Spiral matrix off by 1 index?

[1,2,3,6,9,8,7,1,5]

[1,2,3,6,9,8,7,4,5]

function spiralOrder(matrix) {
  // your code here...
  let top = 0;
  let left = 0;
  let bot = matrix.length - 1;
  let right = matrix[0].length-1;
  const results = [];
  const size = matrix.length * matrix[0].length;
  
  while (results.length < size) {
      
    for (let i = left; i <= right && results.length < size; i++) {
        results.push(matrix[top][i]);
    } 
    top++;
    
    for (let i = top; i <= bot && results.length < size; i++) {
        results.push(matrix[i][right]);
    } 
    right--;
    
    for (let i = right; i >= left && results.length < size; i--) {
        results.push(matrix[bot][i]);
    }
    bot--;

    for (let i = bot; i >= top && results.length < size; i--) {
        results.push([i][left]);
    }
    left++;

  }
    return results;
};


matrix = [[ 1, 2, 3],
          [ 4, 5, 6],
          [ 7, 8, 9]]

console.log(spiralOrder(matrix)); // [1,2,3,6,9,8,7,4,5]

matrix = [[1, 2, 3, 4],
          [5, 6, 7, 8],
          [9,10,11,12]]


console.log(spiralOrder(matrix)); // [1,2,3,4,8,12,11,10,9,5,6,7]