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Each time you call RemoveAt() the size of the array reduces by 1. GetSize() may therefore not give you the result you expect!
A better way would be to replace the elements to be removed with "special" values (like empty strings and -1, for example), then remove those elements in a 2nd loop.
/ravi
My new year's resolution: 2048 x 1536
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ravib@ravib.com
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Thanks ravi. I was thinking of trying the similar stuff as your suggested if I don't have any idea to fix my original algorithm. but now I fixed it! :p
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try removing items from the end of the array instead of the start.
Maximilien Lincourt
Your Head A Splode - Strong Bad
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Thanks anyway 
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Only increment nIndex if the compare fails. With your logic, say you have 5 items
A
B
C
D
E
if nIndex is 2, carrURL[nIndex] is 'C'. If you remove this, the array looks lke
A
B
D
E
and then the for loop increments nIndex to 3.
carrURL[nIndex] is now 'E'.
You've missed 'D' completely.
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Thx very much Graham, as you said, I just skipped 1 value each time.
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Hi,
I would like to ask that;
#include "stdafx.h"<br />
#include <iostream><br />
<br />
int _tmain()<br />
{<br />
int myInts[3] = {0,1,2};<br />
char * myName = "sarp";<br />
<br />
std::cout << myName << std::endl;<br />
std::cout << myInts << std::endl;<br />
<br />
return 0;<br />
}
Why it prints out sarp in first output and memory location in second output? I was waiting for memory location of s in the first one.
Also, what is the difference between;
char * myName = "sarp";<br />
char myName[] = "sarp";
Thanks,
Sarp
-
When in doubt, push a pawn!
-
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cout must have an overloaded method to output char*, and nothing to output int* ( except for the adress ).
Maximilien Lincourt
Your Head A Splode - Strong Bad
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kromozom wrote:
Why it prints out...memory location in second output?
What would you expect it to print out?
kromozom wrote:
I was waiting for memory location of s in the first one.
Then you should use cout << &myName << endl; instead.
"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow
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 well.....for thiz iz for ur info.....
whenu declare the variable say.....
char a[10];
here the variable "a" is bacially like a pointer,it terminates only when it "sees" the "\O"
thatz why u dont get the same answer.....
if want just one letter to come do like thiz.....
cout<<*(myname);
if u want the second letter.....
cout<<*(myname+1)
and so on.....
hope that helpz.....
happy programmin.....
cheerz.....
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Thanks all, I have cleared some of my confused knowledge...
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When in doubt, push a pawn!
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I am using CScrollView to handle scrolling. The only thing I did so far with ScrollView is setscrollsize and that's it.
Why is that when I have long document open and I drag the scroll bar scrolling my scroll bar would jump right back to the to the top/begining as soon I release my mouse button? Mouse click jump to location, click on scroll arrows up and down, or mouse wheel they all scroll fine.
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I test it out by shrinking the document. It seems to occur when the document goes over 1850 lines.
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I have written a program C++. I want to be able to give the user an option to print or print preview the putput or exe file. Are there any tutorials that explain how to create a page like this in MFC. I have a little idea but do not know how to enter my C++ code into the MFC template in order to create the complete program.
Thank You all for all of your assistance.
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REPOST ! 
and i'm not sure you want to print "exe files"... do you know what is exe files ?
do you already opened a compiled file into a WYSIWYG editor (like notepad, ultraedit...) ???
TOXCCT >>> GEII power
[VisualCalc][toxcct]
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The exe file is what I get after I compile and build my program. I run it and out comes an exe file. The program perfroms exactly how I want it to. Now I want to be able to take my code and enter it into MFC so I will have a more functional program that give the user the option to print out the results. With the exe you can only view it. Of course they could maybe cut and paste but that is not to professional.
Thank You
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so, you have an executable (A) that when run will extract/generate another executable (B) ?
and when you run B, you want it to be able to print what it displays ?
if so, you need to reprogram B to handle the print process.
Am I understanding corretly your situation ?
Maximilien Lincourt
Your Head A Splode - Strong Bad
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so what do you want to print ? binary datas ? source codes ? document files manipulated by your "exe" (program) ?
ps : MFC is not a functionality or anything like that. MFC means "Microsoft foundation classes". it is a framework that provides you a set of classes and functions to ease you windows programming?
TOXCCT >>> GEII power
[toxcct][VisualCalc]
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BRIMID wrote:
The exe file is what I get after I compile and build my program.
We all agree on this much. Hereinafter is where things get sketchy.
BRIMID wrote:
I run it and out comes an exe file.
This implies that your program produces another .EXE file. Yes?
BRIMID wrote:
The program perfroms exactly how I want it to.
What exactly does it do?
BRIMID wrote:
Now I want to be able to take my code and enter it into MFC so I will have a more functional program...
Are you saying that you want to base your program on MFC rather than the standard Win32 API?
BRIMID wrote:
...that give the user the option to print out the results.
The results of what?
BRIMID wrote:
With the exe you can only view it.
What is it viewing?
"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow
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I will try to explain a liitle simpler.
I wrote a program to add 1+2=3
I Compile it, Build it, and then execute it. I have a exe file. Right?
Everytime I run the exe file is see 1++2=3. But the file does not have the option to print. I would like to be able to print out the results of the program i.e., 1+2=3.
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So all you are really wanting to do is output the sum of 1 and 2 to the screen?
With C:
printf("%d\n", 1 + 2);With C++:
cout << 1 + 2 << endl; Does that help?
"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow
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I have that. I am able to display output to the screen using cout<<. I want to send the output on the screen to the printer.
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Well, if you are running your program from a command prompt, just redirect its output to the printer like:
C:\> myprog.exe > prn
or
C:\> myprog.exe > lpt1
"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow
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