
#endregion

static void Main()
{
Application.Run(new Form1());
}

private void notifyIcon1_DoubleClick(object sender, System.EventArgs e)
{
this.Show();

object flags = (2 | 4 | 8);
object targetFrame = null;
object postData = null;
object headers = null;

this.axWebBrowser1.Navigate("http://www.google.com",ref flags,ref targetFrame,ref postData,ref headers);

if (this.WindowState==FormWindowState.Minimized)
this.WindowState=FormWindowState.Normal;
this.Activate();
this.notifyIcon1.Visible=false;

}

private void Form1_Load(object sender, System.EventArgs e)
{
this.notifyIcon1.Visible=true;

object flags = (2 | 4 | 8);
object targetFrame = null;
object postData = null;
object headers = null;

this.axWebBrowser1.Navigate("http://www.google.com",ref flags,ref targetFrame,ref postData,ref headers);

}

private void Form1_Closing(object sender, System.ComponentModel.CancelEventArgs e)
{
e.Cancel=true;
this.Hide();
this.ShowInTaskbar=false;
this.notifyIcon1.Visible=true;

}

private void menuItem1_Click(object sender, System.EventArgs e)
{
this.notifyIcon1.Visible=false;
Application.Exit();
}

private void notifyIcon1_MouseDown(object sender, System.Windows.Forms.MouseEventArgs e)
{
Control control = new Control(null,Control.MousePosition.X,Control.MousePosition.Y,1,1);

if (e.Button==MouseButtons.Right)
{
control.Visible = true;
control.CreateControl();
Point pos = new Point(1,1);
this.contextMenu1.Show(control,pos);
}

}
}
}
Thanks

Guffa26-Apr-06 20:52

26-Apr-06 20:52

Perhaps you should mention what it is that you need help with?

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ylw6626-Apr-06 21:03

26-Apr-06 21:03

i write the question in my message:i want to double-click notifyicon to open a webbrowser in it's right position.but it always show in left and top of screen
if you don't know my question clearly, please run the code i gived,i could forward your help
thanks

Guffa26-Apr-06 22:35

26-Apr-06 22:35

What in your opinion is the "right" position for the browser, then?

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b { font-weight: normal; }

ylw6626-Apr-06 23:15

26-Apr-06 23:15

please run the code,then you will see the problem

Guffa27-Apr-06 1:07

27-Apr-06 1:07

No, I will not run the code to see the problem, unless you explain why you can't just tell me.

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ylw6627-Apr-06 15:32

27-Apr-06 15:32

Sorry,i am a newer of codeproject,i don't know what do you mean :

Guffa wrote:
unless you explain why you can't just tell me

i want a notifyicon to active the webbrowser,you can try it.
for example:
your form's location is(300,200),
and have a webbrowser fill the form ,
when you minisize the form to the notifyicon,
and then double-click the notifyicon,
you'will see the webbrowser's location is(0,0),always (0,0)
Thanks

Guffa28-Apr-06 3:21

28-Apr-06 3:21

Which takes us back to the question I asked before:

"What in your opinion is the "right" position for the browser, then?"

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b { font-weight: normal; }

ylw6628-Apr-06 15:01

28-Apr-06 15:01

Perhaps my English is not very well,i mean i want control the webbrowser's position,but i can't.
ex:if i want webbrowser's location in(200,200),but it always in (0,0)

J4amieC26-Apr-06 22:24

J4amieC

26-Apr-06 22:24

In your double-click event handler for notifyIcon1 just set this.Location to wherever you want it positioned onscreen.

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ylw6626-Apr-06 23:18