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Hi, from what I can see the socket is not doing anything or you did not post the full code. The server socket never calls listen or accept. Maybe you could provide us more information? In a nutshell there a three possible designs for a server: your server handles one client at a time (example), uses asynchronous I/O (multiple connections in a single thread context) or uses multi threading (one connection per thread).
Here are some links that might come helpful:
- Internet / Network - CodeProject[^]
- Beej's guide to networking programming[^]
- Winsock Programmer's FAQ[^]
Last two have working client/server examples in section 6. Hope it helps 
/M
Webchat in Europe ![Java | [Coffee]](https://codeproject.global.ssl.fastly.net/script/Forums/Images/coffee.gif) Now with 26% more Twitter
modified on Monday, April 5, 2010 5:40 AM
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this application execute this line : ExecuteCommand(buffer, NULL, 0) but only one time.
I will check your links
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Could you please format your code with <pre> tag for readability and remove the French comments? It was quite hard to read.
Looking again at your code, you have a blocking UDP socket waiting for a connection, which calls ExecuteCommand() and exists the thread? Perhaps all you are looking for is a for loop (and a way to programatically exit the worker thread)?
/M
Webchat in Europe Now with 26% more Twitter
modified on Monday, April 5, 2010 9:10 AM
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Think you for your help. I removed the comments and used
. I hope it's easier to read.
yes, you're right, I want to add a loop but I don't where in my code.
Think you
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Okay thanks for the formatting!
Let my try to help.... put the loop around the blocking part (pseudocode):
socket();
bind();
for(;;)
{
recvfrom();
if(ok) ExecuteCommand();
}
closesocket();
Right now the worker thread has no exit condition, you probably want to add one in order to avoid terminating the thread the hard way at application exit. Also have a look at some other issues, e.g. starting from this line
nb_caracters=recvfrom(socket_recevoir,buffer,1515,0,(struct sockaddr*)&information_recevoir,&tempo);
should become something like
int nb_caracters = recvfrom(socket_recevoir, buffer, sizeof(buffer)-1, 0, (struct sockaddr*)&information_recevoir, &tempo);
if(nb_caracters > 0)
{
buffer[nb_caracters] = 0;
ExecuteCommand(buffer, NULL, 0);
}
Webchat in Europe Now with 26% more Twitter
modified on Monday, April 5, 2010 3:34 PM
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is it possible to give different colors for each row in Listview..
ie blue for the contents in first row
red for 2nd
and so on
thanks in advance.
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As far as i know you can only do that by using an owner-drawn list control and drawing the rows yourself or you can use some pre-made "extended" list control, like CListCtrlEx[^].
> The problem with computers is that they do what you tell them to do and not what you want them to do. <
> Sometimes you just have to hate coding to do it well. <
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I all
I got one example from planetsourcecode.When i compile these code then i am geeting error please help me.
#include "stdafx.h"
#include<stdlib.h>
#include<stdio.h>
#include<conio.h>
#include<string.h>
int _tmain(int argc, _TCHAR* argv[])
{
char *s;
int i,l,*a,f,c,x;
printf("Enter a string : ");
scanf("%s",s);
l=strlen(s);
s[l]=0;
a=(char*)malloc(l);
for(i=0;i<l[i++]=0);
f=1,c=0;
while(f)
{
x=l-1;
a[x]=c++;
for(i=0;i<l&& c-1<l;i++)
printf("%c",s[a[x]]);
if(i>=l)
printf("\n");
while(a[x]>=l)
{
a[x]=c=0;
if(x<0){f=0;break;}
a[x]++;
}
}
printf("Completed");
return 0;
}
Error
error C2440: '=' : cannot convert from 'char *' to 'int *'
error C2109: subscript requires array or pointer type
error C2143: syntax error : missing ';' before ')'
Please help me
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You can seee the error...
Now decide why?
int i,l,*a,f,c,x;
printf("Enter a string : ");
scanf("%s",s);
l=strlen(s);
s[l]=0;
<big>a=(char*)malloc(l);</big>
Величие не Бога может быть недооценена.
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yes i know there is error.When i change Int *a to CHAR *a.But still i have two error.
Error
error C2109: subscript requires array or pointer type
error C2143: syntax error : missing ';' before ')'
If you know solution or condition then please help me
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I cannot get the this code?
