how to solve Exception thrown from XML file

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I am very new to spring . I am trying basic example . I got the following error

Exception in thread "main" org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from file [C:\Users\Raghavendra\workspace\SpringDraw\spring.xml]; nested exception is java.io.FileNotFoundException: spring.xml (The system cannot find the file specified)

I think this error from XML file ,
I think i made a mistake in DOCTYPE definition can you please help me in this . and jars I used here are

org.springframework.core-3.0.1.RELEASE-A
com.springsource.org.apache.commons.logging-1.1.1
org.springframework.beans-3.0.1.RELEASE-A

Posted 21-Feb-14 1:08am

Raghavendra M

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Maarten Kools 21-Feb-14 7:41am

Well, as the exception is a FileNotFoundException, I'd say the file doesn't exist at the specified path.

Raghavendra M 21-Feb-14 7:43am

No . , file is there . . but i didnt specify path any where . . If that is so where should i specify file path

Maarten Kools 21-Feb-14 7:45am

If the file is there, then perhaps it's a permission issue. You might not have permission to read the file at that location when running your program?

Raghavendra M 21-Feb-14 7:48am

Hey I have solved this .., see at first used
BeanFactory factory=new XmlBeanFactory(new FileSystemResource("spring.xml"));

it gives error but now I used
Resource resource=new ClassPathResource("spring.xml");
BeanFactory factory=new XmlBeanFactory(resource);

its solve now . . , what is the difference in that.

Maarten Kools 21-Feb-14 7:51am

Well, I'm not too familiar with Spring/Java, but I can take a guess. A FileSystemResource would be a file on disk, in the working folder of the application. A ClassPathResource would be a file that is located in a folder that is declared in the class path.

Raghavendra M 21-Feb-14 7:52am

K thank u . .

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Maarten Kools · Accepted Answer · 2014-02-21T01:57:00

Answered to remove it from the unanswered questions queue.

As found by Raghavendra M:
Hey I have solved this .., see at first used

Java

BeanFactory factory=new XmlBeanFactory(new FileSystemResource("spring.xml"));

it gives error but now I used