C / C++ / MFC Discussion Boards

Jochen Arndt15-May-18 0:01

15-May-18 0:01

It is a valid reply and the important parts are the script tags which are executed by web browsers showing the final content. If JavaScript is disabled in a browser, the content of the noscript tag is shown:

HTML

<noscript>Please enable JavaScript to view the page content.</noscript>

That is the problem with todays web sites: They don't use plain HTML anymore.

Even well known tools like wget don't support JavaScript and can't be therefore used to download the "visible" content (which may vary with attributes like media type and screen resolution). You would have to use a client that is able to do all the stuff that a web browser can do besides the final rendering.

Re: CInternetSession OpenURL

_Flaviu15-May-18 0:21

_Flaviu

15-May-18 0:21

Thank you Jochen. I had tried to create an html client with CHtmlView, and here is the result:

C++

void CTestHTMLView::OnInitialUpdate()
{
	CHtmlView::OnInitialUpdate();

	Navigate2(_T("http://www.mfinante.ro/pagina.html"), NULL, NULL);
}

result is blank page … is there impossible to solve this programmatically, in this case ?

Re: CInternetSession OpenURL

Jochen Arndt15-May-18 0:31

Jochen Arndt

15-May-18 0:31

Use the CHtmlView GetSource() method to inspect the source. It will probably like those you have already got and should contain hints about what is missing.

Note also that the IE settings are used which might be too restrictive.

Re: CInternetSession OpenURL

_Flaviu15-May-18 0:44

_Flaviu

15-May-18 0:44

I had tried to use CHtmlView::GetSource(), but the string was exactly like the one from CInternetSession::OpenURL() method … no difference between them …

C++

void CTestHTMLView::OnHelpGetsource()
{
	// TODO: Add your command handler code here

	CString s;
	GetSource(s);
}

and the result is:

HTML

<!DOCTYPE html>
<html><head>
<meta http-equiv="Pragma" content="no-cache"/>
<meta http-equiv="Expires" content="-1"/>
<meta http-equiv="CacheControl" content="no-cache"/>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
<link rel="shortcut icon" href="data:;base64,iVBORw0KGgo="/>

<script>

(function(){
    var securemsg;
    var dosl7_common;

window["bobcmn"] = "1111101111101020000000220000000520000000025705570d200000096300000000300000000300000006/TSPD/300000008TSPD_101300000004http200000000200000000";

window.SqNs=!!window.SqNs;try{(function(){try{var ss,Ss,is=1,Js=1,Ls=1,zs=1,Zs=1;for(var jS=0;jS<Ss;++jS)is+=2,Js+=2,Ls+=2,zs+=2,Zs+=3;ss=is+Js+Ls+zs+Zs;window.lJ===ss&&(window.lJ=++ss)}catch(JS){window.lJ=ss}var oS=!0;function ZS(s){!s||document.visibilityState&&"visible"!==document.visibilityState||(oS=!1,document.cookie="brav=ad");return oS}function s_(){}ZS(window[s_.name]===s_);ZS("function"!==typeof ie9rgb4);ZS(/\x3c/.test(function(){return"\x3c"})&!/x3d/.test(function(){return"'x3'+'d';"}));
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document.addEventListener&&document.addEventListener("visibilitychange",function(s){document.visibilityState&&("hidden"===document.visibilityState&&s.isTrusted?Si=!0:"visible"===document.visibilityState&&(Z_=+new Date,Si=!1,ji()))});var li=[17795081,27611931586,1558153217];function Li(s){s="string"===typeof s?s:s.toString(36);var I=window[s];if(!I.toString)return;var l=""+I;window[s]=function(s,l){si=!1;return I(s,l)};window[s].toString=function(){return l}}for(var oi=0;oi<li.length;++oi)Li(li[oi]);
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})();

</script>

<script type="text/javascript" src="/TSPD/08b919fd7aab20003e4c389b6b9d3a377ba58d046d5860c6a5f51ac0cfcb4999230dafe4bf087322?type=8"></script>

<script>

(function(){
    var securemsg;
    var dosl7_common;



})();

</script>

<script type="text/javascript" src="/TSPD/08b919fd7aab20003e4c389b6b9d3a377ba58d046d5860c6a5f51ac0cfcb4999230dafe4bf087322?type=11"></script>
<noscript>Please enable JavaScript to view the page content.</noscript>
</head><body>
</body></html>

No body part … I really don't know hot to overcome this …

modified 15-May-18 6:58am.

