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I have two websites.
1. I used a template.
2. I designed by my own without using template.
after the completion of both websites how do i differ between them that the first one is a template and the second one is no template even that i know it becuase i have worked on them but if someone else worked on that then how do i know and recognize that.
Thanks
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Label one "template"? or include credit to the person who made it in the footer. ask the person who made it what they want you to do.
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dear all
please tell me how tyo insert and retrive images from mysql database
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Hello All,
I am Senthil.S working as DOT Net developer.
I need little help or advice me to migrate Visual Studio 2005 to higher.
I and my team currently working on visual studio 2005 and MS SQL Server 2005.
We all need to migrate to higher version of VS and MS SQL Server. ie. Server is centralized and the project will available on the server. All from my team need to work on the project from their machines (as client) as team work.
Can you help or guide me what version or what type of VS and MS SQL server i need to use.
Can you explain me...
Senthil.S
A Software Engineer
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If you need the Higher version of VS and MSSQL, use VS 2008 ans MSSQL 2008
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Thanks for response Karthik.
Okay I will upgrade to VS 2008.
What about team work and distribute project management.
What version of Visual studio shell i can use.
Senthil.S
A Software Engineer
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I have an assignment to write an online test application, which people can take and get their result immediately. How can i do this using php and javascript. pls this is urgent.
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Most people do their own assignments rather than asking others to do it for them.
Go on, do it yourself, you'll get a nice warm feeling inside.
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hi doctor mick, i already started the application using a php IDE (INTerakt product,Ms collection). All i need is how to store every answer each applicant chooses and check it against the correct answer to determine if the answer is right or wrong. I used radio buttons for the options. I need to know how to Score each applicant. I think I should include this, my application interfaces with a database. Thanks
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What doctormick is Saying is that here we don't do Homework for people, You have to Start something and when you get stucked , consult Google and if you don't find answers there , then you can post and point exactly where your have challenges and we will help you. Please try again to explain your problem because its not clear
Thanks
Vuyiswa Maseko,
Few companies that installed computers to reduce the employment of clerks have realized their expectations.... They now need more and more expensive clerks even though they call them "Developers" or "Programmers."
C#/VB.NET/ASP.NET/SQL7/2000/2005/2008
http://www.vuyiswamaseko.somee.com
http://www.vuyiswamaseko.tiyaneProperties.co.za
vuyiswa@its.co.za
http://www.itsabacus.co.za/itsabacus/
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Hi,
I am trying to disable some items in listbox through javascipt in ASP.net
These items are disabling in IE8 but not disabling in IE6. How can I do it?
var lstRight = document.getElementById("lstSelection");
var fixedFieldIds = document.getElementById("hdnFixedFieldId");
var fieldIdArray = fixedFieldIds.value.split('^');
if(fieldIdArray)
{
for(var i =0;i<fieldIdArray.length;i++)
{
for(var j=0; j<lstRight.options.length; j++)
{
if(lstRight.options[j].value == fieldIdArray[i])
{
lstRight.options[j].disabled = true;
break;
}
}
}
}
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<script type="text/javascript">
disableIt(){
document.getElementById('selectbox').style.display = "none";
document.getElementById('selectbox').style.visibility = "Hidden";
document.getElementById('mytext').style.display = "inline-block";
document.getElementById('mytext').style.visibility = "visibile";
}
</script>
<select id="selectbox" onchange="disableIt();">
<option value="1">1</option>
<option value="2">2</option>
</select>
<div id="mytext">
2
</div>
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no advertisements plzzzzzzzz.......
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If you are feeling thirtst there are 6,268,151 members here who can PISS ON YOU!
Panic, Chaos, Destruction.
My work here is done.
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I am using Visual Studio 2008, c#.
Trying to create a web page to display a multiple column list with no database as a source (update from the code itself).
I see no DataGrid option with ASP.NET.
I am using user control in a web page.
For example, this is how it should look:
IP Protocol Command Data
XXXXXXX TCP XXXXXX XXXXXX
Same ...
This is a list of clients currently connected.
Desparate, tried almost everything.
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I tried this before, seems like all went fine except the page is shown empty.
As I explained before, not sure if it makes any difference, I am using a user control (ascx) in a web page (aspx).
Following is the code I used:
<br />
protected void Page_Load(object sender, EventArgs e)<br />
{<br />
if (!Page.IsPostBack)<br />
{<br />
DataTable myDt = CreateDataTable();<br />
Session["myDatatable"] = myDt;<br />
<br />
this.GridView1.DataSource = ((DataTable)Session["myDatatable"]).DefaultView;<br />
this.GridView1.DataBind();<br />
}<br />
}<br />
<br />
private DataTable CreateDataTable()<br />
{<br />
DataTable myDataTable = new DataTable();<br />
<br />
DataColumn myDataColumn;<br />
<br />
myDataColumn = new DataColumn();<br />
myDataColumn.DataType = Type.GetType("System.String");<br />
myDataColumn.ColumnName = "id";<br />
myDataTable.Columns.Add(myDataColumn);<br />
<br />
myDataColumn = new DataColumn();<br />
myDataColumn.DataType = Type.GetType("System.String");<br />
myDataColumn.ColumnName = "username";<br />
myDataTable.Columns.Add(myDataColumn);<br />
<br />
myDataColumn = new DataColumn();<br />
myDataColumn.DataType = Type.GetType("System.String");<br />
myDataColumn.ColumnName = "firstname";<br />
myDataTable.Columns.Add(myDataColumn);<br />
<br />
myDataColumn = new DataColumn();<br />
myDataColumn.DataType = Type.GetType("System.String");<br />
myDataColumn.ColumnName = "lastname";<br />
myDataTable.Columns.Add(myDataColumn);<br />
<br />
return myDataTable;<br />
}
And thanks again.
