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Simple. Don't allow Guest to use TRIAL version of your software.
Yusuf
Oh didn't you notice, analogous to square roots, they recently introduced rectangular, circular, and diamond roots to determine the size of the corresponding shapes when given the area. Luc Pattyn[^]
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Not Dear You can't Bound any user for this type of software.
mailto: anubhava.prodata@gmail.com
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Hi All,
Actually I want to Print Using Verdana Font with the size of 900.But it not showing Properly.
Please Suggest me how can it Possible.
Thanks
mailto: anubhava.prodata@gmail.com
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The size of the text that you're reading is probably 10 or 12. 900 would be really big 
Are we talking 900 pixels, em, cm, Inch?
I are troll 
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I am talking about em.Which is used in Notepad.
mailto: anubhava.prodata@gmail.com
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900 em would make a 12-point font about 10000 pixels. Can you try "0.9em"?
I are troll 
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Actually i don't know about em.I am Selecting font as
DIm A AS FONT = NEW FONT ( "verdana",900)
mailto: anubhava.prodata@gmail.com
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Can you try this one?
DIm A AS FONT = NEW FONT ("verdana", 16)
I are troll
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But It'S not working fine With the size 900.
mailto: anubhava.prodata@gmail.com
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That's probably because 900 is a too large a number. Have you tried a smaller size?
I are troll
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But i WANT Printout of text which font size is 500.
mailto: anubhava.prodata@gmail.com
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Then you will NEED big paper, or it won't fit 
I are troll
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Of COURCE I WILL NEED BIG PAPER.But how to print It.
Pls don't confuse me it won't Fit or fit.It's Printer problem not software.
mailto: anubhava.prodata@gmail.com
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It seems that there is a 127 maximum font size for (at least) label and textArea. If you set fontSize larger than that it will stay at 127. Very annoying. (Ugly) workaround: use scaleX and scaleY to make text bigger. I wanted a fontsize of 170, so I divided it by 2 and made my fontSize 85, then set the scaleX and scaleY to 2.
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eg_Anubhava wrote: Of COURCE I WILL NEED BIG PAPER
That, my dear friend, was not obvious to me. I don't know of any printer-drivers that have a canvas of that size. Perhaps it will fit on a single sheet from an A0 printer, but I'm afraid you might have to divide some characters over different pieces of paper.
I are troll
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Hello Dear,
My Need Is Printing Only One Character with size of 900. and I think It takes size of A4 Paper.
mailto: anubhava.prodata@gmail.com
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Just tried it with Microsoft Word - a single character with the size "900" does indeed fill an page.
I think that it's easier to "draw" the character to a bitmap, and then to stretch the bitmap to the appropriate size
I are troll
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i was tried. But Character has gone Out of area whether there is enough space from top of Paper.
mailto: anubhava.prodata@gmail.com
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Below is portion of my current code ... obviously I'm having a serious problem with this
Here is my question:
In the following line I need to replace one of these two entries with a "variable"
AddHandler Io_event.Input0, AddressOf F_DriveOK
Any ideas on how to do this ?
I need to add these handles dynamically - meaning the customer can change the mapping and therefore I need to update the handler to point to
A) a different Address or
B) change the input that point to a specific address
What I have now works but is already pages long as I already have +40 Inputs and +25 Mapto locations 
It's definitely time to fix this ....
Public Sub Add_InputHandle(ByVal VirtualNumber As Integer, ByVal MapTo As Integer)
Select Case VirtualNumber
Case 0
Select Case MapTo
Case 0
AddHandler Io_event.Input0, AddressOf F_DriveOK
Case 1
AddHandler Io_event.Input1, AddressOf F_DriveOK
Case 2
AddHandler Io_event.Input2, AddressOf F_DriveOK
.....
.....
.....
End Select
Case 1
Select Case MapTo
Case 0
AddHandler Io_event.Input0, AddressOf F_Estop
Case 1
AddHandler Io_event.Input1, AddressOf F_Estop
Case 2
AddHandler Io_event.Input2, AddressOf F_Estop
.....
.....
.....
End Select
End select
Thanks
Georg
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I would create two variables, then set their values in the case statements, and finally do the add handler using those variables.
You could also store lookup tables for those values, but this code will have to go somewhere.
Christian Graus
Driven to the arms of OSX by Vista.
"I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )
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That sounds good - but correct me if I'm wrong - I don't think you can use a variable in an Address of statement.
So somehow you would have to create another delegate for the adress of statement ???
I did try lot's of different ways a while back - non of them worked ...meaning I was somehow not on the right track 
Can you give me a short example of how your would do this?
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I dunno about addressof , but I'd just create two variables, whatever the types, at the top. Then in my switch statements, I would assign them. I'd do the delegate stuff at the bottom, using the variables.
Christian Graus
Driven to the arms of OSX by Vista.
"I am new to programming world. I have been learning c# for about past four weeks. I am quite acquainted with the fundamentals of c#. Now I have to work on a project which converts given flat files to XML using the XML serialization method" - SK64 ( but the forums have stuff like this posted every day )
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Does the sender object not pass through? It seems to me you should be able to ID the sender inside the delegate and work from that side of the problem. Use one delegate for all of the inputs, that delegate checks the sender ID and matches it to a function based on it's MapTo setting. I forget if you can create a collection of functions in VB.Net, but even without it, that should at least cut the list down to one look up for the MapTo and a 25 option select statement.
The true man wants two things: danger and play. For that reason he wants woman, as the most dangerous plaything.
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I am having some problems with the code I am writing.. here is the error message I'm getting:
error C2664: 'getFirst' : cannot convert parameter 1 from 'char (*)[100]' to 'char *'
And here is the code that is involved..
#include <iostream>
#include <cstdlib>
using namespace std;
bool getFirst(char *);
bool getLast(char *);
void main()
{
char firstName[100];
char lastName[100];
bool validFName;
bool validLName;
int first;
int last;
int length;
do
{
cout << "Enter your first name in lowercase letters: ";
validFName = getFirst(&firstName);
if (!validFName) cout << "Invalid entry. Try again...\n";
} while (!validFName);
cout << "\n";
do
{
cout << "Enter your last name in lowercase letters: ";
validLName = getLast(&lastName);
if (!validLName) cout << "Invalid entry. Try again...\n";
} while (!validLName);
cout << "\nYour full name is " << firstName << " " << lastName << "\n";
first = strlen(firstName);
last = strlen(lastName);
length = (first + last);
cout << "\nYour full name has " << length << " characters\n";
}
bool getFirst(char *first)
{
int iF,lenF;
char bufFirst[100];
bool validFirst = true;
cin.getline(bufFirst,100);
lenF = strlen(bufFirst);
iF = 0;
while (validFirst && iF < lenF)
{
if ((bufFirst[iF] < 'a') || (bufFirst[iF] > 'z'))
validFirst = false;
iF++;
}
return validFirst;
}
bool getLast(char *last)
{
int iL,lenL;
char bufLast[100];
bool validLast = true;
cin.getline(bufLast,100);
lenL = strlen(bufLast);
iL = 0;
while (validLast && iL < lenL)
{
if ((bufLast[iL] < 'a') || (bufLast[iL] > 'z'))
validLast = false;
iL++;
}
return validLast;
}
I cannot figure out how to get the correct output.. It displays crazy characters and says that my string length is 330 characters long..
Any help with this please??
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