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Eddy,
Yes its not a good idea to copy but still i am ordered to do so..
Regards
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Then re-read what I wrote on communicating over TCP/IP. And yes, I'm kinda used to people being ordered and blindly following.
Aw, there's Godwin again
--edit;
Let me rephrase; is the person who proposed this idea and "ordered it" also going to take full responsibility if there's a virus on the network?
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PankajKSood wrote: That thing is also performed though window service.
No, it's not. It's a normal application that is launched from the Run key that does this check, not a service. It's started every time someone logs into the machine.
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1. right click the service in services.
2. Choose "properties"
3. Select the tab "Log On"
4. click the radio button on top saying "Local System account"
5. Tick the checkbox "Allow service to interact with desktop"
I would strongly recommend AGAINST doing this.
hope this helps.
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V.
I have already tried that approach but that fails too.
Regards
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It's not going to work at all.
Starting with Vista, services are no longer allowed to interact with the users desktop. This is expecially true as there is sometimes nobody logged in at the console so there's no desktop to interact with.
You cannot do what you want from a service application. This MUST be done as a normal user app that is usually launched from the Run key in the registry. This application then communicates with the service over some transport, like named pipes, TCP/IP, Shared Memory, or what ever you want. It's the job of this application to provide the user interface for the service, send commands to the service and show any data the service needs displayed.
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Hi Guys
I have question a regarding application Development using MVC 3, What are the best tricks and best practices for MVC 3, I am bigger in this technology, what will help me to speed up learning and achieving the functionality .
I want to know that how events ,states are handled using MVC 3,
Thanks
Vishwa
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When I was first learning MVC3, I found the pluralsight videos and tutorials over at http://www.asp.net/mvc/[^] where of great help.
I actually learnt MVC3 while developing a KPI Management solution for my degree, and it was a great help.
Cheers,
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Thank you Dave,
I am also learning fro the same site, and i reading books also,
i am asking for the better approach or good practice for application development.
As per my knowledge there is no default event handling in MVC 3 so is there any different approach ?
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I also have this book, i am reading from 2 days, may be i have to go through more to clear my doubts.
Thanks buddy
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I am opening an image through my c# windows application. After that i need to show the form in the screen.How can i do this? any Help regarding this ll be useful.
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I've read some materials about SerialPort in VS2010, and they refer to the stream and the input buffer of the SerialPort object! and i wonder what they are ?
In addition, I'd like to change between reading data in binary or text form when reading from serial buffer.How can I do this ?
Hope to get your help ! ^ ~ ^ !
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See the SerialPort class[^] for full details. As to reading text or binary, there is no real difference. Serial ports transmit data as a stream of bytes, it is up to the sender and receiver to agree what that data represents.
One of these days I'm going to think of a really clever signature.
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thanks Richard MacCutchan ! but what about stream and internal buffer ?
and what you mean:"One of these days I'm going to think of a really clever signature" ?
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nqchanh wrote: what about stream and internal buffer ? What about them? You need to explain what your problem is; if you just want general information then go to the MSDN page in the link I gave you and read about the class and its methods and properties.
One of these days I'm going to think of a really clever signature.
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Help,How to Convert the Array,Collection,DataTable Or DataSet to Xml File?
How to Convert the JSON To Xml Or Xml To JSON?
Thank you
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Item 1: I do not want large source files.
Item 2: I have some rectangles on my Form.
Item 3: I want to access the rectangles, for graphing, from other files.
Can someone direct me to some sort of explanation me how that's done ?
Certainly this is common practice; but I can't find it clearly documented in websites, videos, whatever.
------
Details
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If I have a file called GraphClassesAndMethods.cs, and I want to, say, put a dot or a line on a rectangle which I designed with the C# toolbox, then how do I get C# to let my class and method in this file see the rectangle ?
C# knows that they are there when I'm typing in the Form1.cs file, and I wrongly inferred/guessed that the reason that it couldn't see the same rectangle in the graphClassesAndMethods files was because the class had a different name.
To test this, I put a class and method outside the Form1 class (in the Form1.cs file) and Ta-Da, the rectangles were not visible to code in that class. So I thought (wrongly) that if I put the same class name in the other file, then they would be visible.
No.
One "solution" to this problem is to create a ridiculously large amount of source in the file Form1.cs, in which case we will have a blob that works once, version 1.0, and will require three years to implement the simplest little change.
Request: Someone please explain to me how to let my code (i.e., in the other file) see the rectangles which are perfectly visible to code that I type in the Form1 class in the Form1.cs file.
Of particular interest to me is that I would like to also have an InitEverything.cs file where I can put all the "ooops, that should have been done first" routines and so on which tend to crop up during the last 10% of the coding.
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Create your class Rect.cs
In form 1 create an instance of Rect.cs
Rect oRect = new Rect();
Use oRect to do the work.
Create an instance of your ThirdClass passing the instance of oRect in the constructor
ThirdClass oThirdClass = new ThirdClass(oRect);
This really is c#101, buy a book and work through the examples.
Never underestimate the power of human stupidity
RAH
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Files mean nothing.
Well, hardly anything.
You are really asking about access between classes and are likely considering making your fields (rectangles) public so your other classes can access them. If so, don't.
On the other hand, you really haven't given us much information to go on.
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Windows Form controls added using the designer are by default "private".
If you want them to be "public" (using the designer), you need to specicy as such via the "Modifiers" item on a control's "Properties" tab.
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Gerry Schmitz wrote: specicy as such via the "Modifiers" item on a control's "Properties" tab. Did exactly that. Did not work.
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Of course it works.
Assuming you have a "reference" to an "instance" of the form, all "public" fields / properties / controls will be visible in your "other" file.
The controls (eg. your rectangle) are members of your form class; without a reference to the form "object", it "won't work".
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Hi all,
im new to C# (coming from matlab), and so theres a lot to explore for me (the whole OOP thing ). Currently I write a simple program which deserializes a xml file (on a menu click) and shows the xml structure in a treeview.
My Problem:
When clicking on an element of the treeview, i want to show the content of the chosen xml field in a datagrid. This means I have to make the deserialized xml (which is an object) avaialable for the treeView1_AfterSelect. Maybe someone has a hint for me? I already searched for a solutions which fits this problem . Maybe its to obvious ^^?
Here's some code (im very new to OOP so dont laugh ).
...
private void loadObjectsToolStripMenuItem_Click(object sender, EventArgs e)
{
string FilePath = string.Empty;
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.Filter = "xml files (*.xml)|*.xml| All files (*.*)|*.*";
openFileDialog1.InitialDirectory = System.IO.Path.Combine(System.IO.Path.GetDirectoryName(Application.ExecutablePath), @"");
if (openFileDialog1.ShowDialog() == DialogResult.OK)
FilePath = openFileDialog1.FileName;
xmlDataThings xmlData= (xmlDataThings )xmlReadWrite.DeSerializeFromXML(FilePath, typeof(xmlDataThings ));
TreeNode tNode = new TreeNode(openFileDialog1.SafeFileName);
if (treeViewObjects.Nodes.ContainsKey(openFileDialog1.SafeFileName))
return;
tNode.Name = openFileDialog1.SafeFileName;
treeViewObjects.Nodes.Add(tNode);
tNode = treeViewObjects.Nodes[treeViewObjects.Nodes.Count-1];
AddNode(xmlData, tNode);
treeViewObjects.ExpandAll();
}
private void treeViewObjects_AfterSelect(object sender, TreeViewEventArgs e)
{
if (treeViewObjects.SelectedNode.Level == 2)
{
}
...
}
Would be very nice if someone has a hint for me.
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