How to use a create a destination file name(With Path) using a source file name?

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Hello,
I am unable to do this in PERL although this i can do easily in C#.
The problem is like this:

I have a file name Eg: C:\foo\tempfolder\testfolder\data.txt
and now i use the data.txt file extract some data from it and then write it back to another file with file name data_extract.txt
My perl".pl" file is in another folder which means i cannot just give "data_extract.txt" as my destination file name as this will create in the folder of my pl file.
how can i get the file name as C:\foo\tempfolder\testfolder\data_extract.txt
I hope my explanation is clear.

Posted 2-Dec-10 4:30am

asjadazeez

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HimanshuJoshi · Answer 1 · 2010-12-02T04:47:00

You can pass path separately and source and destination file names separately. Like following

PERL

$Path = "C:\\foo\\tempfolder\\testfolder\\";
$SourceFile = $Path . "data.txt";
$DestinationFile = $Path . "data_extract.txt";

open ($SFILEHANDLE, '<', $SourceFile) or die $!;
open ($DFILEHANDLE, '>', $DestinationFile) or die $!;