How can I pass a struct of an array to a function without a pointer ?

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C

struct

I am trying to pass a struct of array to a function without a pointer.

I'm trying to pass an array[], so it will print the next value of the array.

The code below has an array of List[5] = {1,2,3,4}, where the first int in the array
will be processed in

struct Count numbers()

I included the increment i, so the printCode() will print integers of numbers.intOne[1] & numbers.intTwo[1], numbers.intOne[2] & numbers.intTwo[2] etc...

I want the program to run the array one by one, for example 1 will be added by 4 and added by 6, which will print 57. And the next value will be 2, which will result in 6 and 8. But it will only take the same value from the struct and keeps printing 575757.

How can I make the function continue to the next array value (and print 58), and is this possible without an array?

What I have tried:

#include <stdio.h>

struct Count {      //My struct
	int intOne;
	int intTwo;
};

struct Count numbers() {
	struct Count numbers;

	int List[5] = { 1, 2, 3, 4 };  //The array

	int i;
	for (i = 0; i < 10; i++) {           
		numbers.intOne = List[i] + 4;
		numbers.intTwo = List[i] + 6;
		return numbers;
	}
};

void printCode(struct Count numbers) {
	int i;
	for (i = 0; i < 2; i++) {
		printf("%i%i", numbers.intOne, numbers.intTwo); //This thing only prints 575757
	}
}

int main() {

	int i = 0;
	for (i = 0; i < 10; i++) {
		numbers();
		printCode(numbers());
		getchar();
	}

}