Is there a way to get the extension of an image if you know it's link? At first I thought of splitting the string with . and get the last part, but the problem with this is that there are some links that don't include the extension at the end so this is not an universal solution.
Because I know the link each time, is there something I can do with an image object (new Image), or how else can I get the extension? All the results I got were to check if it is an image but not it's extension, or the one I explained above, but that won't work in every scenarios.
Richard Deeming wrote:
Because this will not work in Javascrip with all websites which we actually need, in what other language can it be done?
I do apologies, web applications is not what I normally do, but this time I have to do it and learn for the future, maybe I'll run into something similar.
We don't have any control over the server, this is goin to be done in a extension for Firefox. We added a new contextMenu for images only, and from that we can get the Url, but as I said in the first thread there are some websites that don't add the name and the extension directly into the link (example.com/image.jpg / example.com/someImage), so we need to find another way to get them when the user right click's on it.
With current message, most will not be able find what you want to share and will be lost. Thanks!
This alghoritm i want to use to create shape for cnc foam cutter ... so a one line need to pass all countour paths
i have 4 path with x,y points coordonates
Alghoritm need to find in primis a most low value apropriate to 0 in this case [1,2] that is in path3 point 3
After find this point...compare all points of path3 with points of all paths and find most appropiate value ... in this case [8,4] from path2 that is closest to [8,2] from path3
after find most apropiate value ...join the path3 with path 2 in pointers find
And after join path2 with path3 in this mode ... compare all points of result_path with points of remainder paths (path1,path4) ... and insert path find in result_path in same mode
I dont know how explain better!
I am trying to make an add-on for Mozilla Firefox that will convert an image (from a given direct link) to another format and then give the user the save file pop-up.
I'm doing the testing in straight HTML, because it is easier to do it this way, then keep refreshing the add-on in browser.
Thank you for taking the time to review my question.
I am using Google Maps API and custom JScript to be able to calculate snow loads in Tahoe Basin.
This all works as expected except for one county...El Dorado, which does not work and I have not been able to isolate the issue.
Working Page Here: http://zacharyengineering.com/snowload_calculator
***NOTE: works perfectly except for Eldorado County (South Shore Lake Tahoe) Click and you will see this error:
ERROR: The address provided appears to be in El_Dorado County county (only Placer, Washoe, Nevada, El Dorado, and Douglas counties are supported)
This is the catch-all error for when someone clicks outside of the supported area.
I can upload the JScript file if helpful...
Thanks Again, I am stumped as to how to address this error. matt