This is a simple java problem but I am new to this so please check why I am having problem

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when I am inserting a array of char type. I have set rray, but when I run the program it takes less values and print them instead of taking the no. of values which I have initialized.
please check this

Java

import java.io.*;
class charr
{
    public static void main (String args[]) throws IOException
    {
     BufferedReader br= new BufferedReader (new InputStreamReader(System.in));   
     
     char a [] = new char [5];
     for ( int i=0; i<5; i++)
     {
      char n = (char)br.read();
      a[i] = n;
      
        }
    for ( int i=0; i<5; i++)
     {
      System.out.println ( a[i]);
      
        }
        }
}

What I have tried:

I am new to this so i have tried nothing

Posted 18-Jan-21 4:45am

Bhasker Babu

Updated 18-Jan-21 5:11am

Richard Deeming

v2

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Richard MacCutchan · Answer 1 · 2021-01-18T05:11:00

I just tried your code and it works fine*. Please provide more details as to exactly what you are seeing.

*although it does need to be surrounded by a try/catch sequence to check for IOException.

[edit]
I am still not exactly sure what your problem is, but the following code will allow up to 20 characters to be processed. It will terminate on the end of line.

Java

BufferedReader br= new BufferedReader (new InputStreamReader(System.in));   

char a [] = new char [20];
int count;
try {
    for (count = 0; count < 20; count++) {
        char n = (char)br.read();
        if (n == '\n')  // break if end of line
            break;
        a[count] = n;
    }
    for (int i = 0; i < count; i++) {
        System.out.println ( a[i]);        
    }
}
catch (IOException ee) {
    System.out.println (ee);        
}

[/edit]