C / C++ / MFC

_AnsHUMAN_ wrote:

wchar_t *wCharBuff = new wchar_t[strlen(str)+1];

Rajesh R Subramanian wrote:

You're sure that's right? Smile

Rajesh R Subramanian wrote:

It's been almost six months since he's asking this kind of questions.

You need to google first, if you have "It's urgent please" mentioned in your question.
_AnShUmAn_

_AnsHUMAN_ wrote:

yeah! +1 would stand for the delimiter

"_$h@nky_" wrote:

i m using this function wcstombs

CPallini wrote:

Well, your sentence adds just a bit of confusion to my understanding of the problem.

// Declare a type for the function we want to load.
typedef int (*pTest)(int);
// Function that tries to get a nfunction named Test from the DLL we pass it.
pTest GetTestFnFromDll(LPCTSTR dllName)
{
   // Load the DLL
   HMODULE hDll = LoadLibrary(dllName);
   if (!hDll) return 0;
   // Get the function address
   return (pTest)GetProcAddress(hDll, "Test");
}

int main()
{
   // Use first.dll!Test
   pTest aTestFn = GetTestFnFromDll(_T("first.dll"));
   if (aTestFn)
      std::cout << aTestFn(10) << std::endl;

   // Use second.dll!Test
   pTest aSecondTestFn = GetTestFnFromDll(_T("second.dll"));
   if (aSecondTestFn)
      std::cout << aSecondTestFn(10) << std::endl;

   return 0;
}

Rajesh R Subramanian wrote:

Seriously though, how can three different DLLs export functions with the same exact name?

Stuart Dootson wrote:

So, yeah, it's a valid design pattern - whether or not the OP actually meant to do that is another matter, of course

char test[] = { 'C', ':', 92, 't', 'e', 's', 't', '.', 'j', 'p', 'g', 0 };