C / C++ / MFC Discussion Boards

Please note you are passing the address of inName that is already a pointer to a sockaddr struct.
Change:

vkgktm wrote:
int iResult = orig_connect(s, (struct sockaddr*)&inName, sizeof(inName));

to

C++

int iResult = orig_connect(s, inName, sizeof(*inName));

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke

[My articles]

Hi CPallini,
Thanks for your reeply..
I changed
int iResult = orig_connect(s, (struct sockaddr*)&inName, sizeof(inName));

to
int iResult = orig_connect(s, inName, sizeof(*inName));

But i am getting the error message
error C2664: int (SOCKET,const sockaddr *,int) : cannot convert parameter 2 from sockaddr_in to const sockaddr

try

C++

int iResult = orig_connect(s, (const sockaddr *) inName, sizeof(*inName));

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke

[My articles]

i am still getting the same error 10014

Well, in order to get better help, can you please provide a link to the documentation of the orig_connect function? I cannot find anything about on the web.

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke

[My articles]

hi Now that error gone i am able to connect to proxy but from the proxy i am getting the message Request denied what it means..where is the error..

"But all I can do is hand it to you": Google search for "proxy request denied"[^].

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke

[My articles]

hi thanks for your replies it helped me a lot thanks.

You are welcome.
Smile | :)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke

[My articles]

Hi,

I want to get handle of an already opened window.

For this

I can not use FindWindow() API as Window's title is not known.

And also, I can not use Class name as it is not a registered class.

Can anybody tell me how to solve this issue?

Thanks in advance.

Regards
MSR

As far as I know, every window must belong to a registered class.

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke

[My articles]

Hi, thanks for the reply.

But here we are not regidtering class explicitly. This is the code

CDlg* pDlg = new CDlg;

DialogBoxParam(hInt, MAKEINTRESOURCE(IDD_DLG),
                        hWnd, (DLGPROC)(*pDlg ).WindowMapProc, (LPARAM)pDlg);

I have tried using

FindWindow("CDlg", NULL);

But it is not working.

Now , how to go forward to find IDD_DLG.

Regards
MSR

Your windows is child of the hWnd one and as such must be searched for.

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke

[My articles]

Use

EnumWindows
EnumChildWindows

and look for #32778 class name

use the SPY++ to test it

Mithrill $Shucks | :-\$

CDlg is the class which creates the dialog window and must use some Windows classname, either one of the predefined classes, or a new one registered before creation. What is the base of CDlg?

[edit]It is also likely that the dialog will contain a title that you can search for.[/edit]

Unrequited desire is character building. OriginalGriff

The DialogBoxParam function automatically assigns the predefined class name "#32770" (i.e. dialog box, see here[^]) to the newly created dialog.

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke

[My articles]

I think the OP would like to know this. Wink | ;)

Unrequited desire is character building. OriginalGriff

So let he/she know. Big Grin | :-D

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke

[My articles]

Hi, CDlg is derived from CDlgSlct.

I have tried using the base class also.

But of no use.

Regards
MSR

And what is CDlgSlct derived from? You should know and understand your inheritance tree. In either case see the message from CPallini which tells you what identifier to use for the Dialog windows class.

Unrequited desire is character building. OriginalGriff

Just to be clear, a C++ class should not be confused with a windows class.

Use Spy++, it will tell you the (windows) class name of any window you care to query. Do this to a dialog, and you'll see the name that cPallini provided - the same class-name that you should use with FindWindow.

To that end, which C++ class you inherit from is somewhat irrelevant. You just need the windows class name for a dialog box.

Use WindowFromPoint Api if you know approx location in x,y cords
this returns handle

e.g.

C#

[DllImport("user32.dll")]
static extern IntPtr WindowFromPoint(POINT Point);

The trick is making sure unknown application starts in a known place.

Regards

David Rathbone

Not to mention it musn't be covered by any other window...i doubt this method would be reliable.

> The problem with computers is that they do what you tell them to do and not what you want them to do. <
> If it doesn't matter, it's antimatter.<

Hello,
I have a (maybe small) problem that is driving me mad.
I am using a CHtmlView derived class to display a html file that is stored locally on the PC. I'm using Navigate2() for that. On Windows XP machines everything works fine but Windows 7 always opens a new IExplorer window instead of displaying the file in my view. I tried to override OnNewWindow2() but the according event does not occur.
I use the following code in the OnInitialUpdate() function of the view:

C++

CString fileName = theApp.m_sSettingsPath + CString("Certificate\\certificate.htm");
Navigate2(fileName);

I've also tried the "file://" syntax, but same behaviour.

Thank's for your help,
Ralf

You need to use the extra options (dwFlags and lpszTargetFrameName) in the Navigate2()[^] call, as described here[^].

Unrequited desire is character building. OriginalGriff