C / C++ / MFC

CFirstDialog
{
public:
    // ...
    const CString& GetFileName() const { return m_strFileName; }
protected:
    // ...
    CString m_strFileName;
};

void CFirstDialog::OnEnChangeMfceditbrowse1()
{
    m_browser.GetWindowText(m_strFileName);
}

CSecondDialog
{
public:
    // ...
    void SetFileName(const CString& strFileName) { m_strFileName = strFileName; }
protected:
    // ...
    CString m_strFileName;
};

void CSecondDialog::OnBnClickedOk()
{
    CParentOfDialogs *pParent = static_cast<CParentOfDialogs*>(GetParent());
    // Use pParent here to get the stored name or retrieve it from the first dialog
    CString strFileName = pParent->m_pFirstDialog->GetFileName();
}

Jochen Arndt wrote:

If both dialogs might not exist at the same time you have to store the file name in a member variable of that class (e.g. get the name when DoModal() returns).

void CInputView::OnFirstDlg()
{
	// TODO: Add your command handler code here
	CInputDoc* pDoc = GetDocument();
	CFirstDialog DialogWindow;
        //.....
        CSecondDialog *pDlg = new CSecondDialog(this);
        //...
        pDlg->DoModal();
        delete pDlg;
}

void CMyView::OnSecondDlg()
{
	// TODO: Add your command handler code here
	CMyDoc* pDoc = GetDocument();
	CSecondDialog DialogWindow;
	DialogWindow.DoModal();
	
}

void CInputView::OnFirstDlg()
{
    CFirstDialog DialogWindow;
    DialogWindow.DoModal();
    // Get file name here before DialogWindow goes out of scope
    m_strFileName = DialogWindow.GetFileName();
    // Or (when DialogWindow.m_strFileName is public): 
    //m_strFileName = DialogWindow.m_strFileName
}

CSecondDialog DialogWindow;
// Pass file name before calling DoModal()
DialogWindow.SetFileName(m_strFileName);
DialogWindow.DoModal();

// With class member CSomeDialog *m_pSomeDlg
if (NULL == m_pSomeDlg)
{
    m_pSomeDlg = new CSomeDialog(this);
}

z=x++ - --y *b/a;
x(++) - ((--y) *b / a);
5 - (-11 * 2 / 4)
5 - (-22 / 4)
5 - (-5) // integer arithmetic ignores remainder
10

z = (x++) - (((--y) * b) / a);

z = (5++) - (((--(-10)) * 2) / 4);

z = (5) - ((-11 * 2) / 4);
z = 5 - (-22 / 4);
// The remaining steps are left to your exercise

parkavikkk wrote:

int z, x=5, y= -10, a=4, b=2;
z=x++ - --y *b/a;
Can anyone please solve it and explain the precedence. i am not getting right answer. my answer is 2.5. but it is wrong.