How to extract string in from a default scalar.

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Hello,
I have this small code to do in perl and i am now very sure of how to do it. I have read a line from the csv file int0 $_and now i need to extract a part of the string from it.

Ex line in csv file would be
one;two;three;four;five;six

and i need to have a variable (a scalar) to have the value
fourfive

(without the semicolon between four and five)
i tried with pattern matching but didnt get the proper results
can any one help.

Posted 29-Nov-10 3:55am

asjadazeez

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Manfred Rudolf Bihy · Answer 1 · 2010-11-29T04:05:00

What you need is this:

$info = "one;two;three;four;five;six;"
@items = split(/;/, $info);
$extract = @items[3] + @items[4];

Now extract should contain the string "fourfive".
Arrays in perl are normally zero based, but I think there was something
to change that if you really needed it.
(Sorry I didn't do any Perl for quite some time now. :) )

Cheers

Manfred