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mrby123 wrote:
fscanf_s(f_ptr_seed_inf,"%s\n",ftitle[ifl].GetBuffer(MAX_PATH));
How does this even compile? I would have expected a C2228 error.
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"Show me a community that obeys the Ten Commandments and I'll show you a less crowded prison system." - Anonymous
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As Richard said, I've already answered this question.
You need to change the fscanf_s line as follows -
fscanf_s(f_ptr_seed_inf,"%s\n",ftitle[ifl].GetBuffer(MAX_PATH), MAX_PATH);
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I have read a lot about abstract class, but still have questions, as I have not really used in my c++ code practically.
What is the use of abstract class ? Any sample I can take a look at ?
Thanks.
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AdvancedCPP wrote:
What is the use of abstract class ?
class Shape
{
public:
Shape( int nWidth, int nHeight )
{
m_nWidth = nWidth;
m_nHeight = nHeight;
}
virtual double getArea() = 0;
protected:
int m_nWidth;
int m_nHeight;
};
class Circle : public Shape
{
public:
Circle( int nWidth, int nHeight ) : Shape(nWidth, nHeight) {};
double getArea()
{
int nRadius = m_nWidth / 2;
return 3.1415962 * nRadius * nRadius;
}
};
class Square : public Shape
{
public:
Square( int nWidth, int nHeight ) : Shape(nWidth, nHeight) {};
double getArea() { return m_nWidth * m_nHeight; }
};
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"Show me a community that obeys the Ten Commandments and I'll show you a less crowded prison system." - Anonymous
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One of the points of an abstract class is you'd never create one (e.g. shape in example) - you can't create a 'shape' (what would it look like?) it has to be a circle or a square (as in the example) or some other real thing. But you do create objects that inherit from (use the code in) an abstract class. So the advantage is you only have to write the abstract class code (shape in the example) once, no matter how many different actual concrete classes which inherit the class, you can create such as square, circle etc all which inherit from it.
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AdvancedCPP wrote: I have not really used in my c++ code practically
You have either to change that or your nickname.
Veni, vidi, vici.
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I am creating an application that is multithreaded and all the threads are accessing the same shared memory. The data coming into the memory should be processed in sequential order. Like if 1,2,3,4,5 comes in the memory then it should be processed in same order.
I have used critical section around my memory, but I still get into a race condition where data is not grabbed by the thread in sequential order.
Am I missing anything else to prevent threads from race condition?
Thanks.
ACpp
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Yes, you are.
Google 'multi thread patterns'.
It is a long path, but when you arrive, you're likely to feel it was worth it.
Pablo.
"Accident: An inevitable occurrence due to the action of immutable natural laws." (Ambrose Bierce, circa 1899).
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Can I run two command line instructions on a file in a VS2008 project? I can set each command line instruction up as a rule in the .rules file (see below) but can only select one rule or the other not both. From the input files properties in VS2008 Project View I can select GraphVizSVGRule or GraphVizPNGRule. I want to create both a .svg file and a .png file from the input .gv file (GraphViz)
="1.0"="utf-8"
<VisualStudioToolFile
Name="GraphViz Rule File"
Version="8.00"
>
<Rules>
<CustomBuildRule
Name="GraphViz Dot to SVG Rule"
DisplayName="GraphVizSVGRule"
CommandLine="dot.exe -T svg "$(InputDir)\$(InputName).gv" -o "$(InputDir)\images\$(InputName).svg""
Outputs="$(InputDir)\images\$(InputName) .svg"
FileExtensions="*.gv"
ExecutionDescription="builds svg file"
>
<Properties>
</Properties>
</CustomBuildRule>
<CustomBuildRule
Name="GraphViz Dot to PNG Rule"
DisplayName="GraphVizPNGRule"
CommandLine="dot.exe -T png "$(InputDir)\$(InputName).gv" -o "$(InputDir)\images\$(InputName).png""
Outputs="$(InputDir)\images\$(InputName) .png"
FileExtensions="*.gv"
ExecutionDescription="builds png file"
>
<Properties>
</Properties>
</CustomBuildRule>
</Rules>
</VisualStudioToolFile>
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The only method I have found to run more than one is to create a command script that accepts parameters, so you can pass in the file and directory names.
