MFC SDI File Open Dialog

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Hi,

I have created an MFC SDI project based on the explorer style (it has a left-hand pane containing a tree-view, and a right-hand pane into which I wish to open files).

There is already a file-open menu item which opens a file dialog. When the user selects a file from within the file-open dialog, how do I know that a file has been selected and what its name and directory location is? How do I capture this in my code?

Many thanks.

Posted 24-Mar-11 7:02am

Jackie Lloyd

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4 solutions

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#realJSOP · Answer 1 · 2011-03-24T07:19:00

Solution 1

It's been more than four years since I wrote any MFC stuff, but it goes something like this:

C++

CString path;
if (dlg.DoModal() == IDOK)
{
    path = dlg.GetPathName();
}

Posted 24-Mar-11 7:19am

#realJSOP

Comments

Albert Holguin 24-Mar-11 14:54pm

that's pretty good memory...lol

Jackie Lloyd 25-Mar-11 4:34am

Hi, thankyou very much for your reply - it is very much appreciated.

The main problem I have is that I don't know what the instance of CFileDialog is called. I cannot find any refernce to CFileDialog in the project code, and there is no CFileDialog in the resource view (although there is clearly the dialog for the 'About' dialog). However, when I run the app, the file->open option on the menu-bar clearly opens the file dialog and allows me to select a file (altho nothing happens when I click OK). I do not know how to 'get hold' of the CFileDialog object. Sorry if i did not make that clear initially.

వేంకటనారాయణ(venkatmakam) · Answer 2 · 2011-03-24T07:54:00

Hi You can use the Return value of CFileDialog::DoModa(), Function. If it is IDOK the user selected a file and closed the dialog by clicking on open button and if it is IDCANCEL the dialog was closed using cancel button or X button.
Example:

CFileDialog FileDilog;
if(FileDialog.DoModal() == IDOK)
{
      //Full path of selected file.
      CString strFilePath = FileDialog.GetPathName();
}

In case if you want to know allow multiple file selection Use The code,

if (FileDialog.DoModal() == IDOK)
{
  POSITION pos = FileDialog.GetStartPosition();
  while (pos != NULL)
  {
    CString strFilePath = FileDialog.GetNextPathName(pos);
    // Process the file
  }
}

Check MSDN for More info.
http://msdn.microsoft.com/en-us/library/8dwz4azc%28v=vs.80%29.aspx[^]

bolivar123 · Answer 3 · 2011-03-24T08:48:00

Solution 3

Just override the virtual OnFileOpen function in your application's CDocument based class.

C#

virtual BOOL OnOpenDocument(LPCTSTR lpszPathName);

Posted 24-Mar-11 8:48am

bolivar123

Comments

Ozer Karaagac 24-Mar-11 22:38pm

This one is the more appropriate answer within Document/View architecture.

Jackie Lloyd 25-Mar-11 4:36am

Hi - thankyou very much for your reply. I do not know how to get at the instance of CFileDialog as I cannot find what it's name is anywhere in my application.

Ozer Karaagac 25-Mar-11 8:39am

In doc/view, you normally don't need to handle CFileDialog yourself. Framework does this for you and send you selected file name by lpszPathName parameter of above function when you override CYourAppDoc::OnOpenDocument() member.

If you don't want to use Doc/View architecture and want to show CFileDilog yourself, you need to handle ID_FILE_OPEN event in one of your Doc, View, Frame or App derived classes.

Mithun_linux8898 · Answer 4 · 2013-03-21T18:03:00

Solution 4

Dear Jackie,
I have beel searching all through internet for the same application like treeview display by opening a file. As i am newbie to this technology im not sure how to proceed further so can u please share ur project with me it ll be more helpfull for my career. Can u please mail it to my email id mithunssss3@gmail.com.
Thanks in Advance

Posted 21-Mar-13 18:03pm

Mithun_linux8898

Comments

J.Surjith Kumar 22-Mar-13 10:17am

Why you posted this as the solution???

MFC SDI File Open Dialog

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