Surely having problem, but whether it is related to your code or formating error, please check these things, you can solve these issues.
These are just syntax errors.
for(i=0;i f=1,c=0;
Величие не Бога может быть недооценена.
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Thanks for reply
I have change in code then runing well.Please check it.
#include "stdafx.h"
#include<stdlib.h>
#include<stdio.h>
#include<conio.h>
#include<string.h>
int _tmain(int argc, _TCHAR* argv[])
{
char *s,*a;
int i,l,f,c,x;
printf("Enter a string : ");
scanf("%s",s);
l=strlen(s);
s[l]=0;
a=(char*)malloc(l);
for(i=0;i<l;i++);
f=1,c=0;
while(f)
{
x=l-1;
a[x]=c++;
for(i=0;i<l && c-1<l;i++)
printf("%c",s[a[x]]);
if(i>=l)
printf("\n");
while(a[x]>=l)
{
a[x]=c=0;
if(x<0){f=0;break;}
a[x]++;
}
}
printf("Completed");
return 0;
}
Error
Run-Time Check Failure #3 - The variable 's' is being used without being initialized.
Please help me
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Here, i think you have to help yourself, by learning the syntax of C.
I prefer you to read a C programming book to get throught with syntax.
See in your code, you cannot use scanf as you wish, it is expecting the address of s. so your compiler is complaining
scanf("%s",s);
Expected code is
scanf("%s",&s);
Величие не Бога может быть недооценена.
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Thanks for reply
Now i am getting exception in line s[l]=0;
Unhandled exception at 0x1026f8bc (msvcr90d.dll) in TestingProject.exe: 0xC0000005: Access violation reading location 0xcc006975.
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try this
char *s = new char;
 Failure is Success If we learn from it!!
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I have change in code char *s = new char(230)
Still i have same exception.
Please help me
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no, no, no .... That's not the way to go!
You put some code with some syntax error and even some misconception in it.
That reveal that you are not understanding what your code has to do.
The compiler just gives some errors, but those errors are random as your code is. Attempting to fix those errors doesn't lead anywhere: you're never granted your code will do what you expect.
For example:
char *s;
int i,l,*a,f,c,x;
printf("Enter a string : ");
scanf("%s",s);
s is a pointer pointing to nowhere: where do ypu thoing your scanf can write to ?!?
s[l]=0; tries to write to nowhere since s is nowhere
a is a pointer to int, but you do a=(char*)malloc(l): what did you want to do? allocating char-s or int-s ?!
for(i=0;i
f=1,c=0;
while(f)
This is a mess of tokens with no syntax meaning! Raed about the for syntax, and understand the proper use of '()', ',', and ';'.
x=l-1 Wow... you're looking for problems: never use names like "O" and "l": I have to change font before find it's "l-1" and not "l-l" ... Do you get what I mean? If not, than that demonstrate the problem
Then: I see a malloc, but i don't see a free: not a good way to program...
I don't continue, but what can you do if you don't have clear in your mind what you're gonna do?
2 bugs found.
> recompile ...
65534 bugs found.
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Thanks for vital information and suggestion.
I want to generate Combination of given String.Like this CString test="ABC", then generate like this
AB
AC
AA
BB
BC
BA
CC
CA
CB
If you have any type solution or suggestion then please help me.
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Ok, that's the problem. Now try to come to an algorithmic solution.
That doesn't need to be C or C++, just pseudocode.
Only when you find your algorithm looks meaningful, try to code it!
Than: the problem is not well formed. Do you want only two char-s combination? Does the input string needs to be 3 char-s wide or can it be whatever?
Be sure about that: you risk to produce a code that works on a very specific case, while looking for something more generic.
2 bugs found.
> recompile ...
65534 bugs found.
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yes you right.You have any idea about such type of algo because i havn't found algo.Please help me
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no, I cannot do your homework.
2 bugs found.
> recompile ...
65534 bugs found.
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you don't do my home work just i want to know url link or forum name.i know why you do my home work.
thank
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You can use casting, I know it's available in C++.
Don't know about C, does it have to be C or C++?
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thank for make comment but sorry can you describe in detail.What's not available? please describe in detail.
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