Use the best guess
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Thanks, it's now working with the below as you suggested.
Rule that calls batch file:
<CustomBuildRule
Name="GraphViz Dot to PNG and SVG"
DisplayName="GraphVizPNGSVGRule"
CommandLine="images "$(InputDir)\$(InputName).gv""
Outputs="$(InputDir)\images\$(InputName).png;$(InputDir)\images\$(InputName).svg;"
FileExtensions="*.gv"
ExecutionDescription="builds png and svgfile"
>
<Properties>
</Properties>
</CustomBuildRule>
Batch file that creates svg and png from GraphViz gv file:
echo off
set "p=%~dps1"
set "px=Images\"
set "newp=%p%%px%"
set "newsvg=%newp%%~n1%.svg"
set "newpng=%newp%%~n1%.png"
set "source=%~s1"
echo Creating svg...
dot.exe -T svg %source% -o %newsvg%
echo Creating png...
dot.exe -T png %source% -o %newpng%
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Hello Friends
Application is Compiled on VS2010 in WinXp and it is crashing on Win8 when ivoked by Menu not crashing by shortcuts.
Isn't issue with running application on 64 bit Machine ?
Reagrds
Y
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You are not really providing us with enough information here and I am not sure I understand the difference between launching the application from a menu versus from a shortcut.
However, I think it could be because the shortcut is setting the applications startup folder to be the installation folder, whereas that is not being done when it is launched from the menu.
Soren Madsen
"When you don't know what you're doing it's best to do it quickly" - Jase #DuckDynasty
modified 7-Jun-13 7:32am.
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You will need to provide a lot more information than the above if you want some assistance. Try getting some debug information and show the failing code.
Use the best guess
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I am opening a simple Dialog on Menu->SubMenu And also using keyboard Shotcut too.
But, When I Click on Ok of that Dialog ,it completes its execution and then go to Dissembly.
But If I do same process using Keyboard shortcut then everything is fine.
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I see that I guessed completely wrong when I thought I understood what you were saying. You can disregard my answer as it obviously has nothing to do with that.
Soren Madsen
"When you don't know what you're doing it's best to do it quickly" - Jase #DuckDynasty
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You really should know by now that we cannot guess what is happening in your cpode, nor can we see your screen. Please edit your question and provide some proper technical information.
Use the best guess
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Sorry, but I don't think anyone is likely to be downloading that and doing your job for you.
Use the best guess
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hi guys.. I have written the below code in C. I have 3 bits in three different integer variables. How can I concatenate those values assuring that i need only binary values (1/0).
#include <stdio.h>
#include "manojturbo5.h"
#include "bitsconv.h"
#include "manojencoder2.h"
void main()
{
int message,interleaver,u,p,q,r,final,result,i;
printf("Enter the message\n");
scanf("%d",&message);
bitconv (message);
for(r=0;r<32;r++)
{
u = array[31-r];
p = encoder(array[31-r]);
q = encoder2(array[31-r]);
printf("%d\t %d\t %d\n",u,p,q);
}
return;
}
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Do you really think you will get any different answers than here[^], which you all didn't seem to like?
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I cannot use shifting operator because it will give numbers other than 1/0. If I shift it once i will get 2. I dont want that. I need only binary (1/0).
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Manoj7390 wrote: I cannot use shifting operator because it will give numbers other than 1/0. <layer>
that makes no sense at all.
Manoj7390 wrote: If I shift it once i will get 2.
1 = 00000001 (in binary)
1 << 1 = 2
2 = 00000010 (in binary)
you might benefit from reading about binary math and how computers store numbers.
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I was reading the previous thread and I think the problem you are having is understanding the difference between storing the values and using the values.
Richard showed you how to pack the three binary values into a single integer:
int Answer = (u << 2) | (p << 1) | q
That is for storing them. Don't worry about the actual value of Answer. When you need to use the binary values, you have to unpack them. There are different ways to do it, but I think this method is the easiest way for you to understand it:
q = Answer & 1;
p = (Answer >> 1) & 1;
u = (Answer >> 2) & 1;
Soren Madsen
"When you don't know what you're doing it's best to do it quickly" - Jase #DuckDynasty
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