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onmouseover="TICKER_PAUSED=true" onmouseout="TICKER_PAUSED=false"
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var marqueeWidth='950';
var marqueeHeight='18px';
var pauseMarquee=true;
var fontFamily = 'arial,sans-serif';
var marqueeSpeed=1;
var speedTwo=marqueeSpeed;
var textSpan, marquee;
var fontSize = parseInt(marqueeHeight) - 6;
function marquee(){
var content = document.getElementById('scroller').getAttribute('content');
if (document.getElementById){
var scrollit = '<div style="position:relative; margin:auto; width:'+marqueeWidth+'px;height:'+marqueeHeight+';overflow:hidden;color:#FFFFFF;"';
if (pauseMarquee) scrollit += ' onmouseover="speedTwo=0" onmouseout="speedTwo=marqueeSpeed"';
scrollit +='><div id="marquee" style="position:absolute;left:0px;top:0px;font-family:'+fontFamily+';font-size:'+fontSize+'px;white-space:nowrap;"><\/div><\/div>';
document.getElementById('scroller').innerHTML = scrollit;
marquee = document.getElementById("marquee");
marquee.style.left=(parseInt(marqueeWidth))+"px";
marquee.innerHTML='<span id="text">'+content+'<\/span>';
textSpan = document.getElementById("text").offsetWidth;
setInterval("scrollscroller()",17);
}
}
function scrollscroller(){
marquee.style.left = (parseInt(marquee.style.left)>(-10 - textSpan)) ?parseInt(marquee.style.left)-speedTwo+"px" : parseInt(marqueeWidth)+4+"px";
}
window.onload=marquee;
That js should get you started - you need to change it so that it goes up and down not left though.
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Hello,
I have a div, supposed the be at the bottom of the page, since its position is relative and there are another 2 divs placed before it. However it is diplayed at the top of the page. It is like that, in order to sva space I discarded the elements. The problem is, div footersub behaves like there are not leftsub or rightsub.
Please help.
Thanks alot.
<div id="centrallarge">
<h1 style="height:45px; width:900px;"><img src="images\digersayfa.jpg" alt="photo"/></h1>
<div id="central" style="Width:900px; margin-top:2px; height:700px;">
<div id="leftsub" style="Width:300px; height:650px; margin-top:50px;">
</div>
<div id="rightsub" style="Width:550px; height:700px; font-family:Tahoma; font-s
</div>
<div id="footersub">
</div>
</div>
</div>
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Use this CSS on the page:
html,
body {
margin:0;
padding:0;
height:100%;
}
#centrallarge {
min-height:100%;
position:relative;
}
#footersub {
position:absolute;
bottom:0;
width:100%;
height:60px;
}
This will work in most of the browser.
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I am writing a web-based system with java. There are some labels and reports printing. Each requires different printers which are connected to the same client computer.
How could I set so that, when I Print Doc A, document A would print to printer A, and when clicked Print for Doc B, document B would print to printer B.
The URL for both the documents are different. doc A is on http://www.xyz.com and doc b is on http://www.abc.com.
info: It is a web-based system used within a lan. So each user use the system with a fixed computer.
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If you are using standard html in browser there is no way to force print the document in a printer of your choice. You can give alert to choose the printer of your type before calling window.print, which will open the print dialog.
After that it is on user's choice to use proper printer or not.
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If you are sure that the web application will only run in lan, you can use PrintDocument classes to print the document from the server computer rather than invoking the browser print function.
This way you will eliminate the user's choice of printer selection. But mind that the printers should be connected to your server where the application is hosted. ![Rose | [Rose]](https://www.codeproject.com/script/Forums/Images/rose.gif)
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Hi Abhishek,
I am not sure how to use PrintDocument classes. Can you please guide me how to go about it.
Thanks.
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Create An object of PrintDocument, draw on the Document using Graphics object, print the document.
http://www.dreamincode.net/forums/showtopic71580.htm[^]
check this .. This might help. but it is written in VB.NET.
Another way is to generate Reports and print the resource.