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All you did there was add columns to the datatable, now try adding rows to it:
myDataTable.Rows.Add("XXXXX", "TCP", "XXXXX", "XXXXXX")
That should get you started. 
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Thanks Matthhews!
It did work, but I thought columns are created even when no data is inserted.
Is there a way to force that happen?
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When you create a column, all your doing is making a place to "store" that data in the datatable. You'll still need to create the data to populate it with.
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Still not able to do one thing:
I am creating the GridView, taking the data from a datatable and it is showing just fine.
When I am trying to add few more rows later (depending when I got a trigger from a client), it is not showing up.
Following is my code:
UC1.ascx
<br />
protected void Page_Load(object sender, EventArgs e)<br />
{<br />
if (!Page.IsPostBack)<br />
{<br />
myDataTable = new DataTable();<br />
CreateDataTable();<br />
Session["myDatatable"] = myDataTable;<br />
<br />
this.GridView1.DataSource = ((DataTable)Session["myDatatable"]).DefaultView;<br />
this.GridView1.DataBind();<br />
}<br />
}<br />
<br />
public void CreateDataTable()<br />
{<br />
DataColumn myDataColumn;<br />
<br />
myDataColumn = new DataColumn();<br />
myDataColumn.DataType = Type.GetType("System.String");<br />
myDataColumn.ColumnName = "IP";<br />
myDataTable.Columns.Add(myDataColumn);<br />
<br />
myDataColumn = new DataColumn();<br />
myDataColumn.DataType = Type.GetType("System.String");<br />
myDataColumn.ColumnName = "Port";<br />
myDataTable.Columns.Add(myDataColumn);<br />
<br />
myDataColumn = new DataColumn();<br />
myDataColumn.DataType = Type.GetType("System.String");<br />
myDataColumn.ColumnName = "Command";<br />
myDataTable.Columns.Add(myDataColumn);<br />
<br />
myDataColumn = new DataColumn();<br />
myDataColumn.DataType = Type.GetType("System.String");<br />
myDataColumn.ColumnName = "Data";<br />
myDataTable.Columns.Add(myDataColumn);<br />
<big> !!!!!! This one works fine and shows up correctly !!!!!!!!</big><br />
myDataTable.Rows.Add("IP", "Port", "Command", "Data");<br />
}<br />
<br />
<big>Calling this will have no effect, why???</big><br />
private void AddDataToTable(string Ip, string Port, string Command, string Data)<br />
{<br />
DataRow row;<br />
row = myDataTable.NewRow();<br />
<br />
row["IP"] = Ip;<br />
row["Port"] = Port;<br />
row["Command"] = Command;<br />
row["Data"] = Data;<br />
<br />
myDataTable.Rows.Add(row);<br />
this.GridView1.DataBind();<br />
}<br />
Do not understand why calling AddDataToTable makes nothing.
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Is there a way to open a folder in windows explorer with a Vista Gadget?
I succesfully created the gadget (which lists my current projects and has a hyperlink to the folder containting the relevant documents), but the sidebar blocks popups. I even tried to launch the explorer via the exe, but that's blocked as well.
I found something with VBScript for an alert box, but I couldn't find an example for a popup (hyperlink).
Thanks for any assistance. 
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I have a drop down selection box with items in it. I need to be able to pass the selected item through using an onclick event for the "Submit" button. Is this possible?
I have a JavaScript that is calling a div to popup. This div is the drop down selector. I want the user to click a button to make the drop down appear, then they must select an item in the list and then hit submit. The submit button being clicked I need to bring in the selected value from the drop down and use it in the script that originally told the div to pop up (this is the first button that the user clicks, it actually runs the script which passes 2 variables, and is basically waiting on the drop down selection to save into a 3rd variable, which will then call a PageMethod).
I have
function AddTemplateToUUT(uutnumber,testerid){
var templatename=SelectTemplateToAssign();
PageMethods.AddTemplateToUUT(testerid,uutnumber,templatename,CallbackDiv,CallbackErrorAlert,'divchecklistarea');
}
function SelectTemplateToAssign(){
ShowSelection('divtemplateblock','show');
var tname=document.getElementById('drptemplateselect').value;
alert(tname);
ShowSelection('divtemplateblock','hide');
return (tname);
}
Anyone please help?
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