Navigation Menu with XML Datasource (ASP.NET Server Control)
Aug 9, 2008
11 min read
C#3.0
.NET3.5
VS2008
C#
ASP.NET
XML
.NET
Dev
Intermediate
Advanced
C#
.NET
Visual-Studio

by Enes Gundogmus
Contributor
Introduction
Throughout my Web designing days, I always needed navigation menus with dynamic content which are also easily editable and customizable. Last month, I decided to write a simple menu control which uses CSS to style and uses XML as source for menu items.
Navigation Menu Server Control
<?xml version="1.0" encoding="utf-8" ?> <menuitems> <item id="1" url="Default.aspx" linkname="Main Page" description="Main Page of web siter"/> <item id="2" url="Default2.aspx" linkname="Company" description="Company Details"/> <item id="3" url="Default3.aspx" linkname="Photos" description="Photo Gallery"/> <item id="4" url="Default4.aspx" linkname="Contact" description="Contact Form"/> </menuitems>
This is the XML template for menu items and links.
From the Visual Studio menu, follow the tree: File - New - Project - Web - ASP.NET Server Control, and create a new server control project. By default, ServerControl1.cs is installed. Right click the project and add a new Class called xmlreader.cs In this class, first of all, we define an object that represents menu item. Let's call it menuitem
for simplicity's sake.
using System.Linq; using System.Xml; using System.Xml.Linq; using System.Text; using System.Collections; public class menuitem { public menuitem() { } private string id; //id of item private string url; // url for menu link private string linkname; //name of the link that will be displayed private string description; // description displayed when mouse hover public string Id { get { return id; } set { id = value; } } public string Url { get { return url; } set { url = value; } } public string Linkname { get { return linkname; } set { linkname = value; } } public string Description { get { return description; } set { description = value; } } }
After defining menuitem
, we will create an instance of an arraylist
class called getMenu
into the xmlreader
class. In the getMenu
method, we read XML with XLINQ. This method takes two parameters:
path
xmlFilename
public ArrayList getMenu(string xmlPath, string xmlFileName) { //array List to get menu items from xml ArrayList menuitems = new ArrayList(); try { XElement xmenu = XElement.Load(xmlPath + xmlFileName); if (xmenu != null) { //get data from xml for menu items using XLINQ var xc = from c in xmenu.Elements("item") orderby c.Attribute("id").Value select new { ID = c.Attribute("id"), URL = c.Attribute("url"), LINKNAME = c.Attribute("linkname"), DESCRIPTION = c.Attribute("description") }; foreach (var l in xc) { menuitem itm = new menuitem(); //item id itm.Id = l.ID.Value; //menu item url itm.Url = l.URL.Value; //menu item name itm.Linkname = l.LINKNAME.Value; //menu description itm.Description = l.DESCRIPTION.Value; menuitems.Add(itm); } } } catch (Exception ex) { throw ex; } //return menu items return menuitems; }
In the above methods, we created an arraylist
. Now we have to create our HTML code. To do this, we go to the ServerControl1.cs class.
The menuHtmlGenerator
method is the one that takes items in the arraylist
, we build with getMenu
in xmlreader
and creates the markup code for HTML page.
protected string menuHtmlGenerator(ArrayList aList) { StringBuilder s = new StringBuilder(); //looping through Arraylist collection of Links. for (int i = 0; i < aList.Count; i++) { s.Append(System.Environment.NewLine); s.Append("<li >"); s.Append("<a href ='" + ((menuitem)aList[i]).Url + "' "); s.Append("title='" + ((menuitem)aList[i]).Description + "' "); //if menu will show different class for currently selected item if (useDiffCssForCrrntItem) { if (((menuitem)aList[i]).Id == currentItemId) s.Append("class='" + currentItemClass + "' "); } s.Append(">"); s.Append("<span>" + ((menuitem)aList[i]).Linkname + "</span> "); s.Append("</a>"); s.Append("</li>"); s.Append(System.Environment.NewLine); } //Return Full HTML Code As String return s.ToString(); } }
After generating HTML code, we use a method derived from WebControl
. In the method, the first thing we do is declare properties of the menu. They will be used as design-time attributes to customize the control.
public class ServerControl1 : WebControl { #region 7 properties for design-time attritubes private string xmlPath; // xml file path private string xmlFileName; // xmlfile name private string menuClass; // CSS class to ship the menu private string menuId; // main div id that will surround menu // will menu show selected link differently? private bool useDiffCssForCrrntItem = false; private string currentItemClass; //currently selected item's class private string currentItemId; //id that will determine which item is selected #endregion [Bindable(true)] [Category("Appearance")] [DefaultValue("")] [Localizable(true)] #region 4 Member properties Used as Design-Time Attributes for Our Server Control public string XmlPath { get { return xmlPath; } set { xmlPath = value; } } public string XmlFileName { get { return xmlFileName; } set { xmlFileName = value; } } public string MenuClass { get { return menuClass; } set { menuClass = value; } } public string MenuId { get { return menuId; } set { menuId = value; } } public bool UseDiffCssForCrrntItem { get { return useDiffCssForCrrntItem; } set { useDiffCssForCrrntItem = value; } } public string CurrentItemClass { get { return currentItemClass; } set { currentItemClass = value; } } public string CurrentItemId { get { return currentItemId; } set { currentItemId = value; } } #endregion //render method. THIS IS MAIN METHOD WHERE ALL THE HTML CODE IS GENERATED AND //PASSED TO HTML PAGE protected override void RenderContents(HtmlTextWriter output) { try { // make instance from Data Class xmlreader myData = new xmlreader(); //Write menu div output.Write("<div class='" + menuClass + "' id='" + menuId + "'>"); //Open Ul Tag output.Write("<ul>"); //write the Links Tag which is returned by GetNew(connectionStr) Method //menuHtmlGenerator method is explained below output.Write(menuHtmlGenerator(myData.getMenu(xmlPath, xmlFileName))); //ul Close Tag output.Write("</ul>"); //div Close Tags output.Write("</d i v></div>"); } catch (Exception ex) { output.Write(ex); } }
After we build our project in Visual Studio, right click the head of the toolbox and click Choose Items and select DLL file from the bin folder.
After that, drag and drop the new item to the page. Set the properties. Prepare the XML file which is in the sample project.
Points of Interest
This menu control is a sample of what you can do with server controls. They are powerful and fast.
History
- 8th August, 2008: Initial version
License
This article, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)