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Hi Abhishek,
Thanks for your reply.
The object which is mentioned at http://www.dreamincode.net/forums/showtopic71580.htm, is for printing the pdfs.Our Reports are in pdfs, so I think we can print those using system default printer, I would like to change the printer for labels. I think that would be the easier approach.
Let me know your view.
Thanks.
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Hi Abhishek,
I was looking at the printing pdf link, I do not see anywhere where I can specify different printers.
Thanks.
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Heres a situation. I have a main SWF file that has variables. I load a SWF file inside the main SWF and I want to access variables from the main part. Is this possible? Or what is best way to share information between SWF file?
Thanks in advance.
GreenKhan
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use local connection:
<a href="http://www.trap17.com/index.php/Pass-Variables-2-Swf_t61897.html">http://www.trap17.com/index.php/Pass-Variables-2-Swf_t61897.html</a>[<a href="http://www.trap17.com/index.php/Pass-Variables-2-Swf_t61897.html" target="_blank" title="New Window">^</a>]
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I tried using Flash Object, which is like Flash cookies, but not successful yet 
GreenKhan
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if it is two swf on the same page then use local connection.
if it is two swf on different pages then use environment variables (eg. post to php, store in database and retrieve using php page)
if it is one swf inside another you should be able to give the inner swf an instance name a get the variables that way or possibly use local connection.
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Hello !
i'm new to web design and i have this problem :
i'm creating a web site in dreamweaver cs3 (simple html).one of my pages have some article titles
Title 1
Tilte 2
........
i want to do this : When a user click on the title , to open a popup window without title bar that cointains one image , a description and a close button.But the image and the text should be variables to be used for all articles.
Can someone give me a script in javascript for this situation ?
Thank you in advance !
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Just without doing window.open for which you cant hide title bar, use a floating div to create the popup.
var x = document.createElement('div');
x.style.position = 'absolute';
x.style.top='100px';
x.style.left = '300px';
document.appendChild(x);
Set appropriate content and also review the position according to your requirement. 
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thank you but i want 2 object inside popup to be variables 1 image and 1 text description , so when i click the first article the popup should show the first image and the first description , when i click the second article the popup should show the second image and description .... .
is possible to do that ?
thank you.
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Create an img element and appendChild to the Div. Or just assign the innerHTML to the div you have created inside the popup.
You can change innerHTML also when required. 
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hi,
I am using .net 1.1 version.
The problem is i have used one datagrid which contains some data columns and one checkbox column.
Datagrid contains nearly 50 records and 50 checkboxes.(i.e) each record contains checkbox.
below the datagrid an image button is placed.if i didn't select any checkboxes and click on the image button it should tell please select any two checkboxes for compare.
but i am using .net 1.1 so please any one help me....
i need the javascript code for how to check whether the checkbox is checked or not...
Regards,
Prakash
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Hi Prakash,
Just try this code. This would help you....
function CheckAllCheckBox(grid)
{
var oItem = grid.children;
var theBox=oItem.item(0)
var chk;
chk=true;
elm=theBox.form.elements;
for(i=0;i<elm.length;i++)
if(elm[i].type=="checkbox" && elm[i].id!=theBox.id )
{
if(elm[i].checked!=true)
chk=false;
}
if (chk==false)
{
alert("Please Select atleast One CheckBox")
return false;
}
}
I had used this code long time back.
Be an Eagle, Sky is Yours.
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Hi all,
I have a web application developed using .net 2005.I have used Ajax control toolkit 1.0 along with this.It was working perfectly.When i tried to run the project somedays after ,Ajax control tool kit is not working .What will be the reason.?
These are the errors im getting
1.Could not load file or assembly 'AjaxControlToolkit' or one of its dependencies. The system cannot find the file specified.
2.Unknown server tag 'ajaxToolkit:ToolkitScriptManager'.
Help me to solve this problem..
Thanks in advance for any help.
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how to use _doPostBack in javascript to refresh a parent page.
i am writing window.opener.__doPostBack('pagename',''); it does not work
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