dynamic string array in vb.net

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Hello !
I wanna declare a string array without specifying the size of string array in vb.net. That is, as new element comes, the array should grow at run time.
How can i do that?
Thanx in advance

Posted 22-May-12 22:40pm

Naveen_143

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4 solutions

Solution 5

VB

Dim stringArray As String()

' define three strings
Dim value1 As String = "lions"
Dim value2 As String = "tigers"
Dim value3 As String = "bears"

' using the Split() command, dynamically create them as a three element array
stringArray = Split(value1 + "," + value2 + "," + value3)

' define a fourth string
Dim value4 As String = "Oh my!"

' dynamically add to the array
stringArray = Split(Join(stringArray, ",") + ","+ value4, ",";)

' or, you could ...

stringArray = Split("lions" + "," + "tigers" + "," + "bears", ",")
stringArray = Split(Join(stringArray, ",") + "," + "Oh my!", ",")

Posted 17-Jun-13 9:46am

William Martin

Comments

CHill60 17-Jun-13 17:18pm

It's great that you want to help but this question is a year old and already resolved

Naveen_143 5-Jul-13 4:49am

thanks for your reply.

Solution 3

VB

Dim webQuery As QueryWebService.Service = New QueryWebService.Service


    Dim queryDetails As String()
    Dim i As Integer = 0

    queryDetails = webQuery.getStudentQuery()

    While i < queryDetails.Length
        txtQuery.Text = txtQuery.Text + " " + queryDetails.GetValue(i)
        i = i + 1
    End While

Posted 22-May-12 23:29pm

sunandandutt

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OriginalGriff · Accepted Answer · 2012-05-22T22:45:00

Solution 2

Use a List instead:

VB

Dim myList As New List(Of String)()
myList.Add("Hello")
myList.Add("Goodbye")
Console.WriteLine(myList(1))

If you need it as an array at any time (to pass it to a method for example):

VB

Dim myArray As String() = myList.ToArray()

Posted 22-May-12 22:45pm

OriginalGriff

Comments

VJ Reddy 23-May-12 5:13am

Nice answer. 5!

Naveen_143 23-May-12 5:24am

Hi,
Dim myList As New List(Of String)() is showing an error...Comma,')' , or a valid continuation expected...

OriginalGriff 23-May-12 5:31am

I just pasted the code in my answer into a VB page and it compiles cleanly - check your code and make sure it is identical. If you can't see a problem, then copy and paste the relevant section of your code with the error message here.

Maciej Los 23-May-12 11:16am

Good answer, my 5!

005bharat 31-May-13 4:53am

Great work!

Med_Dev 14-Jun-17 0:18am

Great, I think thta it's the best solution

Chabi Blazquez · Accepted Answer · 2012-05-24T03:25:00

Solution 4

If you wont use Generics, you can do it directly:

VB

Dim s() As String
ReDim Preserve s(UBound(s) + 1)
s(UBound(s)) = "new valor"

Posted 24-May-12 3:25am

Chabi Blazquez

Comments

Naveen_143 12-Jun-12 5:55am

thanks...