C / C++ / MFC

AtineshS wrote:

On running it, I have noticed that it consumes lots of RAM (Memory).

Anonygeeker wrote:

But I am getting segmentation fault. Why?

char *a[]={"abc","xyz","lmn","NULL"};

printf("%c\n",a[i]);

printf("%s\n",a[i]); // use s to print a character aray

char *b; // what does this point to?
int l;
printf("\nenter string to find\n");
fgets(b,MAX,stdin); // but b does not point to anything
printf("%c",*b); // again %c means a single character

char b[MAX];
int l;
printf("\nenter string to find\n");
fgets(b,MAX,stdin);
printf("%s",b);

Richard MacCutchan wrote:

although I may have missed other mistakes

int srch(char *a[],char *b)
{
    int i,r=0;
    for(i=0;a[i];i++){
        printf("%c\n",a[i]);
        if(!strcmp(a[i],b)){
            return 0;
        }
        else{
            return -1;
        }
    }
}

#include <stdio.h>
#include <string.h>
#define MAX 10

int srch(const char *a[],char *b)
{
  int i = 0;
  while ( a[i] != NULL)
  {
    if ( ! strcmp( b, a[i]) ) return i;
    ++i;
  }
  return -1;
}


int main()
{
  int index; 
  const char *a[]={"abc","xyz","lmn", NULL};
  char b[MAX];
  printf("\nplease, enter string to find\n");

  if ( fgets(b, MAX, stdin) )
  {
    // remove the newline 
    for (index = 0; index < MAX; ++index)
      if ( b[index] == '\n')
      {
        b[index] = '\0';
        break;
      }
    
    printf("string to find '%s'\n",b);
    index = srch( a, b);
    if ( index != -1 )
      printf("string found at index = %d\n", index);
    else
      printf("string not found\n");
  }
  return 0;
}