C / C++ / MFC

trioum wrote:

send me chunck of code

int <font color=red>a</font> = 1;

a += ( <font color=red>a</font>+= 3, <font color=gray>5, a</font> );

a += ( <font color=red>a</font>+= 3 ); //(Anything after the first comma will be ignored by the compiler. See <a href="http://msdn.microsoft.com/en-us/library/t29e07xd(VS.80).aspx">Sequential evaluation operator</a>[<a href="http://msdn.microsoft.com/en-us/library/t29e07xd(VS.80).aspx" target="_blank" title="New Window">^</a>]

a += ( a = <font color=red>a</font>+3) //but a was delcared 1, so the expression <font color=red>a</font>=1+3 makes RHS value as 4.

a += a; //But <font color=red>a</font> is 4 now before executing this statement.
        //Therefore adding another 4, the resultant  a = 8. Makes perfect sense to me.

shubhi wrote:

In AS/400’s C showing output: 5

shubhi wrote:

then it will evaluate b+=2 but a will get the value 2, as I m using the braces here.

shubhi wrote:

a += ( a+= 3, 5, a ); //a=1

Rajesh R Subramanian wrote:

a cannot get the value 2, because the expression b+=2 will be executed before it is assigned to a, for the very reason that it is inside braces. Therefore, the value of a would be b+2.

Anoop Dashora wrote:

But not sure of AS/400 C Compiler. Might be it is evaluating as:-

a+=(a+=3.5,a)
a=a+(a=a+3,5,a)
a=1+(4,5,4)
a=5 // But i am not sure with this explanation.

shubhi wrote:

a=(b+=2,5,2)

then it will evaluate b+=2 but a will get the value 2, as I m using the braces here.