C / C++ / MFC

Richard MacCutchan11-Sep-09 1:42

Richard MacCutchan

11-Sep-09 1:42

rajugis wrote:
Getpixel and setpixel methods are too slow

Too slow for what? Please explain what you are trying to achieve.

rajugis wrote:
and plz give me one samples

We have no idea what you are trying to achieve, nor what you have tried. Be specific about which part of your program does not work.

Game-point11-Sep-09 1:58

Game-point

11-Sep-09 1:58

I have one image file ..which contains the buildings i want to cut top of left corner building ..

before that i have read image in pixel - by - pixel so that its very slow ..

~~~~~~~~~~~~~Raju~~~~~~~~~~~~~

Maximilien11-Sep-09 2:34

Maximilien

11-Sep-09 2:34

What is the criteria to cut/crop the image?

Seems to be a hassle to look for pixels details to do that ?

This signature was proudly tested on animals.

Adam Roderick J11-Sep-09 2:41

Adam Roderick J

11-Sep-09 2:41

just check the below links, i think you are looking for these things
CImage with Performance[^]

and one more, more info about cropping and cutting CxImage[^]

Величие не Бога может быть недооценена.

Beginner's Question [modified]

kilt14-Sep-09 2:22

kilt

14-Sep-09 2:22

You must use DIBS (see for hundreds of code samples in C, advanced)[^]

UKM_Student11-Sep-09 1:10

11-Sep-09 1:10

Hmm guys,is it possible to display number1+ number2+number3?

Eg,if a program prompts a user to input 3 numbers,N1,N2 and N3,is it possible for the program to display N1+N2+N3?As far as i know,we can use a while loop to straight away give us the final answer for N1+N2+N3.

To make it clear,if i input 5 as N1,10 as N2 and 15 as N3,can we make the program display
"total=5+10+15=30" instead of "total=30"?

Can someone guide me on this. xD

modified on Friday, September 11, 2009 10:31 AM

Mattias G11-Sep-09 1:13

Mattias G

11-Sep-09 1:13

What have you tried so far? http://mattgemmell.com/2008/12/08/what-have-you-tried[^]

Re: Beginner's Question [modified]

Richard MacCutchan11-Sep-09 1:32

Richard MacCutchan

11-Sep-09 1:32

UKM_Student wrote:
Im currently writing a program which prompts the computer to calculate the sum of even integers between 2 numbers,namely Number_1 and Number_2.Anyone can help me with this?

Yes, lots of people but they may want to be paid for the effort. This is your program so you must at least try and make a start on it. Have you read this[^], especially point 2?

UKM_Student11-Sep-09 2:00

11-Sep-09 2:00

Ok this is what i have tried so far since 2.5 hours ago...and failed >.<

#include<iostream>
using namespace std;
int main()
{

cout<<"c. The total sum of even integers between "<<firstNum<<" and "<<secondNum<<" is : ";
int total=0;
if(firstNum%2==0)
do
{
total=total+firstNum+2;
cout<<total;
firstNum=firstNum+2;
}while(firstNum<secondNum);

PS i chose the if(firstNum%2==0) to show that if the 1st value is an even number,that loop is to be executed.For The part where the first integer is an odd number,i should be able to write that program after you guys can help me solve the even number part Big Grin | :-D

modified on Friday, September 11, 2009 8:08 AM

Adam Roderick J11-Sep-09 2:32

Adam Roderick J

11-Sep-09 2:32

I dont like to give solution so easily to u since you are beginner and if i do so it will be mistake from my side, but since you have already spend more than 2 hours Smile | :)

I appreciate your patience Smile | :)

So here is the solution Smile | :)

But please try to understand and do it .

cin>>firstNum;
cin>>secondNum;
cout<<"c. The total sum of even integers between "<<firstNum<<" and "<<secondNum<<" is : ";

int total=0;
while( firstNum < secondNum )
{
	if( 0 == firstNum%2 )
	{
		total += firstNum;
	}
	firstNum++;
}
cout<<total;

Величие не Бога может быть недооценена.

CPallini11-Sep-09 2:09

11-Sep-09 2:09

And what is your doubt?
(while statement knowledge should be enough for the task).
Smile | :)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler.
-- Alfonso the Wise, 13th Century King of Castile.

This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong.
-- Iain Clarke

[My articles]

UKM_Student11-Sep-09 2:12

11-Sep-09 2:12

the doubt is i can't seem to execute the program >.<

Eg,if i put number1 as 2 and number2 as 10,instead of showing the value of 18,ie.(4+6+8),it shows 4101828

CPallini11-Sep-09 2:32

11-Sep-09 2:32

Your (revised) code

#include <iostream>
using namespace std;
int main()
{
  int firstNum = 2, secondNum = 10;
  int k;
  
  int total = 0;
  k = firstNum + 1;
  if (k % 2 == 1) k++;
  while (k < secondNum)
  {
    total = total + k;
    k += 2;
  }
  cout << "c. The total sum of even integers between " << firstNum << " and " << secondNum << " is : " << total;
}

UKM_Student11-Sep-09 2:41

11-Sep-09 2:41

Erm thanks but do u mind explaining the part where u said
if (k % 2 == 1) k++;???

And i thought that "if statement" needs to be paired with an "else"?

CPallini11-Sep-09 2:51

11-Sep-09 2:51

UKM_Student wrote:
if (k % 2 == 1) k++;???

if k is odd (an odd number modulus 2 gives 1) then increment k (i.e. k=k+1) to make it even.
(Just in case firstNum is odd).

UKM_Student wrote:
And i thought that "if statement" needs to be paired with an "else"?

Actually the else clause is optional in the if statement, see, for instance, here.
Smile | :)

UKM_Student11-Sep-09 2:59

11-Sep-09 2:59

Erm it says that "If the value of expression is nonzero, statement1 is executed. If the optional else is present, statement2 is executed if the value of expression is zero."

So what happens if the value of expression is zero and the optional else is NOT present?Will the compiler even able to compile it?Or will the compiler able to compile it but instead execute the If statement?Or nothing happens at all?

Oh and thanks for your help. Smile | :)

UKM_Student11-Sep-09 3:04

11-Sep-09 3:04

And i got another question if u are free to help >.<

I nid to display number 1-10 and their squares.I managed to display the 1-10 part but couldn't display their squares >.<.The output should be smth like this Big Grin | :-D

1 1
2 4
3 9
4 16
5 25
6 36
7 49
8 64
9 81
10 100

This is what i got so far xD

cout<<"d. Display the numbers 1-10 and their squares."<<endl;

int integer=1;

while(integer<=10)
{
cout<<integer<<endl;
integer++;
}

CPallini11-Sep-09 3:15

11-Sep-09 3:15

Well, you know, squaring a number means multiplying it by itself... Roll eyes | :rolleyes:

UKM_Student11-Sep-09 3:17