Re: CInternetSession OpenURL

Jochen Arndt15-May-18 1:21

Jochen Arndt

15-May-18 1:21

Like before: All output is done by linked JavaScript.

If that is not shown you have to change the IE settings which probably block the execution.

But I don't know if CHtmlView supports all IE features.

Re: CInternetSession OpenURL

Randor 15-May-18 9:46

Randor

15-May-18 9:46

_Flaviu wrote:
I really don't know hot to overcome this

The javascript and/or webassembly needs to execute. Websites are not flat files anymore.

You will need to use a complete browser engine to parse the DOM. In other words most websites today are generating dynamic content via javascript. You need to think outside the box here... that javascript you see needs to execute in order to generate the page.

One quick way to do this would be using a hidden Internet Explorer window as the backend. Creating a Web Browser-Style MFC Application[^]. You could set the CHtmlView to load the site and dump the top document after javascript has modified the DOM.

Some of my tools are using a custom webkit[^] as the backend to do this. You can also use Chromium Embedded[^]. You could probably spend less than a day modifying cefsimple[^] to load the website and dump the top document to file after javascript has executed.

Good Luck.

Best Wishes,
-David Delaune

Why can't variables be declared in a switch statement

tracyhe12313-May-18 20:34

tracyhe123

13-May-18 20:34

I've always wondered this -why can't you declare variables after a case label in a switch statement? In C++ you can declare variables pretty much anywhere (and declaring them close to first use is obviously a good thing) but the following still won't work

Re: Why can't variables be declared in a switch statement

Richard MacCutchan13-May-18 20:58

Richard MacCutchan

13-May-18 20:58

You can, you just need to put them, and the code that uses them inside curly braces, thus:

C++

switch (number)
{
case 1:
    {
        int i; // local to only this case statement
    }
}

Variables not inside such a block are considered to have the scope of the entire switch block. But if they are declared in a single case statement there is a possibility that they would not get initialised safely. To make a variable available to multiple case statements it must be declared before the switch.

why passing argument by reference(&ref) in a template function shows error ? but works fine if arguments passed by pointer(*ptr) ?

Tarun Jha13-May-18 1:46

Tarun Jha

13-May-18 1:46

in the below program it i have used both ways i.e. passed arguments by reference and pointers.

1. Arguments by reference:

#include <iostream>
using namespace std;

template<class T>
void swap(T &x, T &y){
    T temp = x;
    x = y;
    y = temp;
}

void fun(int m, int n, float a, float b){

    cout << "m & n before swap: " << m << " " << n << endl;
    swap(m, n);
    cout << "m & n after swap: " << m << " " << n << endl;

    cout << "i & j before swap: " << a << " " << b << endl;
    swap(a, b);
    cout << "i & j after swap: " << a << " " << b << endl;
}

int main(){
    fun(100, 200, 11.22, 33.44);

    return 0;
}

2. Arguments by pointers:

#include <iostream>
using namespace std;

template<class T>
void swap(T *x, T *y){
    T temp = x;
    x = y;
    y = temp;
}

void fun(int m, int n, float a, float b){

    cout << "m & n before swap: " << m << " " << n << endl;
    swap(m, n);
    cout << "m & n after swap: " << m << " " << n << endl;

    cout << "i & j before swap: " << a << " " << b << endl;
    swap(a, b);
    cout << "i & j after swap: " << a << " " << b << endl;
}

int main(){
    fun(100, 200, 11.22, 33.44);

    return 0;
}

also if i pass the arguments by reference but make it a constant then also i works, why ?

#include <iostream>
using namespace std;

template<class T>
void swap(const T &x, const T &y){
    T temp = x;
    x = y;
    y = temp;
}

void fun(int m, int n, float a, float b){

    cout << "m & n before swap: " << m << " " << n << endl;
    swap(m, n);
    cout << "m & n after swap: " << m << " " << n << endl;

    cout << "i & j before swap: " << a << " " << b << endl;
    swap(a, b);
    cout << "i & j after swap: " << a << " " << b << endl;
}

int main(){
    fun(100, 200, 11.22, 33.44);

    return 0;
}

Thank you.

Re: why passing argument by reference(&ref) in a template function shows error ? but works fine if arguments passed by pointer(*ptr) ?

