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Changing that setting solved it. Thanks.
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"Show me a community that obeys the Ten Commandments and I'll show you a less crowded prison system." - Anonymous
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Dear all,
I'm new comer in development web with jquery. I've problem when I developed my web using jquery. My case is I use two ajax in one jquery that defined in file A. In file A there are dropdown menu and button. the first ajax is triggered when dropdown menu is changed. And then ajax call html from file B. so html in file A replaced by html from file, and now the button coming from html in file B. Dropdown menu html isn't replaced by html from file B, after that I clicked that button, but ajax not triggered. Does anyone have problem with me? Please help me for this matter...
Thank you very much,
Regards
Reinhart
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chandra reinhart wrote: Does anyone have problem with me?
Do you want problem? then open your error console. In firefox use ctrl+Shift+j, in chrome use the same. then see what error it is showing and let us know.
This Signature Panel is available for advertisement.
How to contact: go outside and yell my name.
p.s. If I don't reply, then your offer is not tempting
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Hi rashid..
Thank for your response.. Last night I tried to solve my problem, it happened because I use button from another file so indirectly I have removed the ajax function for that button..
Regards,
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I want to publish my web on my pc with IIS7 but I am getting error message after publish for "access denied to folder"
how can I debug this problem?
Please suggest me.
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we have started a very new company.
and got some customer as well for website development.
Now I am confused, from where to buy hosting space.
my requirements are [PHP , MySql, Html, Javascript, CSS]
Local hosting will be good or internet websites.
Where I will not face any user complain.
and how much it will cast in average?
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Start here[^].
"If you think it's expensive to hire a professional to do the job, wait until you hire an amateur." Red Adair.
nils illegitimus carborundum
me, me, me
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I'm asking about hosting server not professionals
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Sourav Sarkar-SS wrote:
I'm asking about hosting server not
professionals
You're going to have to explain that: makes no sense.
"If you think it's expensive to hire a professional to do the job, wait until you hire an amateur." Red Adair.
nils illegitimus carborundum
me, me, me
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Hi,
I have a button on a HTML page.
If i click that button I have to invoke "OpenFile" dialog.
Could any one assist please.
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Use:
<input type="file" id="fileDialog" />
This would give you browse button on click of which Open File dialog would appear.
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GOOGLE is your friend, GOOGLE dont hurt you!
if you GOOGLE IT you get the answer in a few seconds!
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yea got it man .. I don't have access to google but codeproject in my office .. thanks any how..
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You dont have access to google???
How???
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Hi Sandeep,
Is it posibile to add filters to the openfile dialog box?
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Adding accept attribute could work but as W3 says[^], it's not properly handled by recent browsers.
Your best bet would be to handle it based on the file extension by yourself at the time of page submit or code behind.
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ok thank u.. I will try it out.. once again thank u so much ..
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Hi,
My Web site has some text fields, text area. I want the user to use an option of browsing the files and once he browses the files the contents of the file should be displayed in the textarea. Once the textarea is filled with the contents of the chosen file then I want to submit the form.
Language: JSP only but you can use any scripting language.
No pHp please.
Regards,
Ethan
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here asp, jsp or php none of them has to do anything.
You want to open and see your file in your browser. But browser don't allow accessing local file in the browser. what you can do?
you can write a simple code to post data to server and display it in your textarea:
<script>
function Upload()
{
$("#fileuploader").submit();
}
</script>
<form name=fileuploader id=fileuploader method=post action='webapp/lib/uploads/uploadelaox.php' enctype="multipart/form-data" target='UploadedFrame'>
<input type='file' name='csv' id='csv' onchange='Upload();' Title='Select File Name'>
</form>
<iframe id='UploadedFrame' style='display:none' onload='write_a_function_to_move_all_loaded_text_to_your_text_area()' name='UploadedFrame' ></iframe>
now in your server side verify and do the process to transfer data.
This Signature Panel is available for advertisement.
How to contact: go outside and yell my name.
p.s. If I don't reply, then your offer is not tempting
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Hi All,
I have one have one problem please help me out in this.
I want to display pop in php. Like whenever user fills the form and submit it then after Successful submission of form if the data is inserted in database the it should pop up like Thanks for contacting this is ur enquiry number....blah blah..
Can anyone please help me with this that how can i show this pop or only div after successful insertion of data from php.
Awaiting for reply
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You can't create a pop up with PHP, you would need javascript to do that...
See this sample:
<form name='YourForm' action='check_and_pop.php' method='POST' enctype='application/x-www-form-urlencoded' onsubmit='return JS_verify();'>
In that form header in PHP you can see:
When you will send the form you will go to "check_and_pop.php" only if in the OnSubmit event the JS_verify() javascript function returns TRUE (I'm using a javascript function to verify the filds in the form).
In the check_and_pop.php file you can re-check the contents of the POST using PHP, this is a good option to ensure that you've checked everything even if javascript is disabled in the client side.
Once in the check_and_pop.php file you can show the message you want.
Good luck!
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after you check that the post was made then exit php and run the js code for the alert box and echo in any dynamic content. then open php back up and continue with the rest of your query.. this error always occurred in php development so just try this one.
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