CPallini13-May-18 2:56

CPallini

13-May-18 2:56

You have a name clash with std::swap. Try

C++

#include <iostream>

using std::cout;
using std::endl;

template<class T>
void swap(T &x, T &y){
    T temp = x;
    x = y;
    y = temp;
}

void fun(int m, int n, float a, float b){

    cout << "m & n before swap: " << m << " " << n << endl;
    swap(m, n);
    cout << "m & n after swap: " << m << " " << n << endl;

    cout << "i & j before swap: " << a << " " << b << endl;
    swap(a, b);
    cout << "i & j after swap: " << a << " " << b << endl;
}

int main()
{
    fun(100, 200, 11.22, 33.44);
}

Re: why passing argument by reference(&ref) in a template function shows error ? but works fine if arguments passed by pointer(*ptr) ?

Tarun Jha26-May-18 9:50

Tarun Jha

26-May-18 9:50

ohh...
Thank you

Re: why passing argument by reference(&ref) in a template function shows error ? but works fine if arguments passed by pointer(*ptr) ?

CPallini26-May-18 10:53

CPallini

26-May-18 10:53

You are welcome.

problem encountered by calling constructors explicitly.

Tarun Jha11-May-18 10:20

Tarun Jha

11-May-18 10:20

here in the below program i have tried to pass the values of 1d matrix to the object of class Vector by using constructor explicit call.

#include <iostream>
using namespace std;

const int size = 3;
class Vector {
    int *v;

public:
    Vector(){
        v = new int[size];
        for(int i=0; i<size; i++)
            v[i] = 0;
    }
    Vector(int *a){
        for(int i=0; i<size; i++){
            v[i] = a[i] ;
        }

        //display();
    }
    int operator * (Vector &y){
        int sum=0;
        for(int i=0; i<size; i++)
            sum += this->v[i] * y.v[i] ;
        return sum;
    }

    void display(){
        for(int i=0; i<size; i++)
            cout << v[i] << " ";
        cout << endl;
    }
};

int main(){
    int x[3] = {1, 2, 3};
    int y[3] = {6, 3, 9};
    Vector v1, v2;

    v1 = y;
    v2 = x;

    cout << "v1 = ";
    v1.display();

    cout << "v2 = ";
    v2.display();

    cout << "v1 x v2 = " << v1 * v2 << endl ;
    return 0;
}

Quote:
cout << "v1 = ";
v1.display();

cout << "v2 = ";
v2.display();

the above portion of code doesn't works as expected it gives,

Output:

Quote:

6 3 9
6 3 9
v1 = 6 3 9
v2 = 6 3 9
v1 x v2 = 126

Expected:

Quote:
Quote:

1 2 3
6 3 9
v1 = 1 2 3
v2 = 6 3 9
v1 x v2 = 39

Thank you

Re: problem encountered by calling constructors explicitly.

Joe Woodbury11-May-18 11:39

Joe Woodbury

11-May-18 11:39

The program shouldn't run as is. In your second constructor, you aren't allocating the memory for the vector. (You also aren't deleting that memory in a destructor.)

Also note that you construct the v object in the default constructor. Since there is no assignment operator AND the second constructor is not marked explicit, it is creating a second instance of Vector and then member-wise copying that to the first, clobbering the allocation of v in the first instance. (Why your compiler is letting you get away with this is a mystery to me.)

So, add a destructor and then put "explicit" in front of the second constructor.

Then, remove the assignments and replace the declaration line with: v1(x), v2(y).

(It's still messy code, but in a debugger, you can now see how you are explicitly calling the second constructor and never the first.)

Re: problem encountered by calling constructors explicitly.

Tarun Jha11-May-18 11:57

Tarun Jha

11-May-18 11:57

thank you

Re: problem encountered by calling constructors explicitly.

CPallini12-May-18 4:13

CPallini

12-May-18 4:13

Since you know at compile time the array size, why don't you allocate it on the stack?

C++

#include <iostream>
#include <array>
using namespace std;

constexpr size_t SIZE = 3;

class Vector
{
  array<int,SIZE> x{};

public:
  Vector (const array<int,SIZE> & a)
  {
    for (size_t n=0; n<SIZE; ++n)
      x[n] = a[n];
  }

  int operator * (const Vector & v) const
  {
    int result = 0;
    for (size_t n=0; n<SIZE; ++n)
      result += x[n] * v.x[n];
    return result;
  }
  friend ostream & operator << ( ostream & os, const Vector & v);
};

ostream & operator << ( ostream & os, const Vector & v)
{
  for (const auto & i : v.x)
    os << i << " ";
  return os;
}

int main()
{
  array<int, SIZE> x{1,2,3};
  array<int, SIZE> y{6,3,9};

  Vector v1{x};
  Vector v2{y};

  cout << "v1 " << v1 << endl;
  cout << "v2 " << v2 << endl;
  cout << "v1*v2 = " << (v1*v2) << endl;
}

vs2005 Form window Error C2039

jimNLX11-May-18 6:31

jimNLX

11-May-18 6:31

I'm converting a project from VS2005 to VS2017 and have many errors:

I'm getting many errors for items not being members of System
Windows
Forms
Drawing
Panel
Button
etc....

Is there something missing from my old code or is this not available in VS2017 or is there something that wasn't included?

I think the app creates a form....

Any help to debug would be much appreciated.

Jim

Re: vs2005 Form window Error C2039

Victor Nijegorodov11-May-18 7:23

Victor Nijegorodov

11-May-18 7:23

Is it a managed C++ project type?

Re: vs2005 Form window Error C2039

jimNLX11-May-18 7:28

jimNLX

11-May-18 7:28

Yes it is

Re: vs2005 Form window Error C2039

Victor Nijegorodov11-May-18 8:07

Victor Nijegorodov

11-May-18 8:07

Then it would be better to post in the Managed C++/CLI Forum.

Why do I need typecast hex?

Vaclav_11-May-18 5:18

Vaclav_

11-May-18 5:18

This is silly , but most I/O devices spec sheets data are written as "hex".
If I want to pass this
char *TXBuffer = (char*) 0x04;
to a function it has to be type casted.

Like so
<pre lang="c++">

char *TXBuffer = (char*) 0x04;
int *TEST = (int*)0x04;</pre>

If not I'll get "invalid conversion".

Cheers
Vaclav

Re: Why do I need typecast hex?

Richard MacCutchan11-May-18 6:25

Richard MacCutchan

11-May-18 6:25

Vaclav_ wrote:
char *TXBuffer = (char*) 0x04;

No you don't need to do that, and you shouldn't because it is wrong. You are trying to pass the value 0x04 as the buffer address, which will cause an access violation.

If you need a buffer containing the hex value, and you want to send that buffer's address to a function then you need to do one or other of the following:

C++

unsigned char TXBuffer = 0x04; // a single character
function(&TXBuffer); // use the addressOf operator to pass the address of the character to the function 

// or

unsigned char TXBuffer[] = { 0x04, 0 }; // multiple characters
function(TXBuffer); // TXBuffer is an array, so its name will be translated to its address by the compiler.


// the receiving function should be coded as
xxx function(unsigned char* buffer)
{
    // xxx is the return type
    // the function must know how many characters will be sent in the buffer
    // either a number that is always the same, or the length passed as a second parameter.
    // to access items from the buffer you use:
    unsigned char value = *buffer; // get the first value
    buffer++;                      // increment the pointer to the next element (if more than 1)
    value = *buffer;               // get the next value 
}

Re: Why do I need typecast hex?

Vaclav_11-May-18 6:34

Vaclav_

11-May-18 6:34

Thanks Richard, you are a pal.
Appreciate your comments.

const char [] and char[] difference question

focusdoit10-May-18 14:26

focusdoit

10-May-18 14:26

Hi, I wrote a small c program on a microcontroller, 32bit.

I met a weird problem.

I wrote code like:

C++

const char strtest[] = "Test123\r\n"; //Global
UART_print(strtest); //in a loop

the output is fine, I can see the output on Teraterm(RS232 interface tool), like:
Test123
Test123
..

But when I try code:

char str123[] = "Test123\r\n";  //Global
UART_print(strtest); //in a loop

The output is only the first element:
TTTTTTTT

Any hint is appreciated.

Re: const char [] and char[] difference question

David Crow10-May-18 17:22

David Crow

10-May-18 17:22

focusdoit wrote:
char str123[] = "Test123\r\n"; //Global
UART_print(strtest); //in a loop

Where is str123 used?

What is the signature of UART_print()?

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